Fehling’s Test: Procedure, Applications, Fehling’s Solution

Arpita Srivastava logo

Arpita Srivastava

Content Writer

Fehling’s test is one of the most frequently used tests to determine, estimate and identify the sugars which can be both reducing or non-reducing in nature. The formulation of this test was made by the eminent German chemist Hermann von Fehling. The main utilization of this test is for the differentiation between functional groups of ketone and water-soluble carbohydrates

Keyterms: Ketone, Carbohydrates, Copper II Sulphate, Sodium Hydroxide, Alkali, Fehling’s A, Fehling’s B, Aldehyde


Fehling’s Solution

[Click Here for Sample Questions]

Fehling’s test is carried out with a solution that is freshly prepared in the laboratories. The solution is initially present in the form of two solutions known as Fehling’s A and Fehling’s B. 

Fehling’s A Solution contains copper (II) sulphate. It is a deep blue liquid in nature.

Fehling’s B solution contains potassium sodium tartrate (Rochelle salt) along with a strong alkali, most commonly sodium hydroxide. It is a clear liquid in nature. These solutions are separately prepared and subsequently stored.

Later on, both Fehling’s A solution and Fehling’s B solution are mixed so that the final Fehling’s solution can be derived. The equal volumes of these solutions need to be taken into consideration while mixing. The solution is deep blue in colour. The deep blue ingredient that is being taken is a tartrate complex of Cu2+. The tartrate tetra-anions serve as a chelating agent in the solution.

Fehling’s Test

Fehling’s Test

If the outcome of the test is negative, it results in the formation of Ketone. If the outcome of the test is positive, it results in the formation of Aldehyde. Therefore, Fehling’s test is important to distinguish between aldehydes and ketones. 

Also Read:


Fehling’s Test Procedure

[Click Here for Sample Questions]

The process for the conducting of the Fehling’s test is as follows:

  • Take a dry test tube and add the sample to it.
  • Keep distilled water in another test tube as a control.
  • Add the Fehling’s solution in both these test tubes
  • The tubes are recommended to be kept or held in water baths
  • Observations are to be made and any growth or development of red precipitate needs to be noted

If there is a production or formation of a reddish-brown precipitate, the result is positive. If there is no such kind of transition, the result is negative.

Fehling’s Test Procedure
Fehling’s Test Procedure

Once the mixture of both the solutions is heated, Fehling’s B solution prevalent in the reagent carries out the task of chelation. If the solution of the test presents a sugar molecule or an aldehyde or chelated compound which is reddish-brown in colour along with Fehling’s reagent. If such reddish-brown precipitate is formed, it indicates that a reduced sugar or an aldehyde group is prevalent. The determination of reduced sugar is the primary aim of performing Fehling’s test. To ensure the efficiency and effectiveness of the test, it is required to prepare new reagents. As far as Fehling’s reagent test is concerned, lactose, fructose and glucose being sugars give positive results. 


Reactions of Fehling’s Test

[Click Here for Sample Questions]

The reaction between the copper (II) ions and an aldehyde is presented as:

RCHO + 2Cu2+ + 5OH → RCOO. + Cu2O + 3H2O

Once there is an addition of tartrate, it is presented as:

RCHO + 2Cu(C4H4O6)22− + 5 OH → RCOO + Cu2O + 4 C4H4O62− + 3H2O


Applications of Fehling’s Test 

[Click Here for Sample Questions]

Fehling’s test can be taken into consideration for various kinds of purposes. 

  1. The most popular application of Fehling’s test is to identify and determine whether the carbonyl group concerned is a ketone or an aldehyde. Aldehydes tend to be oxidised and display positive results. Ketones, except the alpha-hydroxy-ketones, do not display any kind of reaction. 
  2.  Fehling’s test is also generally used for monosaccharides, commonly known as simple sugars, along with other reducing sugars. In terms of monosaccharides, it displays positive results not only for aldose monosaccharides but also for ketose monosaccharides, since ketoses are transformed into aldoses through the base contained in the reagent. 
  3. It is used to determine the presence of glucose in the urine. It is applied to identify diabetes as being prevalent in the person. 
  4. Fehling’s test is also applied for the breaking down of starch to convert it into glucose syrup along with maltodextrins. 
  5. To determine the Formic acid. The formic acid (HCO2H) gives a positive result for Fehling’s Test.

