When Wheatstone bridge is in a balanced condition, current via the galvanometer will be

Assuming that the bridge is in a balanced condition, there will be no current flow via the galvanometer due to the fact that the potential difference between the two ends of the galvanometer becomes the same.

Wheatstone Bridge

Wheatstone Bridge


Related Questions

  1. Can you find very high resistance accurately with the help of a Metre bridge?
  2. Why Carey Foster Bridge Is So Sensitive?
  3. Meter Bridge or Slide Wire Bridge is a practical form of?
  4. Meter bridge works on the principle of?
  5. Why should we get the null point in the middle of the Metre bridge wire?
  6. How does a bridge circuit work?
  7. How do you solve an unbalanced bridge?
  8. Why is Wheatstone's bridge more accurate?
  9. What Is Null Voltage?

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CBSE CLASS XII Related Questions

  • 1.
    Photoemission of electrons occurs from a metal (\( \phi_0 = 1.96 \, \text{eV} \)) when light of frequency \( 6.4 \times 10^{14} \, \text{Hz} \) is incident on it. Calculate: Energy of a photon in the incident light, The maximum kinetic energy of the emitted electrons, and The stopping potential.


      • 2.
        Draw a circuit diagram of a full-wave rectifier using p-n junction diodes. Explain its working and show the input-output waveforms.


          • 3.
            If Bohr’s quantization postulate (angular momentum \( = \frac{nh}{2\pi} \)) is a basic law of nature, it should be equally valid for the case of planetary motion also. Why, then, do we never speak of quantization of orbits of planets around the Sun? Explain.


              • 4.
                The figure shows three point charges kept at the vertices of triangle ABC. The net electric field, due to this system of charges, at the midpoint M of base BC will be:

                  • \( \frac{q}{4 \pi \epsilon_0 l^2} \) pointing along MA
                  • \( \frac{q}{\pi \epsilon_0 l^2} \) pointing along AM
                  • \( \frac{q}{2 \pi \epsilon_0 l^2} \) pointing along AM
                  • Zero

                • 5.
                  A light copper ring is freely suspended by a light string. A bar magnet is held horizontally with its length along the axis of the ring. The magnet is moved towards the ring with its N pole facing the loop. What will happen to the ring and its position? Explain.


                    • 6.
                      Four independent waves are expressed as \[ (i)\; y_1=A_1\sin\omega t, \] \[ (ii)\; y_2=A_2\sin 2\omega t, \] \[ (iii)\; y_3=A_3\cos\omega t, \] \[ (iv)\; y_4=A_4\sin\left(\omega t+\frac{\pi}{3}\right) \] The interference between two of these waves is possible in

                        • (i) and (iii) only
                        • (iii) and (iv) only
                        • (i), (iii) and (iv) only
                        • All of them
                      CBSE CLASS XII Previous Year Papers

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