Three incandescent bulbs (each 100 W) are attached in series. In another circuit, three more bulbs of same wattage are attached parallelly to an equal source. Give reasons.

A circuit can only be connected in series if same amount of current passes via the resistors. In every circuit, the amount of voltage across the resistors will be different. Simply put, in a series combination, if even one of the resistors is broken or turns out faulty, then the entire circuit turns off.

Will the bulb in the two circuits have the same brightness?

The bulbs’ resistances in series combination will have to be three times the resistance of one bulb alone. Therefore, the current that passes in the series combination will have to be about one-third in opposition to the current in each bulb in a parallel combination. Hence, it can be said that in parallel combination, the bulbs will glow brighter.

With one bulb fused, will the rest continue to glow in each circuit?

In series combination, the bulbs will gradually stop glowing due to the broken or faulty circuit and will have zero current. However, if the bulbs continue in parallel combination, then they will glow with the same brightness as earlier.

Related Questions

Do Check:

Important Topics of Resistors in Series
Ohm’s law	Derivation of Drift Velocity	Voltage
Cells, emf, Internal Resistance	Unit of Specific Resistance	Power of Alternating Current
Combination of Resistors	Cells in Series and in Parallel	Ohm’s Law and its Limitations
Relation between kva and kw	Unit of Current	Resistivity Temperature Dependence
Types of Current	Difference between air conditioning and refrigeration	Permittivity And Permeability
Ampere	Wheatstone Bridge	Resistivity formula
Electrical Formula	Difference between RTD and thermocouple	Types of Resistors
Resistance Formula	Difference between kva and kw	Current Electricity MCQ
Static Electricity	Relation between resistance and length	Resistor Colour Codes
Current density	Conductivity	Electromotive Force
Current density formula	Difference between AC and DC	Difference between emf and voltage
Potentiometer	Difference Between Primary Cell and Secondary Cell	Internal resistance formula
Current Electricity	Electric Dipole	Power transformers
Carbon Resistor	Differences Between Acceleration and Velocity	Relation between power and resistance
Drift Velocity	Difference between earth and neutral	Uses of Resistor

CBSE CLASS XII Related Questions

1.
(I) The real image of an object placed between $f$ and $2f$ from a convex lens can be seen on a screen placed at the image location. If the screen is removed, is the image still there? Explain.
(II) Plane and convex mirrors produce virtual images of objects. Can they produce real images under some circumstances? Explain.

View Solution

2.
A wire of length $L$ is bent round into (i) a square coil having $N$ turns and (ii) a circular coil having $N$ turns. The coil in both cases is free to turn about a vertical axis coinciding with the plane of the coil, in a uniform, horizontal magnetic field and carry the same currents. Find the ratio of the maximum value of the torque acting on the square coil to that on the circular coil.

View Solution

3.
A circular coil of 100 turns and radius $\left(\frac{10}{\sqrt{\pi}}\right)$ cm carrying current of $5.0\,\text{A}$ is suspended vertically in a uniform horizontal magnetic field of $2.0\,\text{T}$. The field makes an angle $30^\circ$ with the normal to the coil. Calculate:
(I) the magnetic dipole moment of the coil, and
(II) the magnitude of the counter torque that must be applied to prevent the coil from turning.

View Solution

4.
A current of $4.0\,\text{A}$ flows through a wire of length $1\,\text{m}$ and cross-sectional area $1.0\,\text{mm}^2$, when a potential difference of $2\,\text{V}$ is applied across its ends. Calculate the resistivity of the material of the wire.

View Solution

5.
Two point charges -Q and Q are located at points (d, 0) and (0, d) respectively, in x-y plane. The electric field E at the origin will be:

$\frac{1}{4\pi\epsilon_0} \frac{\sqrt{2}Q}{d^2} (\hat{i} - \hat{j})$
$\frac{1}{4\pi\epsilon_0} \frac{\sqrt{2}Q}{d^2} (-\hat{i} - \hat{j})$
$\frac{1}{4\pi\epsilon_0} \frac{Q}{d^2} (\hat{i} - \hat{j})$
$\frac{1}{4\pi\epsilon_0} \frac{Q}{d^2} (-\hat{i} - \hat{j})$

View Solution

6.
The resistance of a metal wire at $20^\circ\text{C}$ is $1.05\,\Omega$ and at $100^\circ\text{C}$ is $1.38\,\Omega$. Determine the temperature coefficient of resistivity of this metal.

View Solution

Three incandescent bulbs (each 100 W) are attached in series. In another circuit, three more bulbs of same wattage are attached parallelly to an equal source. So, give reasons for the following.

Will the bulb in the two circuits have the same brightness?

With one bulb fused, will the rest continue to glow in each circuit?

Related Questions

CBSE CLASS XII Related Questions

4.
A current of \(4.0\,\text{A}\) flows through a wire of length \(1\,\text{m}\) and cross-sectional area \(1.0\,\text{mm}^2\), when a potential difference of \(2\,\text{V}\) is applied across its ends. Calculate the resistivity of the material of the wire.

5.
Two point charges -Q and Q are located at points (d, 0) and (0, d) respectively, in x-y plane. The electric field E at the origin will be:

6.
The resistance of a metal wire at \(20^\circ\text{C}\) is \(1.05\,\Omega\) and at \(100^\circ\text{C}\) is \(1.38\,\Omega\). Determine the temperature coefficient of resistivity of this metal.

Similar Physics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

Three incandescent bulbs (each 100 W) are attached in series. In another circuit, three more bulbs of same wattage are attached parallelly to an equal source. So, give reasons for the following.

Will the bulb in the two circuits have the same brightness?

With one bulb fused, will the rest continue to glow in each circuit?

Related Questions

CBSE CLASS XII Related Questions

4.A current of \(4.0\,\text{A}\) flows through a wire of length \(1\,\text{m}\) and cross-sectional area \(1.0\,\text{mm}^2\), when a potential difference of \(2\,\text{V}\) is applied across its ends. Calculate the resistivity of the material of the wire.

5.Two point charges -Q and Q are located at points (d, 0) and (0, d) respectively, in x-y plane. The electric field E at the origin will be:

6.The resistance of a metal wire at \(20^\circ\text{C}\) is \(1.05\,\Omega\) and at \(100^\circ\text{C}\) is \(1.38\,\Omega\). Determine the temperature coefficient of resistivity of this metal.

Similar Physics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

4.
A current of \(4.0\,\text{A}\) flows through a wire of length \(1\,\text{m}\) and cross-sectional area \(1.0\,\text{mm}^2\), when a potential difference of \(2\,\text{V}\) is applied across its ends. Calculate the resistivity of the material of the wire.

5.
Two point charges -Q and Q are located at points (d, 0) and (0, d) respectively, in x-y plane. The electric field E at the origin will be:

6.
The resistance of a metal wire at \(20^\circ\text{C}\) is \(1.05\,\Omega\) and at \(100^\circ\text{C}\) is \(1.38\,\Omega\). Determine the temperature coefficient of resistivity of this metal.