Spring Constant Formula: Hooke’s Law, Potential Energy, & Solved Examples

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Spring constant’s meaning is associated with simple harmonic motions and Hooke's law. As per Hooke’s law, the force needed to extend or compress a spring is directly proportional to the distance it is stretched.

Simple harmonic motion (SHM) is used in the oscillatory motion of objects. Springs have their own natural “spring constants” which specify how inflexible they are. Hooke's law defines SHM and provides a formula for the applied force using the spring constant. 

Also check: Work Energy and Power

Key Terms: Spring Constant, Hooke’s Law, Spring Constant Formula, Potential Energy of a Spring


What is Spring Constant (or Hooke’s Law)

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Hook’s law is specifying the connection between the distance stretched and the force applied in the spring. It states that the force needed to extend or compress a spring is directly proportionate to the distance it is stretched.

The spring constant defines how much force will be required to deform the spring. The standard international (SI) force constant unit of measurement is Newton/meter, but it is often measured in pounds/inch in North America. A higher spring constant indicates a stiffer spring and similarly, the reverse is also true. The spring constant can be discovered based on four parameters:

  • Wire Diameter: The diameter of the wire that contains the spring.
  • Coil Diameter: Each coil’s diameter estimates the tightness of the coil.
  • Free length: The spring’s length at rest.
  • A number of Active Coils: The number of coils that are free for expansion and contraction.

The letter K is the spring constant and has units as N/m. According to Newton's third law of motion, when a spring is stretched, it retracts with a restoring force. This restoring force follows Hooke's law, which relates the spring force to the spring constant.

Force of the spring (F) = - (spring constant (k)) * (displacement (x))

  • F = – k × x
  • Spring Constant Units = N.m-1

Where

  • F = the restoring force of the spring directed toward equilibrium.
  • k = the spring constant in N.m-1.
  • x = displacing the spring from its equilibrium point.

In other words, the spring constant is the applied force if the displacement in the spring is unity. If a force F is assumed to stretch the spring so that it displaces the equilibrium position by x.

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Relation of Spring Constant and its length

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Assume we have a 6 cm spring with spring constant k. Now, if the spring is split into two bits of equal size, a new spring constant for one of these smaller springs will be 2k. More commonly, the spring constant of a spring is inversely proportionate to the length of the spring, considering we are talking about a special material spring and thickness.

So, let's say we cut the spring in the above example precisely in half, creating two smaller springs of length 3 cm each. The spring constant, twice the original, will apply to smaller springs. The reason behind this is that it is inversely proportional to the spring constant and the length of the spring. This indicates that in a small spring, an original mass of 30 grams will produce only 1 mm of stretch. The bigger the spring constant, the smaller the extension that produces the mentioned force.


Spring Constant Dimensional Formula

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We know that,

F= – kx

Therefore,

\(k = –\frac{F}{x}\)

Dimension of F = [MLT-2]

Dimension of x = [L]

Therefore, the dimension of k =

\(k=-\frac{[MLT^{-2}]}{[L]}=-[MT^{-2}]\)

The Spring Constant Formula is given as,

\(k = –\frac{F}{x}\)

Where,

  • F = Force applied,
  • x = displacement by the spring
  • A negative sign indicates that the restoring force is opposite to the displacement.

It is described in Newton per meter (N/m).


Potential Energy of a Spring (P.E.)

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The energy stored in a stretchable or compressible object is known as the spring’s potential energy. It is also known as elastic potential energy and is equivalent to the force multiplied by the distance traveled.

It is referred as: Potential Energy = Force × Displacement

Also force of the spring is equal to the spring constant × displacement. So,

P.E. = \(\frac{1}{2}\) KX2 (2)

The above-mentioned equation is the formula for the potential energy of a spring.


Applications of Hooke’s Law

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  • Because of the elasticity of springs, Hooke's law is usually applied to springs.
  • It is used not only in the field of engineering but also in the field of medical science.
  • It is useful in diving boards, spring beds, lungs, skin, and automobile suspension systems.
  • It is the basic principle underlying spring scales, manometers, and clock balance wheels.
  • It is also the basis of acoustics, seismology, and molecular mechanics.

Limitations of Hooke’s Law

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The drawbacks of Hooke's law are as follows:

  • Hooke's law only applies in the elastic region then it fails.
  • Hooke's law gives correct results only for solid bodies with small forces and deformations.

Things to Remember

  • As per Hooke’s law, the force needed to extend or compress a spring is directly proportional to the distance it is stretched.
  • Force of the spring (F) = - (spring constant (k)) * (displacement (x))
    • F = – k × x
    • Spring Constant Units = N.m-1

Dimension of k =\(k=-\frac{[MLT^{-2}]}{[L]}=-[MT^{-2}]\)

  • The energy stored in a stretchable or compressible object is known as spring potential energy. P.E. = \(\frac{1}{2}\) KX2 ⇢ (2)
  • Hooke's law has the limitation that it applies only under the elastic limit of any material, which means that the material must be perfectly elastic to obey Hooke's law.
  • Because of the elasticity of springs, Hooke's law is usually applied to springs. It is used not only in the field of engineering but also in the field of medical science.
  • Hooke's law only applies in the elastic region then it fails and gives correct results only for solid bodies with small forces and deformations.

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Sample Questions

Ques. Define Spring Constant. (2 Marks)

Ans: The spring constant is the force exerted to stretch or compress the spring, divided by the amount of time the spring lengthens or shortens. When a spring is stretched, according to Hooke's law, the force exerted is proportional to the increase in length from the equilibrium length. It is used to determine the stability or instability of a spring, and thus the system for which it is intended.

