NCERT Solutions for Class 12 Chapter 13 Probability Exercise 13.2

Collegedunia Team logo

Collegedunia Team

Content Curator

Class 12 Maths NCERT Solutions Chapter 13 Probability Exercise 13.2 is based on following concepts: Multiplication Theorem on Probability and Independent Events. 

Independent events are two events wherein the probability of occurrence of one of them is not affected by the occurrence of the other are called independent events.

Download PDF NCERT Solutions for Class 12 Maths Chapter 13 Probability Exercise 13.2

Check out the solutions of Class 12 Maths NCERT solutions Chapter 13 Probability Exercise 13.2

Read More: NCERT Solutions For Class 12 Mathematics Chapter 13 Probability

Also check other Exercise Solutions of Class 12 Maths Chapter 13 Probability

Also Read:

Also Read:

CBSE CLASS XII Related Questions

  • 1.

    The motion of a particle is described as \( S = 2t^{3} - 6t^{2} + 8 \). Its velocity \( \frac{dS}{dt} \), when the acceleration \( \frac{d^{2}S}{dt^{2}} \) vanishes is :

      • \( -6 \) unit/sec
      • \( 0 \) unit/sec
      • \( 18 \) unit/sec
      • \( 6 \) unit/sec

    • 2.

      For the given Linear Programming Problem, shade the feasible region on the graph and write the coordinates of the corner points.

      Minimize \(Z = 5x + 7y\)

      subject to constraints

      \[ 2x + y \geq 8 \]

      \[ x + 2y \geq 10 \]

      \[ x,\ y \geq 0. \]


        • 3.

          Solve the differential equation \( y + \frac{d}{dx}(xy) = x(\sin x + \log x) \).


            • 4.

              Find the sum of maximum and minimum values of \(f(x) = \sin x\,(1 + \cos x)\) in the interval \([0, \pi]\).


                • 5.

                  For the following Linear Programming Problem, shade the feasible region on the graph and find the coordinates of its corner points :

                  Minimize \(Z = 18x + 10y\)

                  subject to constraints

                  \[ \begin{aligned} 4x + y &\ge 20 \\ 2x + 3y &\ge 30 \\ x, y &\ge 0. \end{aligned} \]


                    • 6.

                      For events A and B, if \(P(B)=\frac{3}{5}\), \(P(A/B)=\frac{1}{2}\) and \(P(A\cup B)=\frac{4}{5}\), then \(P(A)\) is :

                        • \(\frac{1}{2}\)
                        • \(\frac{3}{5}\)
                        • \(\frac{1}{5}\)
                        • \(\frac{3}{10}\)
                      CBSE CLASS XII Previous Year Papers

                      Comments


                      No Comments To Show