Why is the curve representing Ohm's law linear?

The curve that represents Ohm’s law is linear as the law denotes a linear relationship between the applied voltage and the current produced. The electric current is proportional to the voltage, hence the I–V curve is a straight line through the origin with a positive slope.

Ohm's law V-I graph

Related Questions:

  1. What is the necessary condition for a conductor to obey Ohm's Law?
  2. How do you find the resistance to Ohm's law?
  3. Is resistance constant in Ohm's law?

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CBSE CLASS XII Related Questions

  • 1.

    A parallel beam of monochromatic light falls normally on a single slit of width $a$ and a diffraction pattern is observed on a screen placed at distance $D$ from the slit. Explain:

    (I) the formation of maxima and minima in the diffraction pattern, and

    (II) why the maxima go on becoming weaker and weaker with its increasing number $n$.


      • 2.
        In a region, the electric potential varies as \(V = 10 - 50x\), where \(V\) is in volts and \(x\) is in meters. The electric field in the region is

          • \(10\ \text{N/C}\) along \(+x\)
          • \(10\ \text{N/C}\) along \(-x\)
          • \(50\ \text{N/C}\) along \(+x\)
          • \(50\ \text{N/C}\) along \(-x\)

        • 3.
          Two point charges -Q and Q are located at points (d, 0) and (0, d) respectively, in x-y plane. The electric field E at the origin will be:

            • \(\frac{1}{4\pi\epsilon_0} \frac{\sqrt{2}Q}{d^2} (\hat{i} - \hat{j})\)
            • \(\frac{1}{4\pi\epsilon_0} \frac{\sqrt{2}Q}{d^2} (-\hat{i} - \hat{j})\)
            • \(\frac{1}{4\pi\epsilon_0} \frac{Q}{d^2} (\hat{i} - \hat{j})\)
            • \(\frac{1}{4\pi\epsilon_0} \frac{Q}{d^2} (-\hat{i} - \hat{j})\)

          • 4.
            The resistance of a metal wire at \(20^\circ\text{C}\) is \(1.05\,\Omega\) and at \(100^\circ\text{C}\) is \(1.38\,\Omega\). Determine the temperature coefficient of resistivity of this metal.


              • 5.

                A square loop of side 0.50 m is placed in a uniform magnetic field of 0.4 T perpendicular to the plane of the loop. The loop is rotated through an angle of $60^\circ$ in 0.2 s. The value of emf induced in the loop will be:

                  • 5 V
                  • 3.5 V
                  • 2.5 V
                  • Zero V

                • 6.

                  (I) The real image of an object placed between $f$ and $2f$ from a convex lens can be seen on a screen placed at the image location. If the screen is removed, is the image still there? Explain.

                  (II) Plane and convex mirrors produce virtual images of objects. Can they produce real images under some circumstances? Explain.

                    CBSE CLASS XII Previous Year Papers

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