What is meant by adjacent sides?

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In mathematics and geometry, adjacent sides refer to sides that share a common endpoint or vertex. Adjacent sides can be found in various two-dimensional shapes, such as squares, rectangles, triangles, and polygons.

For example, in a square, each of the four sides is adjacent to the two sides it touches. In a rectangle, two sides that are opposite each other are referred to as "opposite sides," while the other two sides are considered to be adjacent. Any two sides that share a common vertex are considered to be adjacent sides in a triangle.

Adjacent sides play an important role in many geometric calculations and measurements, such as finding the perimeter of a shape, calculating the area, and determining the interior and exterior angles of a shape. By understanding the relationships between adjacent sides, it is possible to make more precise calculations and predictions about various shapes and figures.

Adjacent Sides

Adjacent Sides

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CBSE CLASS XII Related Questions

1.
Find the domain of \[ q(x)=\cos^{-1}(4x^2-3). \] Hence, find the value of \(x\) for which \[ q(x)=0. \] Also, write the range of \[ 3q(x)-\pi. \]

View Solution

2.
Check whether the function \[ f(x)= \begin{cases} \dfrac{|x-3|}{2(x-3)}, & x<3,\\[6pt] \dfrac{x-6}{6}, & x\geq 3 \end{cases} \] is continuous at \(x=3\) or not.

View Solution

3.
If \[ \frac{d}{dx}(F(x))=\frac{1}{e^x+1}, \] then find \(F(x)\), given that \[ F(0)=\log\left(\frac{1}{2}\right). \]

View Solution

4.
For \[ f(x)=x+\frac{1}{x}, \quad x\neq 0. \]

local maximum value is 2
local minimum value is \( -2 \)
local maximum value is \( -2 \)
local minimum value \( < \) local maximum value

View Solution

5.
The least value of \[ f(x)=e^{-x} \] in the interval \[ [0,3] \] is:

\( e^{-3} \)
\( -1 \)
\( 1 \)
\( -e^3 \)

View Solution

6.
The domain of \[ f(x)=\cos^{-1}(2x-5) \] is:

\([-1, 1]\)
\([4, 6]\)
\([-7, -3]\)
\([2, 3]\)

View Solution

What is meant by adjacent sides?

CBSE CLASS XII Related Questions

1.
Find the domain of \[ q(x)=\cos^{-1}(4x^2-3). \] Hence, find the value of \(x\) for which \[ q(x)=0. \] Also, write the range of \[ 3q(x)-\pi. \]

2.
Check whether the function \[ f(x)= \begin{cases} \dfrac{|x-3|}{2(x-3)}, & x<3,\\[6pt] \dfrac{x-6}{6}, & x\geq 3 \end{cases} \] is continuous at \(x=3\) or not.

3.
If \[ \frac{d}{dx}(F(x))=\frac{1}{e^x+1}, \] then find \(F(x)\), given that \[ F(0)=\log\left(\frac{1}{2}\right). \]

4.
For \[ f(x)=x+\frac{1}{x}, \quad x\neq 0. \]

5.
The least value of \[ f(x)=e^{-x} \] in the interval \[ [0,3] \] is:

6.
The domain of \[ f(x)=\cos^{-1}(2x-5) \] is:

Comments

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What is meant by adjacent sides?

CBSE CLASS XII Related Questions

1.Find the domain of \[ q(x)=\cos^{-1}(4x^2-3). \] Hence, find the value of \(x\) for which \[ q(x)=0. \] Also, write the range of \[ 3q(x)-\pi. \]

2.Check whether the function \[ f(x)= \begin{cases} \dfrac{|x-3|}{2(x-3)}, & x<3,\\[6pt] \dfrac{x-6}{6}, & x\geq 3 \end{cases} \] is continuous at \(x=3\) or not.

3. If \[ \frac{d}{dx}(F(x))=\frac{1}{e^x+1}, \] then find \(F(x)\), given that \[ F(0)=\log\left(\frac{1}{2}\right). \]

4. For \[ f(x)=x+\frac{1}{x}, \quad x\neq 0. \]

5. The least value of \[ f(x)=e^{-x} \] in the interval \[ [0,3] \] is:

6.The domain of \[ f(x)=\cos^{-1}(2x-5) \] is:

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
Find the domain of \[ q(x)=\cos^{-1}(4x^2-3). \] Hence, find the value of \(x\) for which \[ q(x)=0. \] Also, write the range of \[ 3q(x)-\pi. \]

2.
Check whether the function \[ f(x)= \begin{cases} \dfrac{|x-3|}{2(x-3)}, & x<3,\\[6pt] \dfrac{x-6}{6}, & x\geq 3 \end{cases} \] is continuous at \(x=3\) or not.

3.
If \[ \frac{d}{dx}(F(x))=\frac{1}{e^x+1}, \] then find \(F(x)\), given that \[ F(0)=\log\left(\frac{1}{2}\right). \]

4.
For \[ f(x)=x+\frac{1}{x}, \quad x\neq 0. \]

5.
The least value of \[ f(x)=e^{-x} \] in the interval \[ [0,3] \] is:

6.
The domain of \[ f(x)=\cos^{-1}(2x-5) \] is: