NCERT Solutions For Class 12 Physics Chapter 5: Magnetism and Matter

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NCERT Solutions for class 12 physics chapter 5 Magnetism and Matter are given in this article with a detailed explanation. Magnetism is a force by virtue of which a metal is attracted to certain materials, which are known as magnets. These days magnets have a lot of applications in areas such as an electric bell, telephone, radio, loudspeaker, motors, fans, screwdrivers, etc.

The chapter has a weightage of 5 to 6 marks in the CBSE Class 12 Physics Examination. The NCERT Solutions for Class 12 Physics Chapter 5 covers concepts of the dipole moment of a magnet, permanent magnets, classification of magnetic materials, etc.

Download PDF: NCERT Solutions for Class 12 Physics Chapter 5

NCERT Solutions for Class 12 Physics Chapter 5

NCERT solutions for class 12 physics chapter 5: Magnetism and Matter are given below.

Class 12 Physics Chapter 5 Magnetism and Matter – Important Concepts

Magnetic field lines are the imaginary lines along which the North Magnetic move.

The larger the number of magnetic field lines per unit area, the stronger the magnetic field will be.

When a magnet placed in a uniform magnetic field B experiences a dipole moment m, then it experiences a force, torque, and potential energy.

Force = zero
Torque = m*B
Potential energy = m*B.

Magnetic Materials are classified as Diamagnetic, paramagnetic, and ferromagnetic. χ refers to the magnetic sensitivity of the material.

Diamagnetic materials – negative and small χ
Paramagnetic materials – positive and small χ
Ferromagnetic materials – large χ.

The magnetic field of a solenoid with a radius, carrying I current at distance r on the axis is given by:

$B = {\mu_0 \over 4\pi} {2m \over r^3}$

In the above formula, m refers to the magnetic moment of the solenoid that is given by –

$m = n(2l)(\pi a^2)$

Also Read:

Chapter 5 Related Articles
Lorentz Force	Unit of Magnetic Field	The Bar Magnet
Electric Bell	Electromagnetic Induction	Earth's Magnetism
Magnetic Poles	Ferromagnetism	Magnetism and Gauss Law
Magnetization and Magnetic Intensity	Permanent Magnets and Electromagnets	Magnetic Properties of Materials

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CBSE CLASS XII Related Questions

1.
Draw the plot of potential energy of a pair of nucleons as a function of their separation. Write two important conclusions that can be drawn from this plot.
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2.
The resistance of a metal wire at $20^\circ\text{C}$ is $1.05\,\Omega$ and at $100^\circ\text{C}$ is $1.38\,\Omega$. Determine the temperature coefficient of resistivity of this metal.
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3.
A parallel beam of monochromatic light falls normally on a single slit of width $a$ and a diffraction pattern is observed on a screen placed at distance $D$ from the slit. Explain:
(I) the formation of maxima and minima in the diffraction pattern, and
(II) why the maxima go on becoming weaker and weaker with its increasing number $n$.
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4.
(I) The real image of an object placed between $f$ and $2f$ from a convex lens can be seen on a screen placed at the image location. If the screen is removed, is the image still there? Explain.
(II) Plane and convex mirrors produce virtual images of objects. Can they produce real images under some circumstances? Explain.
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5.
Two point charges -Q and Q are located at points (d, 0) and (0, d) respectively, in x-y plane. The electric field E at the origin will be:
- $\frac{1}{4\pi\epsilon_0} \frac{\sqrt{2}Q}{d^2} (\hat{i} - \hat{j})$
- $\frac{1}{4\pi\epsilon_0} \frac{\sqrt{2}Q}{d^2} (-\hat{i} - \hat{j})$
- $\frac{1}{4\pi\epsilon_0} \frac{Q}{d^2} (\hat{i} - \hat{j})$
- $\frac{1}{4\pi\epsilon_0} \frac{Q}{d^2} (-\hat{i} - \hat{j})$
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6.
The resistance of a metal wire at $20^\circ\text{C}$ is $1.05\,\Omega$ and at $100^\circ\text{C}$ is $1.38\,\Omega$. Determine the temperature coefficient of resistivity of this metal.
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