
Education Journalist | Study Abroad Lead
Potential energy is the stored form of energy within a body when force is applied to a body such as gravitational force or spring force in order to make it work and move from its original place. Potential energy can be expressed in multiple ways such as:
- When there is no electric field,
- When there is a single charge in an external electric field,
- When there are two charges in an external electric field and with presence of a dipole in an external electric field.
| Table of Content |
Key Takeaways: Potential energy, Dipole, External electric field, Electric field, Conservative force, Gravitational force, Spring force, Force
What is Potential Energy?
[Click Here for Sample Questions]
- Potential Energy is the energy possessed by a body due to its position or it is the energy which can be stored by the body.
- It arises from the configuration of the system on shifting the body from the reference point and is the ability of doing work by or against a conservative force.
- Potential energy can be positive or negative and is only defined for a conservative force.
- Potential energy depends upon the frame of reference but change in potential energy does not depend upon the frame of reference.

Potential Energy
Also Read:
| Related Articles | ||
|---|---|---|
| Difference Between Voltage and Current | Uses of Rectifier | Current Electricity |
| Electric Flux | Coulomb's Law | Electric Charge |
| Dielectric Constant | Application of Gauss Law | Gauss Law |
What is Electric Field?
[Click Here for Sample Questions]
- Electric field is the region of space surrounding the electrically charged objects/particles where a force is exerted by other electrically charged objects/particles.
- When a charged object/particle interacts with another charged object/particle, then that attractive or repulsive interaction is known as electric force.
- The force on a unit positive charge at a point in an electric field is equal to the electric field intensity at that point.

