In a balanced condition, resistance R3 has temperature coefficient 0.0004 degree C−1

As per the question, resistance R3 has a temperature coefficient of 0.0004^∘C⁻¹in a balanced condition. And, the temperature of R3 is increased by 100^∘C. In order to determine the voltage generated between S and T, we have to consider the following formula:

R¹= R₀ (1 + \(\alpha\)\(\Delta\)T)

Values of Resistance

Values of Resistance

Thus, after replacing the values, we get:

⇒ 300 (1 + 0.0004 \(\times\) 100)

Therefore, R¹ = 312 \(\Omega\)

I₁ = \({{50} \over 370}\)A

I₂ = \({{50} \over 600}\)A

⇒ V_s – \({{50} \over 370}\) \(\times\) 312 + \({{50} \over 600}\) \(\times\) 500 = V_T

V_s– V_T = 0.26 Volts (V)

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In a balanced condition, resistance R3 has temperature coefficient 0.0004 degree C 1. With temperature of R3 increased by 100 degree C, find voltage generated between S and T.

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In a balanced condition, resistance R3 has temperature coefficient 0.0004 degree C 1. With temperature of R3 increased by 100 degree C, find voltage generated between S and T.

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2. If both the number of protons and the neutrons are conserved in each nuclear reaction, in what way is mass converted into energy (or vice versa) in a nuclear reaction? Explain.

3. Draw the number of scattered particles versus the scattering angle graph for scattering of alpha particles by a thin foil. Write two important conclusions that can be drawn from this plot.

4.Write the expression for the magnetic field due to a current element in vector form. Consider a 1 cm segment of a wire, centered at the origin, carrying a current of 10 A in positive x-direction. Calculate the magnetic field \( \mathbf{B} \) at a point \( (1 \, \text{m}, 1 \, \text{m}, 0) \).

5.The figure shows three point charges kept at the vertices of triangle ABC. The net electric field, due to this system of charges, at the midpoint M of base BC will be:

6.Two small identical metallic balls having charges \( q \) and \( -2q \) are kept far at a separation \( r \). They are brought in contact and then separated at distance \( \frac{r}{2} \). Compared to the initial force \( F \), they will now:

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5.
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6.
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