Things to Remember

  • To carry out the Fehling’s Test, the substance is heated in the presence of Fehling’s Solution. 
  • Fehling’s Solution is prepared freshly in the laboratory. 
  • It is prepared by mixing an equal amount of Fehling’s Solution A and Fehling’s Solution B. 
  • If a reddish-brown precipitate is formed then the result is positive. If there is no such kind of changes, the result is negative. 
  • Fehling’s test is most commonly used to determine whether the carbonyl group is a ketone or an aldehyde. 

Also Read:


Sample Questions

Ques: (a) Write the products formed when CH3CHO reacts with the following reagents:
(i) HCN (ii) H2N–OH (iii) CH3CHO in the presence of dilute NaOH
(b) Give simple chemical tests to distinguish between the following pairs of compounds :
(i) Benzoic acid and Phenol (ii) Propanal and Propanone. (All India 2014, 5 Marks)

Ans: 

(i) HCN (ii) H2N–OH (iii) CH3CHO in the presence of dilute NaOH
(i) HCN (ii) H2N–OH (iii) CH3CHO in the presence of dilute NaOH

(b) (i) Benzoic acid and Phenol: On adding NaHCO3 to both solutions carbon dioxide gas is evolved with benzoic acid while phenol does not form CO2.

 Benzoic acid and Phenol
Benzoic acid and Phenol

(ii) Propanal and Propanone: Propanal gives a positive test with Fehling’s solution in which a red ppt. of cuprous oxide is obtained while propanone does not respond to the test.

Propanal and Propanone
Propanal and Propanone

Ques: (a) Give chemical tests to distinguish between the following pairs of compounds:
(i) Ethanal and Propanone.
(ii) Pentan-2-one and Pentan-3-one.
(b) Arrange the following compounds in increasing order of their acid strength: Benzoic acid, 4- Nitrobenzoic acid, 3,4 -Dinitrobenzoic acid, 4- Methoxybenzoic acid. (All India 2015, 3 Marks)

Ans: (a) (i) Acetaldehyde (Ethanal) and Acetone (Propanone)

Acetaldehyde gives the silver mirror with Tollen’s reagent while Acetone does not give this test.

Acetaldehyde (Ethanal) and Acetone (Propanone)
Acetaldehyde (Ethanal) and Acetone (Propanone)

Acetaldehyde forms red ppt with Fehling’s solution. Acetone does not form a precipitate with Fehling’s Solution.

Acetaldehyde (Ethanal) and Acetone (Propanone)
Acetaldehyde (Ethanal) and Acetone (Propanone)

(ii) Pentan-2-one and Pentan-3-one

Pentan-2-one forms yellow ppt with an alkaline solution of iodine (iodoform test), but pentane-3-one does not give iodoform test.

CH3COCH2CH2CH3 + 3I2+ 4NaOH → CH3CH2CH2COONa + CHI3 + 3H2O + 3NaI

Pentan-2-one gives white ppt with sodium bisulphite while pentan-3-one does not.

Pentan-2-one and Pentan-3-one
Pentan-2-one and Pentan-3-one

(b) 4- Methoxybenzoic add < Benzoic acid < 4- Nitrobenzoic acid < 3,4-Dinitrobenzoic acid 

Ques: Give a simple chemical test to distinguish between Acetophenone and Benzophenone. (2 Marks)

Ans: The test which can distinguish between Acetonphenone and Benzophenone is Fehling’s Test.

Aldehydes respond to Fehling’s test, but ketones do not.

Propanal being an aldehyde reduces Fehling’s solution to a red-brown precipitate of Cu2O, but propanone being a ketone does not react to Fehling’s solution.

Propanal being an aldehyde reduces Fehling’s solution to a red-brown precipitate of Cu2O, but propanone being a ketone does not react to Fehling’s solution.

Ques: Fehling solution does not oxidize benzaldehyde but Tollen's reagent oxidizes benzaldehyde. Give reasons. (2 Marks)

Ans: Aldehydes such as benzaldehyde does not contain alpha hydrogens and cannot form an enolate. Therefore, they do not give a positive test with Fehling's solution which is also a weaker oxidizing agent than Tollen's reagent. That is why Fehling’s solution does not oxidize benzaldehyde and gives negative tests.

