What is potential difference of a cell?

Cell Potential is the measure of the potential difference between two half cells in an electrochemical cell.

  • The potential difference in a cell is caused by the ability of electrons to flow from one-half of the cell to the other.
  • Electrochemical cell anatomy is given below – 

Electrochemical Cell


Related Questions

  1. Define: 1 volt, Potential difference.
  2. Write Two Differences Between Emf And Potential Difference.
  3. What Is Null Voltage?

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CBSE CLASS XII Related Questions

  • 1.
    Consider the nuclear reaction \( X \to Y + Z \). Let \( M_x \), \( M_y \), and \( M_z \) be the masses of the three nuclei X, Y, and Z respectively. Then which of the following relations hold true?

      • \( (M_x - M_z)<M_y \)
      • \( (M_x - M_y)<M_z \)
      • \( M_x>(M_y + M_z) \)
      • \( M_x<(M_y + M_z) \)

    • 2.
      Draw the plot of potential energy of a pair of nucleons as a function of their separation. Write two important conclusions that can be drawn from this plot.


        • 3.
          A current of \(4.0\,\text{A}\) flows through a wire of length \(1\,\text{m}\) and cross-sectional area \(1.0\,\text{mm}^2\), when a potential difference of \(2\,\text{V}\) is applied across its ends. Calculate the resistivity of the material of the wire.


            • 4.

              (I) The real image of an object placed between $f$ and $2f$ from a convex lens can be seen on a screen placed at the image location. If the screen is removed, is the image still there? Explain.

              (II) Plane and convex mirrors produce virtual images of objects. Can they produce real images under some circumstances? Explain.


                • 5.
                  The resistance of a metal wire at \(20^\circ\text{C}\) is \(1.05\,\Omega\) and at \(100^\circ\text{C}\) is \(1.38\,\Omega\). Determine the temperature coefficient of resistivity of this metal.


                    • 6.
                      Two point charges -Q and Q are located at points (d, 0) and (0, d) respectively, in x-y plane. The electric field E at the origin will be:

                        • \(\frac{1}{4\pi\epsilon_0} \frac{\sqrt{2}Q}{d^2} (\hat{i} - \hat{j})\)
                        • \(\frac{1}{4\pi\epsilon_0} \frac{\sqrt{2}Q}{d^2} (-\hat{i} - \hat{j})\)
                        • \(\frac{1}{4\pi\epsilon_0} \frac{Q}{d^2} (\hat{i} - \hat{j})\)
                        • \(\frac{1}{4\pi\epsilon_0} \frac{Q}{d^2} (-\hat{i} - \hat{j})\)
                      CBSE CLASS XII Previous Year Papers

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