What is a Wheatstone Bridge?

A Wheatstone bridge is an electrical circuit wherein an unknown electrical resistance can be measured by means of two different portions belonging to a bridge circuit.

What is Wheatstone Bridge?

Wheatstone bridge, otherwise called resistance bridge, assists in the calculation of unknown resistance with the help of balancing two legs of the bridge circuit. Out of both, one leg comprises the component of unknown resistance. Wheatstone bridge basically works on the principle of null deflection, which can be expressed as the ratio of their resistances being equivalent with no current flows through the circuit.

Applications of Wheatstone Bridge

Some of the applications of Wheatstone Bridge include:

  • Wheatstone bridge is often used for the measurement of very low resistance values with accuracy.
  • Wheatstone bridge, alongside being an operational amplifier, is also utilised to gauge physical parameters, such as, temperature, strain, light, and more.
  • Wheatstone bridge also helps in the estimation of quantities of capacitance, inductance and impedance using the variations.

Related Questions of Wheatstone Bridge

  1. Why should we get the null point in the middle of the Metre bridge wire?
  2. How does a bridge circuit work?
  3. Can you find very high resistance accurately with the help of a Metre bridge?
  4. Why Carey Foster Bridge Is So Sensitive?
  5. A meter bridge also called a slide wire bridge is an instrument that works on the principle of a Wheatstone bridge. A meter bridge is used in finding the unknown resistance of a conductor as that of in a Wheatstone bridge.
  6. Meter Bridge or Slide Wire Bridge is a practical form of?
  7. Meter bridge works on the principle of?
  8. How do you solve an unbalanced bridge?
  9. Why is Wheatstone's bridge more accurate?
  10. What Is Null Voltage?

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CBSE CLASS XII Related Questions

  • 1.
    A long solenoid of length \( L \) and radius \( r_1 \) having \( N_1 \) turns is surrounded symmetrically by a coil of radius \( r_2 \, (r_2>r_1) \) having \( N_2 \) turns (\( N_2 \ll N_1 \)) around its mid-point. Derive an expression for the mutual inductance of solenoid and coil. Is \( M_{12} = M_{21} \) valid in this case?


      • 2.
        Two thin lenses of focal length \( f_1 \) and \( f_2 \) are placed in contact with each other coaxially. Prove that the focal length \( f \) of the combination is given by \[ f = \frac{f_1 f_2}{f_1 + f_2}. \]


          • 3.
            Suppose a pure Si crystal has \( 5 \times 10^{28} \) atoms per \( \text{m}^3 \). It is doped with \( 5 \times 10^{22} \) atoms per \( \text{m}^3 \) of Arsenic. Calculate majority and minority carrier concentration in the doped silicon. (Given: \( n_i = 1.5 \times 10^{16} \, \text{m}^{-3} \))


              • 4.
                If Bohr’s quantization postulate (angular momentum \( = \frac{nh}{2\pi} \)) is a basic law of nature, it should be equally valid for the case of planetary motion also. Why, then, do we never speak of quantization of orbits of planets around the Sun? Explain.


                  • 5.
                    Write the expression for the magnetic field due to a current element in vector form. Consider a 1 cm segment of a wire, centered at the origin, carrying a current of 10 A in positive x-direction. Calculate the magnetic field \( \mathbf{B} \) at a point \( (1 \, \text{m}, 1 \, \text{m}, 0) \).


                      • 6.
                        The figure shows three point charges kept at the vertices of triangle ABC. The net electric field, due to this system of charges, at the midpoint M of base BC will be:

                          • \( \frac{q}{4 \pi \epsilon_0 l^2} \) pointing along MA
                          • \( \frac{q}{\pi \epsilon_0 l^2} \) pointing along AM
                          • \( \frac{q}{2 \pi \epsilon_0 l^2} \) pointing along AM
                          • Zero
                        CBSE CLASS XII Previous Year Papers

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