What are the advantages of a potentiometer?

Potentiometer works on the method of zero deflection so that the possibility of error is extremely small. It is a highly sensitive device, therefore it can measure small EMFs.

  • A standard cell can be used to standardize a potentiometer. 
  • As per the requirement, the length of the potentiometer can be increased in order to get an accurate value.
  • The potentiometer does not draw any current from the circuit in which it is used.

Related Questions

  1. What is a DC Potentiometer?
  2. Is a potentiometer analog or digital?
  3. What is balance point in potentiometer?
  4. How does a potentiometer measure EMF?
  5. Which Metal Is Used In Potentiometer?
  6. State the Working Principle of a Potentiometer.
  7. Why High Resistance Is Used In Potentiometer?
  8. Sensitivity of potentiometer can be increased by__________.
  9. What are the two faults in a potentiometer if the balance point is not obtained?

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CBSE CLASS XII Related Questions

  • 1.
    An astronomical telescope consists of two converging lenses. One of them of large aperture and large focal length is called objective lens and the other one, of smaller focal length and smaller aperture is called the eyepiece. It is used to see distant objects which are not seen clearly with naked eyes. The image formed by the objective lens acts as an object for the eyepiece and the final image produced by the eyepiece is magnified.


      • 2.
        Derive an expression for the capacitance of a parallel plate capacitor of plate area A and plate separation d with air present between the plates.


          • 3.
            Consider a cylindrical conductor of length \( l \) and area of cross-section \( A \). Current \( I \) is maintained in the conductor and electrons drift with velocity \( \vec{v}_d \, (|\vec{v}_d| = \frac{eE}{m} \tau) \), where symbols have their usual meanings. Show that the conductivity of the material of the conductor is given by \[ \sigma = \frac{n e^2 \tau}{m}. \]


              • 4.
                A charged particle $+q$ in an electric field $\vec{E}$ experiences a force in the direction of the electric field. As a result, its kinetic energy changes. Similarly, the charged particle also experiences a force when it moves in a magnetic field $\vec{B}$. But this magnetic force is perpendicular to both velocity $\vec{v}$ of the charged particle and the magnetic field $\vec{B}$, so it cannot change the kinetic energy of the charged particle. Consider two charged particles 1 and 2 of masses $m$ and $\frac{m}{2}$ having charges $-q$ and $+2q$ respectively. They are accelerated from rest through the same potential difference $V$ and acquire kinetic energy $K_1$ and $K_2$. Then they enter in a region of uniform magnetic field $\vec{B}$ perpendicular to their velocities.


                  • 5.
                    An electric field $\vec{E}$ is established across the ends of a cylindrical conductor of length L and area of cross-section A. Discuss how electrons attain an average velocity, independent of time. Hence, obtain a relation between current in the conductor and this ‘average velocity’ of electrons.


                      • 6.
                        Two air-filled capacitors of capacitances $C_1$ and $C_2$ are connected in parallel with a dc battery. After the capacitors are fully charged, a slab of dielectric constant K is inserted between the plates of each capacitor. How will the (i) charge on each capacitor and (ii) energy stored in the capacitor affected after the slab is introduced.

                          CBSE CLASS XII Previous Year Papers

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