The image shows an unbalanced Wheatstone bridge. Find direction of conventional current between B and D.

The potential drop present across AD is lesser than the one across AB. Therefore, the potential of D is seen to be higher than the one of B. Thus, the flow is generally from D to B.

Unbalanced Wheatstone Bridge

Unbalanced Wheatstone Bridge

What is Wheatstone Bridge?

Wheatstone bridge, otherwise called resistance bridge, helps in the calculation of unknown resistance means of balancing two legs of the bridge circuit. Here, one of the legs contains the component of unknown resistance.

Construction of Wheatstone bridge

Wheatstone bridge circuit basically comprises of four arms. Wherein, two arms contain of known resistances while the other two arms consist of an unknown resistance and a variable resistance. In the construction of Wheatstone bridge, the circuit consists of a galvanometer as well as an electromotive force source. Herein, the emf source is connected between two points a and b.

Wheatstone Bridge

Wheatstone Bridge

On the other hand, the galvanometer is connected between points c and d. The current which is seen to flow via the galvanometer depends on the potential difference across it.


Related Questions

  1. Meter bridge works on the principle of?
  2. Why should we get the null point in the middle of the Metre bridge wire?
  3. How does a bridge circuit work?
  4. Define Wheatstone bridge.
  5. Can you find very high resistance accurately with the help of a Metre bridge?
  6. Why Carey Foster Bridge Is So Sensitive?
  7. Meter Bridge or Slide Wire Bridge is a practical form of?
  8. How do you solve an unbalanced bridge?
  9. Why is Wheatstone's bridge more accurate?
  10. What Is Null Voltage?

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CBSE CLASS XII Related Questions

  • 1.
    A light copper ring is freely suspended by a light string. A bar magnet is held horizontally with its length along the axis of the ring. The magnet is moved towards the ring with its N pole facing the loop. What will happen to the ring and its position? Explain.


      • 2.
        Four independent waves are expressed as \[ (i)\; y_1=A_1\sin\omega t, \] \[ (ii)\; y_2=A_2\sin 2\omega t, \] \[ (iii)\; y_3=A_3\cos\omega t, \] \[ (iv)\; y_4=A_4\sin\left(\omega t+\frac{\pi}{3}\right) \] The interference between two of these waves is possible in

          • (i) and (iii) only
          • (iii) and (iv) only
          • (i), (iii) and (iv) only
          • All of them

        • 3.
          Assertion (A) : All atoms have a net magnetic moment. Reason (R) : A current loop does not always behave as a magnetic dipole.

            • Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
            • Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
            • Assertion (A) is true, but Reason (R) is false.
            • Both Assertion (A) and Reason (R) are false.

          • 4.
            The figure shows three point charges kept at the vertices of triangle ABC. The net electric field, due to this system of charges, at the midpoint M of base BC will be:

              • \( \frac{q}{4 \pi \epsilon_0 l^2} \) pointing along MA
              • \( \frac{q}{\pi \epsilon_0 l^2} \) pointing along AM
              • \( \frac{q}{2 \pi \epsilon_0 l^2} \) pointing along AM
              • Zero

            • 5.
              If Bohr’s quantization postulate (angular momentum \( = \frac{nh}{2\pi} \)) is a basic law of nature, it should be equally valid for the case of planetary motion also. Why, then, do we never speak of quantization of orbits of planets around the Sun? Explain.


                • 6.
                  If both the number of protons and the neutrons are conserved in each nuclear reaction, in what way is mass converted into energy (or vice versa) in a nuclear reaction? Explain.

                    CBSE CLASS XII Previous Year Papers

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