State Ohm's law. How can it be verified experimentally?

Ohm’s law states that voltage across a conductor is directly proportional to the current flowing through it, provided the temperature and physical conditions remain constant.

Experimental Verification of Ohm’s Law

The experiment that can easily verify Ohm’s Law is given below – 
Apparatus Required:

Circuit Diagram:

Ohm's Law Circuit Diagram

Procedure:

  • The key K is initially closed, and the rheostat is adjusted to get the minimum reading in Ammeter A and voltmeter V.
  • The current is gradually increased in the circuit by moving the sliding terminal of the rheostat.
  • During the process, current flows in the circuit, and a corresponding value of potential difference across the resistance wire R is recorded.
  • Therefore, different sets of values of current and voltage are obtained.
  • For each set of values of V and I, the V/I ratio is calculated.
  • When you calculate V/I for each recording, you will observe that it is almost the same. So V/I = R is a constant.
  • Plot a graph of current against potential difference which will be a straight line.
  • This shows that the current is proportional to the potential difference.

Related Questions:

  1. What is the necessary condition for a conductor to obey Ohm's Law?
  2. Why is the curve representing Ohm's law linear?
  3. What are the limitations of Ohm's Law?
  4. How do you find the resistance to Ohm's law?
  5. What are the 3 forms of Ohm's law
  6. Is resistance constant in Ohm's law?

Read More:

CBSE CLASS XII Related Questions

  • 1.

    (I) The real image of an object placed between $f$ and $2f$ from a convex lens can be seen on a screen placed at the image location. If the screen is removed, is the image still there? Explain.

    (II) Plane and convex mirrors produce virtual images of objects. Can they produce real images under some circumstances? Explain.


      • 2.

        A ray of light MN is incident normally on the face corresponding with side AB of a prism with an isosceles right-angled triangular base ABC. Trace the path of the ray as it passes through the prism when the refractive index of the prism material is (i) $\sqrt{2}$, and (ii) $\sqrt{3}$.


          • 3.
            In a region, the electric potential varies as \(V = 10 - 50x\), where \(V\) is in volts and \(x\) is in meters. The electric field in the region is

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                • 5.
                  Two point charges -Q and Q are located at points (d, 0) and (0, d) respectively, in x-y plane. The electric field E at the origin will be:

                    • \(\frac{1}{4\pi\epsilon_0} \frac{\sqrt{2}Q}{d^2} (\hat{i} - \hat{j})\)
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                  • 6.

                    A square loop of side 0.50 m is placed in a uniform magnetic field of 0.4 T perpendicular to the plane of the loop. The loop is rotated through an angle of $60^\circ$ in 0.2 s. The value of emf induced in the loop will be:

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                    CBSE CLASS XII Previous Year Papers

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