Ques: What is Fehling's solution? (1 Mark)

Ans: Fehling’s solution is used to carry out Fehling’s solution. Fehling’s solution is a mixture of an alkaline solution of copper (II) sulphate (CuSO4) and Sodium Potassium Tartrate (Rochelle Salt). The solution is freshly prepared in the laboratories. It is initially present in the form of two solutions known as Fehling’s A and Fehling’s B solution.

Ques: Which of the following aldehydes give a red precipitate with Fehling’s solution? (2 Marks)
(a) Benzaldehyde
(b) Salicyladehyde
(c) Acetaldehyde
(d) None of the above

Ans: Correct option is (C) Acetaldehyde

Explanation: As we know that only aliphatic aldehydes give red ppt of Cu2O with Fehling Solution. So, only acetaldehyde gives a red ppt with Fehling’s solution. 

Ques: Few simple chemical tests are given below to differentiate between the pairs of compounds. Which of the following tests is not correct for differentiation? (2 Marks)
(a) Propanal and Propanone - Silver mirror test
(b) Acetophenone and benzophenone - Idoform test
(c) Ethanal and propanal - Fehling’s test
(d) Benzoic acid and ethyl benzoate- Sodium bicarbonate test

Ans: The correct option is (c) Ethanal and propanal - Fehling's test

Explanation: Both ethanal and propanal can not be differentiated by Fehling’s Solution test. They both will give the silver mirror test and form a red precipitate with Fehling's solution.

For Latest Updates on Upcoming Board Exams, Click Here: https://t.me/class_10_12_board_updates


Do Check Out:

Class 11 & 12 PCMB Study Guides
Formulas in Physics Class 12 Physics Notes SI units in Physics
Topics for Comparison in Physics MCQs in physics Important Physics Constants and Units
Class 12 Biology Notes Fundamental theorem of arithmetic NCERT Solutions for Class 11 Maths
Important Derivations in Physics Calculus Important Chemical Reactions
Geometry Determine Refractive Index of Glass NCERT Solutions for Class 12 Biology
NCERT Solutions for Class 12 English NCERT Solutions for Class 12 Maths Probability and Statistics
Class 12 Chemistry Notes NCERT Solutions for Class 12 Physics Class 12 Maths Notes
Topics with relation in physics NCERT Class 11 Physics Book NCERT Solutions for Class 12 Chemistry
Class 11 Notes Class 12 Physics Practicals Class 12 Physics Book PDF
NCERT Solutions for Class 11 Chemistry Chemistry MCQs NCERT Solutions for Class 11 English
NCERT Class 11 Chemistry Book Class 12 Physics Syllabus Number Systems
Biology MCQs NCERT Solutions for Class 11 Physics Important Chemistry Formulas
Class 11 PCMB Syllabus Trigonometry Biology Study Notes
Mensuration Comparison Topics in Biology Comparison topics in Chemistry
Comparison Topics in Maths Permutation and Combination Physics Study Notes
NCERT Class 12 Textbooks NCERT Class 12 Biology Book NCERT Class 12 Maths Book
Important Maths Formulas Maths MCQs Periodic Table in Chemistry
Chemistry Study Notes Class 12 Chemistry Practicals NCERT Class 11 Biology Book
Important Named Reactions NCERT Solutions for Class 11 Biology Class 12 PCMB Notes

CBSE CLASS XII Related Questions

  • 1.
    Give structures of A, B and C: Aniline $\xrightarrow{Br_2/H_2O}$ A $\xrightarrow{NaNO_2+HCl, 0-5^\circ C}$ B $\xrightarrow{H_3PO_2+H_2O}$ C


      • 2.
        Explain: (i) Presence of carbonyl group in glucose. (ii) Presence of five $-$OH groups attached to different carbon atoms.


          • 3.
            Why is o-nitrophenol more acidic than o-methoxyphenol?


              • 4.
                Which isomer of $C_4H_9Br$ is most reactive towards $S_N1$ reaction?


                  • 5.
                    61 g benzoic acid (M = 122 g mol$^{-1}$) dissolved in 500 g benzene. Vapour pressure of pure benzene = 66 torr. Assume complete dimerisation. Calculate vapour pressure of solution.


                      • 6.
                        What are reducing sugars?

                          CBSE CLASS XII Previous Year Papers

                          Comments


                          No Comments To Show