Two conducting wires X and Y of the same diameter but different materials are joined in series across a battery. If the number density of electrons in X is twice that in Y, find the ratio of the drift velocity of electrons in the two wires.

In the series arrangement, the current remains the same – 

\(i_x = i_y\)

For the same diameter, the cross-sectional area will remain the same.

Therefore, \(\begin{array}{l}n_{x} eAv_{x} = n_{y}eAv_{y}\end{array}\)

\(= \begin{array}{l} \frac{v_{x}}{v_{y}} \end{array}\)

\(=\begin{array}{l} \frac{n_{y}}{2n_{y}}\end{array}\)

= 1/2

Therefore, \(\begin{array}{l}v_{x} : v_{y} = 1:2\end{array}\)

Read More: Drift Velocity


Related Questions

  1. Define: 1 volt, Potential difference.
  2. What Are Two Kinds Of Electricity?
  3. Write Two Differences Between Emf And Potential Difference.
  4. Why Potentiometer Is Preferred Over Voltmeter?
  5. In a Potentiometer Arrangement, a Cell of Emf 1.25 v Gives a Balance Point at 35 cm Length of the Wire. If the Cell Is Replaced by Another Cell, the Balance Point Shifts to 63 cm, Then Emf of the Second Cell Is?

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CBSE CLASS XII Related Questions

  • 1.
    In a region, the electric potential varies as \(V = 10 - 50x\), where \(V\) is in volts and \(x\) is in meters. The electric field in the region is

      • \(10\ \text{N/C}\) along \(+x\)
      • \(10\ \text{N/C}\) along \(-x\)
      • \(50\ \text{N/C}\) along \(+x\)
      • \(50\ \text{N/C}\) along \(-x\)

    • 2.
      A current of \(4.0\,\text{A}\) flows through a wire of length \(1\,\text{m}\) and cross-sectional area \(1.0\,\text{mm}^2\), when a potential difference of \(2\,\text{V}\) is applied across its ends. Calculate the resistivity of the material of the wire.


        • 3.

          The number of free electrons per unit volume ($\text{m}^3$) in a wire made of copper (resistivity $1.72 \times 10^{-8}\,\Omega\,\text{m}$) is $8.5 \times 10^{28}$. Calculate the average number of collisions made by an electron in one second when an electric field is maintained in the wire.


            • 4.

              A magnet held vertically, with its north pole down, is dropped along the axis of a closed solenoid placed vertically on a table. If the observer looks down from the top,

                • the induced current will flow in the anticlockwise direction.
                • the induced current will flow in the clockwise direction.
                • no induced current will flow in the solenoid.
                • the magnet will fall with a constant velocity.

              • 5.
                Two point charges -Q and Q are located at points (d, 0) and (0, d) respectively, in x-y plane. The electric field E at the origin will be:

                  • \(\frac{1}{4\pi\epsilon_0} \frac{\sqrt{2}Q}{d^2} (\hat{i} - \hat{j})\)
                  • \(\frac{1}{4\pi\epsilon_0} \frac{\sqrt{2}Q}{d^2} (-\hat{i} - \hat{j})\)
                  • \(\frac{1}{4\pi\epsilon_0} \frac{Q}{d^2} (\hat{i} - \hat{j})\)
                  • \(\frac{1}{4\pi\epsilon_0} \frac{Q}{d^2} (-\hat{i} - \hat{j})\)

                • 6.

                  A square loop of side 0.50 m is placed in a uniform magnetic field of 0.4 T perpendicular to the plane of the loop. The loop is rotated through an angle of $60^\circ$ in 0.2 s. The value of emf induced in the loop will be:

                    • 5 V
                    • 3.5 V
                    • 2.5 V
                    • Zero V
                  CBSE CLASS XII Previous Year Papers

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