Reimer Tiemann Reaction: Explanation and Reactions

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Namrata Das

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Reimer-Tiemann reaction, which was named after two chemists Karl Reimer and Ferdinand Tiemann, is a chemical reaction used for the ortho-formylation of phenols (C6H5OH). One of the simplest examples being the conversion of phenol to salicylaldehyde. It is a type of substitution reaction. Here we will discuss the concept in detail along with some important questions.According to the Reimer-Tiemann reaction, when phenol is refluxed with chloroform and sodium hydroxide at 340 K followed by hydrolysis, produces o-hydroxy benzaldehyde as main product and p-hydroxy benzaldehyde as minor product.

Key Terms: Reimer and Tiemann's reaction, biphasic solvent, dichlorocarbene,biphasic system, chemical reaction, chloroform, sodium hydroxide,benzaldehyde  


Detailed Explanation of Reimer and Tiemann

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As the hydroxides that are present in chloroform are not readily soluble, there requires a biphasic solvent to carry out the entire reaction. This biphasic system mostly consists of an aqueous hydroxide solution with an organic phase that has the chloroform in it. The two reagents that were separated, are brought together so that the reaction can take place. Several techniques are used to bring these reagents together. A few of them are- rapid mixing, phase transfer catalysts, or the use of the emulsifying agent.

Reimer and Tiemann reaction

Reimer and Tiemann reaction

The same reaction becomes even more effective when hydroxy-aromatic compounds like naphthol are used. Other organic heterocyclic compounds that are very rich in electrons like pyrroles and indoles can also experience Reimer and Tiemann reactions with ease.

To start the process the reaction needs heat and once the reaction starts, it can come out as a highly exothermic reaction. This in turn further increases the reaction rate. This is the reason why Reimer and Tiemann's reactions are always preferred in thermal runaways.

Note: By the virtue of two electrons withdrawing from their own to the chlorine group carbine (3) is highly deficient and it gets attracted to electron-rich phenoxide (5).

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Reimer and Tiemann Mechanism

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The mechanism in Reimer and Tiemann's reaction begins with the deprotonation of chloroform with the help of a strong base to form chloroform carbanion. This chloroform carbanion undergoes rapid alpha elimination giving rise to dichlorocarbene which is the principal reactive species in this reaction.

Reimer and Tiemann reaction is also known as an organic chemical reaction where phenol is converted into an ortho benzaldehyde using chloroform as a base and an acidic mixture or workup.

This chemical reaction can also be defined as the ortho-formylation of phenols.

  • The chloroform is deprotonated by the strongly basic aqueous hydroxide solution and produces the chloroform carbanion.
  • This chloroform carbanion easily goes through alpha elimination, and gives dichlorocarbene as the product. As already mentioned, dichlorocarbene is the primary reactive species.
  • Then the aqueous hydroxide deprotonates the phenol reactant as well, and gives a negatively charged phenoxide.
  • This negative charge is now delocalized into the benzene ring that causes it to be far more nucleophilic.
  • As a result, this causes a nucleophilic attack on the dichlorocarbene, forming an intermediate dichloromethyl substituted phenol.
  • This intermediate is exposed to basic hydrolysis in order to achieve the formation of the desired ortho-hydroxybenzaldehyde.

ortho-hydroxybenzaldehyde

ortho-hydroxybenzaldehyde


Reimer and Tiemann Condition

Mostly all hydroxides are not soluble in chloroform. A biphasic solvent is required to carry out this reaction. A biphasic system consists of an aqueous hydroxide solution with an organic phase that contains chloroform.

The two reagents are first separated and again reacted together to make sure the Reimer and Tiemann reaction takes place. This entire process can be achieved by rapid mixing phase transfer crystals or an emulsifying agent, the best example for this is the use of 1,4-dioxane as a solvent.

1,4-dioxane as a solvent

4-dioxane

This kind of reaction just needs to be initiated first by heating, once we start this reaction it turns out to be highly exothermic. This combination makes it prone to thermal runways.


