Why is the curve representing Ohm's law linear?

The curve that represents Ohm’s law is linear as the law denotes a linear relationship between the applied voltage and the current produced. The electric current is proportional to the voltage, hence the I–V curve is a straight line through the origin with a positive slope.

Ohm's law V-I graph

Related Questions:

  1. What is the necessary condition for a conductor to obey Ohm's Law?
  2. How do you find the resistance to Ohm's law?
  3. Is resistance constant in Ohm's law?

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CBSE CLASS XII Related Questions

  • 1.
    Write two advantages of reflecting telescope over refracting telescope.


      • 2.
        Consider the nuclear reaction \( X \to Y + Z \). Let \( M_x \), \( M_y \), and \( M_z \) be the masses of the three nuclei X, Y, and Z respectively. Then which of the following relations hold true?

          • \( (M_x - M_z)<M_y \)
          • \( (M_x - M_y)<M_z \)
          • \( M_x>(M_y + M_z) \)
          • \( M_x<(M_y + M_z) \)

        • 3.
          Consider a cylindrical conductor of length \( l \) and area of cross-section \( A \). Current \( I \) is maintained in the conductor and electrons drift with velocity \( \vec{v}_d \, (|\vec{v}_d| = \frac{eE}{m} \tau) \), where symbols have their usual meanings. Show that the conductivity of the material of the conductor is given by \[ \sigma = \frac{n e^2 \tau}{m}. \]


            • 4.
              The resistance of a metal wire at \( 20^\circ \text{C} \) is \( 1.05 \, \Omega \) and at \( 100^\circ \text{C} \) is \( 1.38 \, \Omega \). Determine the temperature coefficient of resistivity of this metal.


                • 5.
                  Two metal spheres of radii $r_1$ and $r_2$ ($> r_1$) having charges $q_1$ and $q_2$ respectively kept in air, are brought in contact. Which of the following statements is not correct ?

                    • The total charge of the two spheres is conserved.
                    • Both spheres attain the same potential.
                    • The final potential of the system equals $\frac{1}{4\pi\epsilon_0} \frac{(q_1 + q_2)}{(r_1 + r_2)}$
                    • The final potential of the system equals $\frac{1}{4\pi\epsilon_0} \frac{(q_1 + q_2) (r_1 + r_2)}{r_1 r_2}$

                  • 6.
                    Read the following paragraph and answer the questions that follow.
                    A p-type or n-type semiconductor can be converted into a p-n junction by doping it with suitable impurity. The motion of majority charge carriers causes diffusion current across the junction while the barrier electric field causes motion of minority carriers for drift current. In case of unbiased diode, the diffusion and drift currents are equal. This equilibrium is disturbed by the biasing batteries. Diodes, therefore, allow currents in one direction. This property of diode is used in making rectifiers.

                      CBSE CLASS XII Previous Year Papers

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