Draw an electric circuit with a cell, key, ammeter, a resistor (series) of 2 ohm with combination of two resistors (4 ohm each) in parallel and a voltmeter across parallel combination.

As per the question, Will the potential difference across the 2 Ω resistor be similar to the one across the parallel combination with 4Ω resistors? The following reasons can be illustrated:

Step 1: Circuit Diagram

The circuit diagram with a cell, key, ammeter, resistors in series (2 \(\Omega\)) with a combination of two resistors can be represented as:

Electric Circuit Diagram

Electric Circuit Diagram

Step 2: Solution

Effective resistance of the parallel connected combination of two resistors is:

Reff = \({4\ \times\ 4} \over {4\ +\ 4}\)

⇒ Reff = \({{16} \over 8}\)

⇒ Reff = 2Ω

Hence, because of the 2 Ω resistor and the parallel combination of two 4 Ω resistors are connected in series, the flow of current will be in the same direction. Due to this reason, the potential difference that occurs between the two-ohm resistors is similar to the potential difference between two resistors jointly.


Related Questions

  1. In An Arrangement Of Resistances, Find Effective Resistance Between Points A and B.
  2. What Is Effective Resistance?
  3. X and Y, which are two resistors, with resistances of 2 Ω and 3 Ω respectively are first connected in parallel and then in series. In both cases, the voltage that is supplied is 5 V. (i) Illustrate a circuit diagram to show the combination of resistors. (ii) Calculate the amount of voltage across 3 Ω resistor in the series combination of resistors.
  4. Two Identical Resistors With Resistances 15 Ohm Are Connected In Series And Parallel To A Battery Of 6 V. Calculate Ratio Of Power Consumed.
  5. A Circuit Consists Of A Battery Of 3 Cells (2 V Each), A Combination Of Three Resistors, 10 Ohm, 20 Ohm And 30 Ohm, Attached Parallelly, With Plug Key And Ammeter (In Series).

Also Check:

CBSE CLASS XII Related Questions

  • 1.
    Consider a cylindrical conductor of length \( l \) and area of cross-section \( A \). Current \( I \) is maintained in the conductor and electrons drift with velocity \( \vec{v}_d \, (|\vec{v}_d| = \frac{eE}{m} \tau) \), where symbols have their usual meanings. Show that the conductivity of the material of the conductor is given by \[ \sigma = \frac{n e^2 \tau}{m}. \]


      • 2.
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          • 3.
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              • 4.
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                  • 5.
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                      • 6.
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                          CBSE CLASS XII Previous Year Papers

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