State Ohm's law. How can it be verified experimentally?

Ohm’s law states that voltage across a conductor is directly proportional to the current flowing through it, provided the temperature and physical conditions remain constant.

Experimental Verification of Ohm’s Law

The experiment that can easily verify Ohm’s Law is given below – 
Apparatus Required:

Circuit Diagram:

Ohm's Law Circuit Diagram

Procedure:

  • The key K is initially closed, and the rheostat is adjusted to get the minimum reading in Ammeter A and voltmeter V.
  • The current is gradually increased in the circuit by moving the sliding terminal of the rheostat.
  • During the process, current flows in the circuit, and a corresponding value of potential difference across the resistance wire R is recorded.
  • Therefore, different sets of values of current and voltage are obtained.
  • For each set of values of V and I, the V/I ratio is calculated.
  • When you calculate V/I for each recording, you will observe that it is almost the same. So V/I = R is a constant.
  • Plot a graph of current against potential difference which will be a straight line.
  • This shows that the current is proportional to the potential difference.

Related Questions:

  1. What is the necessary condition for a conductor to obey Ohm's Law?
  2. Why is the curve representing Ohm's law linear?
  3. What are the limitations of Ohm's Law?
  4. How do you find the resistance to Ohm's law?
  5. What are the 3 forms of Ohm's law
  6. Is resistance constant in Ohm's law?

Read More:

CBSE CLASS XII Related Questions

  • 1.
    An electric field $\vec{E}$ is established across the ends of a cylindrical conductor of length L and area of cross-section A. Discuss how electrons attain an average velocity, independent of time. Hence, obtain a relation between current in the conductor and this ‘average velocity’ of electrons.


      • 2.
        A charged particle $+q$ in an electric field $\vec{E}$ experiences a force in the direction of the electric field. As a result, its kinetic energy changes. Similarly, the charged particle also experiences a force when it moves in a magnetic field $\vec{B}$. But this magnetic force is perpendicular to both velocity $\vec{v}$ of the charged particle and the magnetic field $\vec{B}$, so it cannot change the kinetic energy of the charged particle. Consider two charged particles 1 and 2 of masses $m$ and $\frac{m}{2}$ having charges $-q$ and $+2q$ respectively. They are accelerated from rest through the same potential difference $V$ and acquire kinetic energy $K_1$ and $K_2$. Then they enter in a region of uniform magnetic field $\vec{B}$ perpendicular to their velocities.


          • 3.
            A student sets up the circuit as shown in the figure to find the value of unknown resistance X and records a set of readings of the voltmeter and the ammeter by using the rheostat.


              • 4.
                With the help of a labelled diagram, explain the principle, construction and working of an a.c. generator.


                  • 5.
                    Two air-filled capacitors of capacitances $C_1$ and $C_2$ are connected in parallel with a dc battery. After the capacitors are fully charged, a slab of dielectric constant K is inserted between the plates of each capacitor. How will the (i) charge on each capacitor and (ii) energy stored in the capacitor affected after the slab is introduced.


                      • 6.
                        An astronomical telescope consists of two converging lenses. One of them of large aperture and large focal length is called objective lens and the other one, of smaller focal length and smaller aperture is called the eyepiece. It is used to see distant objects which are not seen clearly with naked eyes. The image formed by the objective lens acts as an object for the eyepiece and the final image produced by the eyepiece is magnified.

                          CBSE CLASS XII Previous Year Papers

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