What are the limitations of Ohm's Law?

Ohm's law states that electric current is directly proportional to the voltage and is inversely proportional to resistance. The current-voltage relationship can be denoted as V = IR where V is voltage, I is current, and R is resistance.

Limitations of Ohm's Law

The limitations of ohm’s law are –

Ohm's law doesn’t apply to unilateral electrical components like diodes as well as transistors even though they only permit current to flow just in one way.
The level of voltage will not be constant with respect to time for nonlinear electrical components having properties such as resistance, capacitance, etc which makes Ohm’s law difficult to apply.

For example:

Semiconductors such as Germanium and Silicon don’t obey Ohm’s law and are therefore called Non-Ohmic conductors.
A water volt-ammeter is a unilateral network, therefore Ohm’s law is not applicable to such networks.

Related Questions:

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Ohm’s Law – Important Topics
Current Electricity	Cells in Series and in Parallel	Current Density
Wheatstone Bridge	Relation between kva and kw	Combination of Resistors
Potentiometer	Cells, emf, Internal Resistance	Unit of Specific Resistance
Static Electricity	Difference between AC and DC	Resistor Colour Codes
Ampere	Difference between kva and kw	Permittivity And Permeability
Electric Dipole	Resistivity Temperature Dependence	Unit of Current
Meter Bridge	Difference between RTD and thermocouple	Electromotive Force
Kirchhoff’s Rules	Difference between air conditioning and refrigeration	Internal resistance formula
Types of Current	Relation between resistance and length	Types of Resistors
Derivation of Drift Velocity	Difference Between Primary Cell and Secondary Cell	Electrical Formula
Drift Velocity	Differences Between Acceleration and Velocity	Power Of Alternating Current
Resistivity formula	Relation between power and resistance	Current density formula
Carbon Resistor	Difference between earth and neutral	Resistance Formula
Uses of Resistor	Difference between emf and voltage	Circuit Diagram
Power transformers	Current Electricity NCERT Solutions	Voltage divider formula

CBSE CLASS XII Related Questions

1.
A square loop of side 0.50 m is placed in a uniform magnetic field of 0.4 T perpendicular to the plane of the loop. The loop is rotated through an angle of 60° in 0.2 s. The value of emf induced in the loop will be:

5 V
3.5 V
2.5 V
Zero V

View Solution

2.
Two heaters rated as \((P_1,V)\) and \((P_2,V)\) are connected in series across a dc source of \(V/2\) volt. The power consumed by the combination will be –

\((P_1+P_2)\)
\(\dfrac{P_1+P_2}{2}\)
\(\dfrac{P_1P_2}{2(P_1+P_2)}\)
\(\dfrac{P_1P_2}{4(P_1+P_2)}\)

View Solution

3.
A light copper ring is freely suspended by a light string. A bar magnet is held horizontally with its length along the axis of the ring. The magnet is moved towards the ring with its N pole facing the loop. What will happen to the ring and its position? Explain.

View Solution

4.
Two small identical metallic balls having charges \( q \) and \( -2q \) are kept far at a separation \( r \). They are brought in contact and then separated at distance \( \frac{r}{2} \). Compared to the initial force \( F \), they will now:

attract with a force \( \frac{F}{2} \)
repel with a force \( \frac{F}{2} \)
repel with a force \( F \)
attract with a force \( F \)

View Solution

5.
Two parallel plate capacitors X and Y are connected in series to a 6 V battery. They have the same plate area and same plate separation but capacitor X has air between its plates, whereas capacitor Y contains a material of dielectric constant 4. Calculate the capacitances of X and Y, if the equivalent capacitance of the combination of X and Y is \( 4 \, \mu\text{F} \). Calculate the potential difference across the plates of X and Y.

View Solution

6.
Draw the number of scattered particles versus the scattering angle graph for scattering of alpha particles by a thin foil. Write two important conclusions that can be drawn from this plot.

View Solution

What are the limitations of Ohm's Law?

Limitations of Ohm's Law

CBSE CLASS XII Related Questions

1.
A square loop of side 0.50 m is placed in a uniform magnetic field of 0.4 T perpendicular to the plane of the loop. The loop is rotated through an angle of 60° in 0.2 s. The value of emf induced in the loop will be:

2.
Two heaters rated as \((P_1,V)\) and \((P_2,V)\) are connected in series across a dc source of \(V/2\) volt. The power consumed by the combination will be –

3.
A light copper ring is freely suspended by a light string. A bar magnet is held horizontally with its length along the axis of the ring. The magnet is moved towards the ring with its N pole facing the loop. What will happen to the ring and its position? Explain.

4.
Two small identical metallic balls having charges \( q \) and \( -2q \) are kept far at a separation \( r \). They are brought in contact and then separated at distance \( \frac{r}{2} \). Compared to the initial force \( F \), they will now:

6.
Draw the number of scattered particles versus the scattering angle graph for scattering of alpha particles by a thin foil. Write two important conclusions that can be drawn from this plot.

Similar Physics Concepts

Comments

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What are the limitations of Ohm's Law?

Limitations of Ohm's Law

CBSE CLASS XII Related Questions

1.A square loop of side 0.50 m is placed in a uniform magnetic field of 0.4 T perpendicular to the plane of the loop. The loop is rotated through an angle of 60° in 0.2 s. The value of emf induced in the loop will be:

2.Two heaters rated as \((P_1,V)\) and \((P_2,V)\) are connected in series across a dc source of \(V/2\) volt. The power consumed by the combination will be –

3.A light copper ring is freely suspended by a light string. A bar magnet is held horizontally with its length along the axis of the ring. The magnet is moved towards the ring with its N pole facing the loop. What will happen to the ring and its position? Explain.

4.Two small identical metallic balls having charges \( q \) and \( -2q \) are kept far at a separation \( r \). They are brought in contact and then separated at distance \( \frac{r}{2} \). Compared to the initial force \( F \), they will now:

6. Draw the number of scattered particles versus the scattering angle graph for scattering of alpha particles by a thin foil. Write two important conclusions that can be drawn from this plot.

Similar Physics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
A square loop of side 0.50 m is placed in a uniform magnetic field of 0.4 T perpendicular to the plane of the loop. The loop is rotated through an angle of 60° in 0.2 s. The value of emf induced in the loop will be:

2.
Two heaters rated as \((P_1,V)\) and \((P_2,V)\) are connected in series across a dc source of \(V/2\) volt. The power consumed by the combination will be –

3.
A light copper ring is freely suspended by a light string. A bar magnet is held horizontally with its length along the axis of the ring. The magnet is moved towards the ring with its N pole facing the loop. What will happen to the ring and its position? Explain.

4.
Two small identical metallic balls having charges \( q \) and \( -2q \) are kept far at a separation \( r \). They are brought in contact and then separated at distance \( \frac{r}{2} \). Compared to the initial force \( F \), they will now:

6.
Draw the number of scattered particles versus the scattering angle graph for scattering of alpha particles by a thin foil. Write two important conclusions that can be drawn from this plot.