State the Working Principle of a Potentiometer.

The working principle of a potentiometer is that the fall of potential energy across any portion of the wire is directly proportional to the length of that specific portion provided that the wire is of the uniform area of cross-section and the constant current flowing through it.


Related Questions

  1. What is balance point in potentiometer?
  2. How does a potentiometer measure EMF?
  3. Sensitivity of potentiometer can be increased by___________
  4. Which Metal Is Used In Potentiometer?
  5. Why High Resistance Is Used In Potentiometer?
  6. What is a DC Potentiometer?

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CBSE CLASS XII Related Questions

  • 1.
    Two heaters rated as \((P_1,V)\) and \((P_2,V)\) are connected in series across a dc source of \(V/2\) volt. The power consumed by the combination will be –

      • \((P_1+P_2)\)
      • \(\dfrac{P_1+P_2}{2}\)
      • \(\dfrac{P_1P_2}{2(P_1+P_2)}\)
      • \(\dfrac{P_1P_2}{4(P_1+P_2)}\)

    • 2.
      Four independent waves are expressed as \[ (i)\; y_1=A_1\sin\omega t, \] \[ (ii)\; y_2=A_2\sin 2\omega t, \] \[ (iii)\; y_3=A_3\cos\omega t, \] \[ (iv)\; y_4=A_4\sin\left(\omega t+\frac{\pi}{3}\right) \] The interference between two of these waves is possible in

        • (i) and (iii) only
        • (iii) and (iv) only
        • (i), (iii) and (iv) only
        • All of them

      • 3.
        The figure shows three point charges kept at the vertices of triangle ABC. The net electric field, due to this system of charges, at the midpoint M of base BC will be:

          • \( \frac{q}{4 \pi \epsilon_0 l^2} \) pointing along MA
          • \( \frac{q}{\pi \epsilon_0 l^2} \) pointing along AM
          • \( \frac{q}{2 \pi \epsilon_0 l^2} \) pointing along AM
          • Zero

        • 4.
          Assertion (A) : The mass of a nucleus is less than the sum of the masses of the constituent nucleons. Reason (R) : Energy is absorbed when the nucleons are bound together to form a nucleus.

            • Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
            • Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
            • Assertion (A) is true, but Reason (R) is false.
            • Both Assertion (A) and Reason (R) are false.

          • 5.
            A square loop of side 0.50 m is placed in a uniform magnetic field of 0.4 T perpendicular to the plane of the loop. The loop is rotated through an angle of 60° in 0.2 s. The value of emf induced in the loop will be:

              • 5 V
              • 3.5 V
              • 2.5 V
              • Zero V

            • 6.
              Two small identical metallic balls having charges \( q \) and \( -2q \) are kept far at a separation \( r \). They are brought in contact and then separated at distance \( \frac{r}{2} \). Compared to the initial force \( F \), they will now:

                • attract with a force \( \frac{F}{2} \)
                • repel with a force \( \frac{F}{2} \)
                • repel with a force \( F \)
                • attract with a force \( F \)
              CBSE CLASS XII Previous Year Papers

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