How do you find the resistance in Ohm's law?

According to Ohm’s law, the voltage across a conductor is directly proportional to the current that flows through it, provided the temperature and physical conditions remain constant.

Mathematically, Ohm’s law can be denoted as:

V = IR
In order to find the resistance, the formula can be rewritten as:

\(R = {V \over I}\)

Related Questions:

  1. What is the necessary condition for a conductor to obey Ohm's Law?
  2. Is resistance constant in Ohm's law?
  3. Why is the curve representing Ohm's law linear?

Read More:

CBSE CLASS XII Related Questions

  • 1.
    If both the number of protons and the neutrons are conserved in each nuclear reaction, in what way is mass converted into energy (or vice versa) in a nuclear reaction? Explain.


      • 2.
        Two heaters rated as \((P_1,V)\) and \((P_2,V)\) are connected in series across a dc source of \(V/2\) volt. The power consumed by the combination will be –

          • \((P_1+P_2)\)
          • \(\dfrac{P_1+P_2}{2}\)
          • \(\dfrac{P_1P_2}{2(P_1+P_2)}\)
          • \(\dfrac{P_1P_2}{4(P_1+P_2)}\)

        • 3.
          A light copper ring is freely suspended by a light string. A bar magnet is held horizontally with its length along the axis of the ring. The magnet is moved towards the ring with its N pole facing the loop. What will happen to the ring and its position? Explain.


            • 4.
              If Bohr’s quantization postulate (angular momentum \( = \frac{nh}{2\pi} \)) is a basic law of nature, it should be equally valid for the case of planetary motion also. Why, then, do we never speak of quantization of orbits of planets around the Sun? Explain.


                • 5.
                  A square loop of side 0.50 m is placed in a uniform magnetic field of 0.4 T perpendicular to the plane of the loop. The loop is rotated through an angle of 60° in 0.2 s. The value of emf induced in the loop will be:

                    • 5 V
                    • 3.5 V
                    • 2.5 V
                    • Zero V

                  • 6.
                    Photoemission of electrons occurs from a metal (\( \phi_0 = 1.96 \, \text{eV} \)) when light of frequency \( 6.4 \times 10^{14} \, \text{Hz} \) is incident on it. Calculate: Energy of a photon in the incident light, The maximum kinetic energy of the emitted electrons, and The stopping potential.

                      CBSE CLASS XII Previous Year Papers

                      Comments


                      No Comments To Show