Electric Field
Potential Energy when there is no External Electric Field
[Click Here for Sample Questions]
Consider two positive charges q1 and q2, where q1 is lying near to a point ‘P’ and q2 is at infinity.
We assume that the potential energy at infinity is zero
We know that two like charges repel each other and when we try to bring q2 at point P, q1 and q2 will repel each other and therefore some work will be done against the repulsive force and this work will be stored as the potential energy in q2.
Work done will be given by,
W = Vq2
Also,
U =\(\frac{q_1q_2}{r_{12}} \frac{1}{4\pi \epsilon_o}\)
Now we are concerned with potential energy of a charge (s) in an external field.
The external electric field is not produced by the given charge whose potential energy we wish to calculate.
Potential Energy of a Single Charge in an External Electric Field
[Click Here for Sample Questions]
Work done in bringing a charge ‘q’ from infinity to a point in the external field is qV
W=qVr
Also the work done work is stored in the form of potential energy where work is given by-;
U= qVr
Potential energy of the System of Two Charges in External Electric Field
Consider two points, r1 and r2 in an external electric field and we want to bring charges q1 and q2 to the points r1 and r2 respectively.
Then, the work done to bring charge q1 at r1 will be given by,
U1= q1Vr1
The work done to bring charge q2 at r2 will be given by,
U2= q2Vr2
But as q1 and q2 are like charges so there will be some repulsion between q1 and q2, hence some work will be done to bring the charges at r1 and r2, which will be stored in the form of potential energy, given by
U12 = \(\frac{q_1q_2}{4\pi \epsilon_o}\)
Total potential energy will be given by -;
U = U1 + U2 + U
U = q1Vr1 + q2Vr2 + \(\frac{q_1q_2}{4\pi \epsilon_o}\)
Potential Energy of a Dipole in an External Electric Field
[Click Here for Sample Questions]
An electric dipole is a system formed by two equal and opposite charges placed at a short distance apart.
The product of one charge and the distance between the charges is known as the ‘electric dipole moment.’
It is denoted by ‘P’
P = q×2l
Now, let us consider a dipole with q1 and q2.
Consider charge q1 to be positive and charge q2 to be negative.
Let this dipole be placed in a uniform electric field ‘E’.
We know that when a charge is placed in an electric field, some force is applied.
As, q1 is a positive charge, force will be applied on the charge q1 in the direction of the electric field, given by,
F= q1E
As, q2 is a negative charge, force will be applied on the charge q2 in the direction opposite to that of the electric field, given by,
F = – q2E
Therefore, the net force applied will be equal to zero.
But, as the forces are being applied in the opposite directions and also there is some distance between q1 and q2, there will be some rotating effect in the dipole or we can say there will be torque in the dipole, given by-;
τ = P×E
τ = PE sinθ
When the electric dipole is placed parallel to the electric field then torque will be 0 because the angle between the electric field and the dipole will be 0o.
Suppose an external torque \(\tau_{ex}\)is applied in such a manner that it just neutralises this torque and rotates it in the plane of paper from θ1 to θ2, at an infinitesimal angular speed and without angular acceleration.
The amount of the work done by the external torque will be given by,
W = \(\int^{\theta_1}_{\theta_o} \tau_{ex}.d\theta\)
W = \(\int^{\theta_1}_{\theta_o} PEsin \theta.d\theta\)
W =\( PE\int^{\theta_1}_{\theta_o}sin \theta.d\theta\)
W = PE [-cosθ]θ?θ?
W = PE [cosθ?1- cosθ2]
This work is stored as the potential energy of the system.
Uθ = PE (cosθ1- cosθ2)
Let us assume that the initial angle is 90o.
Uθ = – PEcosθ
Therefore, the potential energy in the external field in an electric dipole at an angle θ, is given by –PEcosθ.
Things to Remember
- E is produced by sources external to the given charges.
- The external field E is not produced by the given charge(s) whose potential energy we wish to calculate.
- The V electrical potential is a scalar without any direction and E electric field is a vector.
- A body must possess some form of energy in order to contain potential energy.
- An object will have more gravitational potential when it is heavier and higher above the ground level.
Read More:
Sample Questions
Ques. A hollow metal sphere of radius 10cm is charged such that the potential on its surface is 5V. What is the centre of the sphere? (All India 2011)[2 Marks]
Ans. Potential at the surface is given as 5V, and we know that the electric field inside a hollow sphere is ‘zero’.
Hence, E = dV/dr = 0
And this can be 0, only and only if V is either constant or zero.
V cannot be zero, hence V will be a constant.
Vcentre =Vr (r<R) = VR
Vcentre = Vsurface = 5V
Ques. Determine the potential energy of a system containing two charges 7μC and -2μC separated by a distance of 18 cm. (2 marks)
Ans. q? = 7μC = 7×10-6 C q2 = -2×10-6 C
r= 18cm= 0.18m
Electrostatic potential energy of the two charges
U = \(\frac{q_1q_2}{4\pi \epsilon_o}\) = -0.75
Ques. The electrostatic potential energy between proton and electron separated by a distance 1A? is? (2 marks)
Ans. -e = -1.6×10-19 C
e= 1.6×10-19 C
Also, 1A? = 10-10m
U = \(\frac{Kq_1q_2}{r}\)= -14.4 eV
Ques. The electric potential at a point in free space due to a charge Q coulomb is Q×1011 volts. The electric field at that point is ? (2 marks)
Ans. V= Q×1011 volt = \(\frac{kQ}{R}\)
R= \(\frac{9 \times 10^9}{10^{11}}\) = 0.09m
E = \(\frac{kQ}{r^2}\) = \(\frac{9 \times 10^9 \times Q}{(9 \times 10^{-2})^2}\)
E = \(\frac{10^{13}}{9}\)Q v/m = 4πε?1022 V/m
Ques. What must be the magnitude of an isolated positive charge so as to produce an electric potential of 3105 V at a distance of 3m from it? (2 marks)
Ans. \(\frac{kQ}{r^2}\) = 3105
=\(\frac{9 \times 10^9 \times q}{3}\) = 3105
q= 10-4 C
Ques. A point charge q produces an electric field of magnitude 2.0 NC-1 at a point distant 50cm from it. Find the value of q. (2 marks)
Ans. E =\(\frac{kq}{r^2}\)
q = \(\frac{Er^2}{k}\)
q = \(\frac{2 \times 0.5 \times 0.5}{9 \times 10^9}\)
q = 0.5555 x 10-10 C
q = 5.56 x 10-11C
For Latest Updates on Upcoming Board Exams, Click Here: https://t.me/class_10_12_board_updates
Check-Out:







Comments