As a formula, it modifies Hooke's law and is denoted by the equation \(k = –\frac{F}{x}\). Where k is the spring constant, F is the force applied at x, and x is the deflection through the spring expressed in N/m.

Ques. Can Spring Constant Be Negative, or Can it take a Value of Zero? (2 Marks)

Ans: As per Hooke’s law, F = – kx

Here, the negative sign suggests that the force applied by the spring will forever be on the opposite side of the force applied by the load. The reason behind it is that the spring will always try to recover its original length. The spring constant describes the stiffness of the spring; so, it should forever have a positive value.

If the spring constant is zero, it indicates that the spring stiffness will be zero. It will no longer be a spring because no force will act in the opposite direction. Now if the spring constant is a negative value, it will mean that instead of an equal and opposite force, the spring will exert a force in the direction of the displacement. This means that even if the spring is stretched by one unit, it will continue to stretch infinitely.

Ques. What are the uses of springs? (2 Marks)

Ans: Scooping a ballpoint pen (a notable one with a button you can click to retract the ball) and you'll find a spring inside. Take a look under your car and you'll see springs there too, which serve as shock absorbers to smooth out bumps in the road. You will see springs in clocks and watches, as we have seen before. And even a car speedometer has a spring (at least, one of the old-school mechanical ones). Once you start noticing spring, you will find springs everywhere.

Ques. How does length influence the spring constant? (2 Marks)

Ans: Assume there is a 6 cm spring with a spring constant of k. What will happen if the spring is split into two similar-sized pieces? One of these shorter springs will contain a new spring constant of 2k. Generally, the spring constant of a spring is inversely proportional to the length of the spring considering a specific material spring and thickness.

So, in the previous example, suppose the spring is cut exactly in half, resulting in two shorter springs, each 3 cm in length. A spring constant twice as big as the original will be used for the smaller springs. The reason behind it is that it is inversely proportional to both the spring length and the spring constant.

Ques. Explain the concept of Spring Force. (2 Marks)

Ans: For springs, there is a position at which they are neutral. When they are stretched or compressed, then there is a restoring force that will constantly point in the direction of the equilibrium position. A pendulum is neutral when hanging straight down. If the pendulum is pulled away from its equilibrium position, it swings back and forth as tension forces and gravity act on it. A spring is a tool that is traditionally used and its stiffness is routinely neglected due to negligible mass.

Ques. Discover the spring constant for spring if it needs a 9000 Newton force to pull the spring 30.0 cm from the position of equilibrium. (3 Marks)

Ans: We can rearrange the formula for the spring constant to solve for the spring constant, k, as follows:

F= – K × x

i.e., \(k = –\frac{F}{x}\)

In this example, a force of 9000 N is pulling on the spring. It indicates that the spring retracts with an equal and opposite force of -9000 N.

Furthermore, the displacement is 30.0 cm = 0.30 m. Therefore, by placing the values in the above formula, we will get,

K = \(\frac{- 9000}{0.30}\)

i.e., K= 30000 N/m

Thus, the spring constant of the spring = 30000 N/m.

Ques. A force of 3500 newtons is applied to a spring having a spring constant of k = 14000 N/m. Estimate how far the spring will be displaced from equilibrium. (5 Marks)

Ans: Rearranging the spring constant formula we can find the displacement:

F= – K × x

i.e., \(X = –\frac{F}{k}\)

In this example, a force of 3500 N is pulling on the spring. It indicates that the spring retracts with an equal and opposite force of -3500 N.

Thus,

x = \(\frac{- 3500}{14000}\)

x = 0.250 m

x = 25.0 cm

Hence, the spring is displaced by 25.0 cm.

Ques. A spring having a load of 5 Kg is stretched by 40 cm. Calculate its spring constant. (5 Marks)

Ans: As mentioned in the problem,

Mass of spring, m = 5 Kg

Displacement, x = 40 cm

We know that,

Force F = m × a

Putting the values in the formula,

F = 5 × 0.4

F = 2 Newton

Now, the spring constant is:

\(k = –\frac{F}{x}\)

i.e., K = \(\frac{– 2}{0.4}\)

K = – 5 N/m

Hence, the spring constant will be – 5 N/m.

Ques. A boy with a weight of 20 pounds stretches a spring by 50 cm. Compute the spring‘s spring constant. (3 Marks)

Ans: Given:

Mass (m) = 20 lbs = \(\frac{20}{2.2}\) = 9.09 Kilogram

Displacement x = 50 cm

The force F = ma 

= 9.09 × 9.8 = 89.082 N

The spring constant formula is given by:

\(k = –\frac{F}{x}\)

= \(\frac{-89.082}{0.5}\) = – 178.164 N/m.

Ques. A spring is stretched by 4 m with a force of 2N. Estimate its spring constant. (3 Marks)

Ans: Mentioned,

Force, F = 2 N, and

Displacement, X = 4 m.

The Spring constant, \(k = –\frac{F}{x}\)

K = \(\frac{- 2N}{4m}\)

K = – 0.5 Nm-1.

Ques. If the spring constant is 0.1 Nm-1, how much force is needed to stretch a 3-meter spring to 5 meters? (3 Marks)

Ans: Mentioned, 

Length of spring = 3m

Spring constant, K = 0.1 Nm-1

Stretch it to 5 meters so the displacement of the spring is X = 5 – 3 = 2m

Now, the required Force is F = – Kx

F = – (0.1 Nm-1 × 2m)

F = – 0.2 N.


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