Three incandescent bulbs (each 100 W) are attached in series. In another circuit, three more bulbs of same wattage are attached parallelly to an equal source. So, give reasons for the following.

A circuit can only be connected in series if same amount of current passes via the resistors. In every circuit, the amount of voltage across the resistors will be different. Simply put, in a series combination, if even one of the resistors is broken or turns out faulty, then the entire circuit turns off.

Will the bulb in the two circuits have the same brightness?

The bulbs’ resistances in series combination will have to be three times the resistance of one bulb alone. Therefore, the current that passes in the series combination will have to be about one-third in opposition to the current in each bulb in a parallel combination. Hence, it can be said that in parallel combination, the bulbs will glow brighter.

With one bulb fused, will the rest continue to glow in each circuit? 

In series combination, the bulbs will gradually stop glowing due to the broken or faulty circuit and will have zero current. However, if the bulbs continue in parallel combination, then they will glow with the same brightness as earlier.


Related Questions

  1. In An Arrangement Of Resistances, Find Effective Resistance Between Points A and B.
  2. What Is Effective Resistance?
  3. What is Null Voltage?
  4. X and Y, which are two resistors, with resistances of 2 Ω and 3 Ω respectively are first connected in parallel and then in series. In both cases, the voltage that is supplied is 5 V. (i) Illustrate a circuit diagram to show the combination of resistors. (ii) Calculate the amount of voltage across 3 Ω resistor in the series combination of resistors.
  5. Draw An Electric Circuit With A Cell, Key, Ammeter, A Resistor (Series) Of 2 Ohm With Combination Of Two Resistors (4 Ohm Each) In Parallel And A Voltmeter Across Parallel Combination.
  6. Two Identical Resistors With Resistances 15 Ohm Are Connected In Series And Parallel To A Battery Of 6 V. Calculate Ratio Of Power Consumed.
  7. A Circuit Consists Of A Battery Of 3 Cells (2 V Each), A Combination Of Three Resistors, 10 Ohm, 20 Ohm And 30 Ohm, Attached Parallelly, With Plug Key And Ammeter (In Series).

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CBSE CLASS XII Related Questions

  • 1.
    Two small identical metallic balls having charges \( q \) and \( -2q \) are kept far at a separation \( r \). They are brought in contact and then separated at distance \( \frac{r}{2} \). Compared to the initial force \( F \), they will now:

      • attract with a force \( \frac{F}{2} \)
      • repel with a force \( \frac{F}{2} \)
      • repel with a force \( F \)
      • attract with a force \( F \)

    • 2.
      Write any two features of nuclear forces.


        • 3.
          Assertion (A) : The mass of a nucleus is less than the sum of the masses of the constituent nucleons. Reason (R) : Energy is absorbed when the nucleons are bound together to form a nucleus.

            • Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
            • Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
            • Assertion (A) is true, but Reason (R) is false.
            • Both Assertion (A) and Reason (R) are false.

          • 4.
            If both the number of protons and the neutrons are conserved in each nuclear reaction, in what way is mass converted into energy (or vice versa) in a nuclear reaction? Explain.


              • 5.
                Assertion (A) : All atoms have a net magnetic moment. Reason (R) : A current loop does not always behave as a magnetic dipole.

                  • Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
                  • Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
                  • Assertion (A) is true, but Reason (R) is false.
                  • Both Assertion (A) and Reason (R) are false.

                • 6.
                  Photoemission of electrons occurs from a metal (\( \phi_0 = 1.96 \, \text{eV} \)) when light of frequency \( 6.4 \times 10^{14} \, \text{Hz} \) is incident on it. Calculate: Energy of a photon in the incident light, The maximum kinetic energy of the emitted electrons, and The stopping potential.

                    CBSE CLASS XII Previous Year Papers

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