NCERT Solutions For Class 12 Physics Chapter 9: Ray Optics and Optical Instruments

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Jasmine Grover

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NCERT Solutions for Class 12 Physics Chapter 9 Ray Optics and Optical Instruments are provided in this article. Optics helps us study the properties and behaviour of light. In Ray Optics, the light travels in a straight line stating that there is an image for each and every object. The optical devices made utilising reflecting and refracting properties of lenses, mirrors and prisms known as Optical instruments.

Class 12 Physics Chapter 9 is a part of Unit 6 Optics which along with Unit 5 Electromagnetic Waves has a weightage of 18 marks in the CBSE Class 12 Board exam.  The NCERT Solutions for Class 12 Physics Chapter 9 covers concepts of refraction, Snell’s Law, and total internal reflection

Download PDF: NCERT Solutions for Class 12 Physics Chapter 9 Ray Optics and Optical Instruments


NCERT Solutions for Class 12 Physics Chapter 9

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Class 12 Physics Chapter 9 – Important Topics Covered

  • Ray Optics is the branch of physics that deals with the behaviour of light as a ray which travels in a straight line.
Light always travels in a straight line. It does not require any medium to travel
  • Reflection is the phenomenon wherein light changes its path without any change in the medium.

Laws of Reflection

  1. The angle of incidence, represented as i is equal to the angle of reflection, represented as r.
    ∠i = ∠r.
  2. The incident ray, the reflected ray and the normal to the reflecting surface at the incidence point, all lie in the same plane.
  • The mirror formula represents a relation between the focal length of the mirror and the distances of objects and images from the mirror.
\({1 \over v} + {1 \over u} = {1 \over f} \)
  • Linear Magnification: The ratio of the size of the image that is formed by a spherical mirror I to the size of the object O is known as linear magnification.
\(m={I \over O}={-v \over u}\)
  • Refraction is the phenomenon of change in the path of light as it goes from one medium to another.

Laws of Refraction

  1. The incident ray, refracted ray and the normal to the refracting surface at the point of incidence, all lie in the same plane.
  2. The ratio of the sin of the angle of incidence to the sin of the angle of refraction is constant for any two given mediums. This constant is the relative refractive index.

n = sin i/sin r (Snell’s law)

where, n is the refractive index of the second medium when first medium is air.
 


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CBSE CLASS XII Related Questions

  • 1.

    (I) The real image of an object placed between $f$ and $2f$ from a convex lens can be seen on a screen placed at the image location. If the screen is removed, is the image still there? Explain.

    (II) Plane and convex mirrors produce virtual images of objects. Can they produce real images under some circumstances? Explain.


      • 2.

        Find the ratio $\dfrac{\lambda_\alpha}{\lambda_p}$ of the de Broglie wavelength $\lambda_\alpha$ associated with an alpha particle to the de Broglie wavelength $\lambda_p$ associated with a proton if both are moving with the same velocity.


          • 3.

            A square loop of side 0.50 m is placed in a uniform magnetic field of 0.4 T perpendicular to the plane of the loop. The loop is rotated through an angle of $60^\circ$ in 0.2 s. The value of emf induced in the loop will be:

              • 5 V
              • 3.5 V
              • 2.5 V
              • Zero V

            • 4.

              A circular coil of 100 turns and radius $\left(\frac{10}{\sqrt{\pi}}\right)$ cm carrying current of $5.0\,\text{A}$ is suspended vertically in a uniform horizontal magnetic field of $2.0\,\text{T}$. The field makes an angle $30^\circ$ with the normal to the coil. Calculate:

              (I) the magnetic dipole moment of the coil, and

              (II) the magnitude of the counter torque that must be applied to prevent the coil from turning.


                • 5.

                  A magnet held vertically, with its north pole down, is dropped along the axis of a closed solenoid placed vertically on a table. If the observer looks down from the top,

                    • the induced current will flow in the anticlockwise direction.
                    • the induced current will flow in the clockwise direction.
                    • no induced current will flow in the solenoid.
                    • the magnet will fall with a constant velocity.

                  • 6.
                    Two point charges -Q and Q are located at points (d, 0) and (0, d) respectively, in x-y plane. The electric field E at the origin will be:

                      • \(\frac{1}{4\pi\epsilon_0} \frac{\sqrt{2}Q}{d^2} (\hat{i} - \hat{j})\)
                      • \(\frac{1}{4\pi\epsilon_0} \frac{\sqrt{2}Q}{d^2} (-\hat{i} - \hat{j})\)
                      • \(\frac{1}{4\pi\epsilon_0} \frac{Q}{d^2} (\hat{i} - \hat{j})\)
                      • \(\frac{1}{4\pi\epsilon_0} \frac{Q}{d^2} (-\hat{i} - \hat{j})\)
                    CBSE CLASS XII Previous Year Papers

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