In a balanced condition, resistance R3 has temperature coefficient 0.0004 degree C 1. With temperature of R3 increased by 100 degree C, find voltage generated between S and T.

As per the question, resistance R3​ has a temperature coefficient of 0.0004∘C−1 in a balanced condition. And, the temperature of R3​ is increased by 100∘C. In order to determine the voltage generated between S and T, we have to consider the following formula:

R1 = R0 (1 + \(\alpha\)\(\Delta\)T)

Values of Resistance

Values of Resistance

Thus, after replacing the values, we get:

⇒ 300  (1 + 0.0004 \(\times\) 100)

Therefore, R1 = 312 \(\Omega\)

I1 = \({{50} \over 370}\)A

I2 = \({{50} \over 600}\)A

⇒ Vs – \({{50} \over 370}\) \(\times\) 312 + \({{50} \over 600}\) \(\times\) 500 = VT

Vs – VT = 0.26 Volts (V)


Related Questions

  1. Why should we get the null point in the middle of the Metre bridge wire?
  2. How does a bridge circuit work?
  3. Can you find very high resistance accurately with the help of a Metre bridge?
  4. Why Carey Foster Bridge Is So Sensitive?
  5. Meter Bridge or Slide Wire Bridge is a practical form of?
  6. Meter bridge works on the principle of?
  7. How do you solve an unbalanced bridge?
  8. Why is Wheatstone's bridge more accurate?
  9. What Is Null Voltage?

Read More:

CBSE CLASS XII Related Questions

  • 1.
    Capacitors are manufactured with certain standard capacitances and working voltages. However, these standard values may not be the ones that are actually needed in a particular application. Two or more capacitors can be grouped in series or in parallel to achieve desired capacitance and voltage. When connected in series, the total capacitance decreases while the voltage rating increases, whereas in parallel connections, the total capacitance increases and maintains the same voltage rating. A capacitor stores energy in the electric field between its plates and stored energy is proportional to the square of the voltage and capacitance $U = \frac{1}{2}CV^2$, where symbols have their usual meanings.
    Two capacitors, one of $3 \ \mu$F and the other of $6 \ \mu$F, are connected in series in the circuit as shown in the figure, for a long time. }


      • 2.
        Two air-filled capacitors of capacitances $C_1$ and $C_2$ are connected in parallel with a dc battery. After the capacitors are fully charged, a slab of dielectric constant K is inserted between the plates of each capacitor. How will the (i) charge on each capacitor and (ii) energy stored in the capacitor affected after the slab is introduced.


          • 3.
            Consider the nuclear reaction \( X \to Y + Z \). Let \( M_x \), \( M_y \), and \( M_z \) be the masses of the three nuclei X, Y, and Z respectively. Then which of the following relations hold true?

              • \( (M_x - M_z)<M_y \)
              • \( (M_x - M_y)<M_z \)
              • \( M_x>(M_y + M_z) \)
              • \( M_x<(M_y + M_z) \)

            • 4.
              An electric field $\vec{E}$ is established across the ends of a cylindrical conductor of length L and area of cross-section A. Discuss how electrons attain an average velocity, independent of time. Hence, obtain a relation between current in the conductor and this ‘average velocity’ of electrons.


                • 5.
                  Read the following paragraph and answer the questions that follow.
                  In an experiment with convex lens of focal length f, the screen is fixed at a distance D from the object. A student slowly moves the lens away from the object towards the screen and finds that she is able to form sharp image of the object for two positions of the lens. The distance between these two positions of the lens is d.


                    • 6.
                      A charged particle $+q$ in an electric field $\vec{E}$ experiences a force in the direction of the electric field. As a result, its kinetic energy changes. Similarly, the charged particle also experiences a force when it moves in a magnetic field $\vec{B}$. But this magnetic force is perpendicular to both velocity $\vec{v}$ of the charged particle and the magnetic field $\vec{B}$, so it cannot change the kinetic energy of the charged particle. Consider two charged particles 1 and 2 of masses $m$ and $\frac{m}{2}$ having charges $-q$ and $+2q$ respectively. They are accelerated from rest through the same potential difference $V$ and acquire kinetic energy $K_1$ and $K_2$. Then they enter in a region of uniform magnetic field $\vec{B}$ perpendicular to their velocities.

                        CBSE CLASS XII Previous Year Papers

                        Comments


                        No Comments To Show