NCERT Solutions for Class 12 Chapter 13 Probability Exercise 13.3

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Class 12 Maths NCERT Solutions Chapter 13 Probability Exercise 13.3 is based on Bayes’ Theorem also covering questions based on Bayes Theorem Formula.

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CBSE CLASS XII Related Questions

  • 1.
    A function \[ f:\mathbb{R}-\left\{\frac{3}{5}\right\} \to \mathbb{R}-\left\{\frac{3}{5}\right\} \] is defined as \[ f(x)=\frac{3x+2}{5x-3}. \] Show that \(f\) is one-one and onto.


      • 2.
        In a school, the probability of holding a debate competition is \( \frac{1}{3} \) and that of a quiz competition is \( \frac{2}{3} \). In the two participating teams, A has 4 girls and 6 boys and B has 7 girls and 3 boys. If a debate competition is held, the students are selected from team A and for the quiz competition they are selected from team B. If only two students are to be chosen from the teams, then find the probability that one will be a girl and the other a boy.


          • 3.
            Find: \[ \int \frac{x^2}{(x^2+9)(x^2+16)}\,dx \]


              • 4.

                Check whether \[ f:\mathbb{R}-\{3\}\rightarrow\mathbb{R} \] defined as \[ f(x)=\frac{x-2}{x-3} \] is onto or not. 


                  • 5.
                    For \[ f(x)=x+\frac{1}{x}, \quad x\neq 0. \]

                      • local maximum value is 2
                      • local minimum value is \( -2 \)
                      • local maximum value is \( -2 \)
                      • local minimum value \( < \) local maximum value

                    • 6.

                      Check whether the function \[ f(x)= \begin{cases} \dfrac{|x-3|}{2(x-3)}, & x<3,\\[6pt] \dfrac{x-6}{6}, & x\geq 3 \end{cases} \] is continuous at \(x=3\) or not. 

                        CBSE CLASS XII Previous Year Papers

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