What is the relation between drift velocity and electric field?

Mobility m is defined as the magnitude of drift velocity per unit of an electric field. Therefore, 

m = |Vd|/E = qt/m

The SI unit used to represent mobility is m2/Vs. It is a positive quantity.

Vd = mE

This is the relation between the drift velocity of an electron and the applied electric field.

Drift velocity varies with the electric field intensity and is given by the formula \(\begin{array}{l}V_{d}\propto E\end{array}\)


Related Questions

  1. Give two examples of drift velocity.
  2. What Are Two Kinds Of Electricity?
  3. Why Potentiometer Is Preferred Over Voltmeter?
  4. Two conducting wires X and Y of the same diameter but different materials are joined in series across a battery. If the number density of electrons in X is twice that in Y, find the ratio of the drift velocity of electrons in the two wires.
  5. It is known that the drift velocity of electrons is only a few mm/s for a current of a few amperes. How is it possible that a current is established almost instantaneously when a circuit is closed? For example, a bulb glows as soon as the connection is switched on. Explain.

Read More:

CBSE CLASS XII Related Questions

  • 1.
    A wire of length \(L\) is bent round into (i) a square coil having \(N\) turns and (ii) a circular coil having \(N\) turns. The coil in both cases is free to turn about a vertical axis coinciding with the plane of the coil, in a uniform, horizontal magnetic field and carry the same currents. Find the ratio of the maximum value of the torque acting on the square coil to that on the circular coil.


      • 2.

        A magnet held vertically, with its north pole down, is dropped along the axis of a closed solenoid placed vertically on a table. If the observer looks down from the top,

          • the induced current will flow in the anticlockwise direction.
          • the induced current will flow in the clockwise direction.
          • no induced current will flow in the solenoid.
          • the magnet will fall with a constant velocity.

        • 3.
          Two point charges -Q and Q are located at points (d, 0) and (0, d) respectively, in x-y plane. The electric field E at the origin will be:

            • \(\frac{1}{4\pi\epsilon_0} \frac{\sqrt{2}Q}{d^2} (\hat{i} - \hat{j})\)
            • \(\frac{1}{4\pi\epsilon_0} \frac{\sqrt{2}Q}{d^2} (-\hat{i} - \hat{j})\)
            • \(\frac{1}{4\pi\epsilon_0} \frac{Q}{d^2} (\hat{i} - \hat{j})\)
            • \(\frac{1}{4\pi\epsilon_0} \frac{Q}{d^2} (-\hat{i} - \hat{j})\)

          • 4.

            A ray of light MN is incident normally on the face corresponding with side AB of a prism with an isosceles right-angled triangular base ABC. Trace the path of the ray as it passes through the prism when the refractive index of the prism material is (i) $\sqrt{2}$, and (ii) $\sqrt{3}$.


              • 5.

                A rectangular loop of size 5 cm $\times$ 8 cm is lying in the $x$-$y$ plane in a uniform magnetic field $\vec{B} = (2.0\ \text{T})\hat{k}$. The total magnetic flux linked with the loop is:

                  • 80 Wb
                  • 16 Wb
                  • \(8 \times 10^{-2}\) Wb
                  • \(8 \times 10^{-3}\) Wb

                • 6.

                  A square loop of side 0.50 m is placed in a uniform magnetic field of 0.4 T perpendicular to the plane of the loop. The loop is rotated through an angle of $60^\circ$ in 0.2 s. The value of emf induced in the loop will be:

                    • 5 V
                    • 3.5 V
                    • 2.5 V
                    • Zero V
                  CBSE CLASS XII Previous Year Papers

                  Comments


                  No Comments To Show