Two conducting wires X and Y of the same diameter but different materials are joined in series across a battery. If the number density of electrons in X is twice that in Y, find the ratio of the drift velocity of electrons in the two wires.

In the series arrangement, the current remains the same – 

\(i_x = i_y\)

For the same diameter, the cross-sectional area will remain the same.

Therefore, \(\begin{array}{l}n_{x} eAv_{x} = n_{y}eAv_{y}\end{array}\)

\(= \begin{array}{l} \frac{v_{x}}{v_{y}} \end{array}\)

\(=\begin{array}{l} \frac{n_{y}}{2n_{y}}\end{array}\)

= 1/2

Therefore, \(\begin{array}{l}v_{x} : v_{y} = 1:2\end{array}\)

Read More: Drift Velocity


Related Questions

  1. Define: 1 volt, Potential difference.
  2. What Are Two Kinds Of Electricity?
  3. Write Two Differences Between Emf And Potential Difference.
  4. Why Potentiometer Is Preferred Over Voltmeter?
  5. In a Potentiometer Arrangement, a Cell of Emf 1.25 v Gives a Balance Point at 35 cm Length of the Wire. If the Cell Is Replaced by Another Cell, the Balance Point Shifts to 63 cm, Then Emf of the Second Cell Is?

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                    CBSE CLASS XII Previous Year Papers

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