Things to Remember

  • The topic “Reimer-Tiemann Reaction'' is covered in Chapter 11 Alcohols, Phenols, and Ethers of NCERT Class 12 Chemistry.
  • The chapter will carry around 3-4 marks in the board examination.
  • Reimer-Tiemann reaction is an organic chemical reaction used for the ortho-formylation of the phenols.
  • It is a substitution reaction.
  • One common example of this reaction is the conversion of phenol to salicylaldehyde

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Sample Questions

Ques: Sodium ethoxide has reacted with ethanoyl chloride. The compound that is produced in the above reaction is: (1 mark)
(1) Diethyl ether
(2) 2-butanone
(3) Ethyl chloride
(4) Ethyl ethanoate

Ans: 4) Ethyl Ethanoate

Ques: Reimer and Tiemann's reaction involves a
(1) Carbonium ion intermediate
(2) Carbene intermediate
(3) Carbanion intermediate
(4) Free radical intermediate (1 mark)

Ans: Reimer and Tiemann reactions involve carbene as intermediate as it is shown in the mechanism.

Ques: What is the Reimer and Tiemann formylation reaction? (1 mark)

Ans: Reimer and Tiemann reaction is a chemical reaction used for the ortho formylation of phenols; with the simplest example being the conversion of phenol to salicylaldehyde.

Ques: Reimer and Tiemann reaction
(1) Follow electrophilic addition reaction
(2) Involves the addition of CH2
(3) Follows electrophilic substitution and gives a product that is stabilized due to H-bonding.
(4) Involves acidic medium to form electrophile. (1 mark)

Ans: Follow electrophilic addition reaction.

Ques: In Reimer and Tiemann reaction, reactants are: (1 mark)
(1) Phenol, CHCl3, and alkali
(2) Phenol, CCl4, and alkali
(3) Aniline, CHCl3 and alkali
(4) Both phenol, CHCl3 and alkali, and phenol, CCl4, and alkali.

Ans: (4) Both phenol, CHCl3 and alkali and phenol, CCl4 and alkali.

In Reimer and Tiemann reactions, reactants are both phenol, CHCl3 and alkali, and phenol, CCl4, and alkali. When phenol, CHCl3, and alkali are used, the product is salicylaldehyde. When phenol, CCl4, and alkali are used, the product is salicylic acid. Hence, option D is correct.

Ques: Write the equation that are involved in the following reactions: (2 marks)
(1) Reimer Tiemann reaction
(2) Kolbe’s reaction

Ans:

  1. Reimer-Tiemann reaction

  1. Kolbe’s reaction

Ques: Give two reactions that show the acidic aspect of phenol. Compare the acidity of phenol with that of control. (3 marks)

Ans: Reaction with active metals: Phenol reacts with active metals such as Na, K and so on and H2 is evolved. 

Reactions with alkalies: Phenol neutralises the caustic alkalies like NaOH and KOH in order to form salt and water.

Phenol shows a considerable acidic nature as compared to ethanol because of the structural difference in C6H5 and C2H5 parts of the two molecules.


Previous Year Questions

Ques: Explain the following reactions with an example for each:
(1) Reimer-Tiemann reaction
(2) Friedel crafts reaction (Delhi 2010/Comptt. Delhi 2012/ All India 2014)

Ans: 1. Reimer-Tiemann reaction: In this reaction, the treatment of phenol with CHCl3 in the presence of aqueous NaOH at 340 K followed by hydrolysis, giving salicylaldehyde.

Reimer-Tiemann reaction

2. Friedel crafts reaction is used for introducing an alkyl or an acyl group into an aromatic compound in the presence of Lewis acid catalyst.

Example:

 Friedel crafts reaction

Ques: Write the mechanism of the following reaction:
Write the mechanism of the following reaction?
Write the equation involved in the Reimer-Tiemann reaction. (Delhi 2014)

Ans:

Write the equation involved in the Reimer-Tiemann reaction

Write the equation involved in the Reimer-Tiemann reaction

  1. Due to the formation of intramolecular H-bonding, ortho-nitrophenol has lower boiling point, while p-nitrophenol forms intermolecular H-bonding.           

Ques:
Write the Reimer-Tiemann reaction. 
Write the mechanism of acid dehydration of ethanol to yield ethene. (Comptt. All India 2017)

Ans:

  1. According to the Reimer-Tiemann reaction, when phenol is refluxed with chloroform and sodium hydroxide at 340 K followed by hydrolysis, produces o-hydroxy benzaldehyde as main product and p-hydroxy benzaldehyde as minor product.
  1. The mechanism of acid dehydration of ethanol into ethene:
  2. The mechanism of acid dehydration of ethanol into ethene:

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