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When a capacitor is connected to an ac source, an interesting relationship is generated by the curve formed by the voltage and the current. Meaning, when voltage is zero, the current is maximum and again, when voltage is maximum, the current becomes zero. Here, we have a capacitor and an AC voltage V which is represented by “~” and which produces a potential difference across its terminals that changes sinusoidally.
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Key Terms: AC Voltage, Kirchhoff’s rule, AC Biasing, RLC Circuit, Capacitor, Electrical circuit, Volatge, Current
AC Voltage Applied to a Capacitor
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The unit deals with an electrical circuit where an AC Voltage is used in an AC Capacitor. If we consider the electrical circuit then the equation will show the result. Let us consider a capacitor and an AC Voltage V represented by the symbol ---. It produces a difference across its terminal which varies in its way. The equation stands like this:-
V= vmsinwt
In this equation, vm stands for the amplitude of the oscillating difference.
The angular frequency is symbolized w.
The current passes through the resistor which is the result of the present voltage source. We can calculate the same by using Kirchhoff’s rule.
∑V (t) = 0
The conductors are separated by the mediums which we call capacitors. In this unit, we will deal with how a capacitor works when ac is passed through it. We will understand the electrical circuit with an ac capacitor and will get the results after measuring all the possibilities.
The video below explains this:
AC Voltage Applied to a Capacitor Detailed Video Explanation:
The capacitor in an AC Circuit
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If the AC Conductor is connected to a DC Source then the current will not flow through it and if we connect the lamp with the circuit the lamp will not light up. The current stops flowing through the capacitor. If the capacitor has an insulating medium between the plates then the current flow will be restricted. But instead of a DC Source if an AC Source is connected to the capacitor and then the lamp is connected to the circuit then the lamp will light up. The dimension of the capacitor is the same as ohm (Ω). Ohm works exactly like a resistance which restricts the flow of the electricity through the capacitor. But if the frequency and the capacity of the capacitor are compared then they have an inverse relation.
If we connect the DC Source to a capacitor then it charges. But after charging neither the current will flow from the capacitor nor will the lamp glow. If we reduce the C then also it will remain affectless. But the result will be the lamp will light up. The reactance increases if the C is reduced and therefore the lamp lights up and glows.
Highlights of AC Biasing
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When one thinks about DC the major concern that arises is why the current is restricted to flow in the DC Connected areas and the current easily reaches the AC Source. The below-mentioned equation will explain such:-
V= Q*C*V=CQ
Within a short period the lamp will light up but after some time the current will be restricted and the current will not flow. When an AC Source is concerned the voltage is altered and it gets charged but the capacitor does not charge. When the capacitor gets charged this is across the plate the capacitor rises and charges. It also has a vice-versa relationship.
If the voltage rises in a reverse direction then the capacitor gets charged in an alternate direction and the plates which were positively charged before will become negatively charged at the moment or vice-versa. The charge of the plates can also come down to zero in this situation. The whole theory is explained through an equation-
Q= C/times
VQ= C*V
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Mathematical Expressions
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The current flow of AC is:
i=DQ/DT
Now altering the voltage applied to a capacitor is
V = Vmsin (w*t)
When Vm= amplitude of voltage and w= angular frequency. Charge Q on the capacitor is
Q= C*V
Therefore, one can write
Q= C*Vm*sin (w*t)
Maximum Current
Sin(w*t+2π)
AC Voltage Applied to LCR Circuit Series
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To determine the instant current ‘I’ and the relation with the phase if it is applied to the alternate voltage v, two methods are used to determine such. The first method is the phasors technique and the second one is the analytical method where one needs to depend on ‘I’. Here, we have obtained the amplitude and phase of current that we can use for an LCR series circuit using the phasors technique. But the method of analyzing ac circuits has disadvantages. But the first method is silent about the initial condition. To justify the method, the arbitrary value of t (say t1) is considered and the different phasors are drawn which will reflect the relative angle between the different types of phasors. The solution of the analysis is called the steady-state solution. Moreover, a transient solution is there if v=0. The normal solution is the aggregation of transient and steady-state solutions. But the method used does not have a general solution. After a long time, the transient effect dies out and the circuit performance is called the steady-state solution.
Resonance
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RLC Circuit has an interesting character called the phenomenon of resonance. The phenomenon of resonance is common among systems that have a oscillate tendency at a particular frequency. This frequency is known as the system's natural frequency. If this system is driven by an energy source at a natural frequency, the amplitude of oscillation is very large. One can consider the example of the child using a swing. The natural frequency of the swing and its movement proves the resonance concept. The regular interval of swing and the natural frequency of the swing will determine the final result. If the frequency and the pull come at the same pace then the amplitude of the swing will be more and will determine the final result. The resonance frequency can be described by the equation XL=wL. So, here if w varies, the impedance also varies. Eg- if at w0 Xl=Xc, then the impedance becomes minimum.
Things to Remember
- The unit deals with an electrical circuit where an AC Voltage is used in an AC Capacitor.
- When one thinks about DC the major concern that arises is why the current is restricted to flow in the DC Connected areas and the current easily reaches the AC Source.
- The angular frequency is symbolized w.
- The current passes through the resistor which is the result of the present voltage source. We can calculate the same by using Kirchhoff’s rule. ∑V (t) = 0
- To determine the instant current ‘I’ and the relation with the phase if it is applied to the alternate voltage v, two methods are used.
- RLC Circuit has an interesting character called the phenomenon of resonance.
- The regular interval of swing and the natural frequency of the swing will determine the final result.
Also Read:
Sample Questions
Ques. A reactive element in an AC circuit causes the current flowing
(i) to lead in phase by Π/2 and
(ii) to lag in phase by Π/2 with respect to the applied voltage. Identify the element in each case. (Delhi 2010C)
Ans.
- In the case of a pure capacitive circuit, the current leads in phase by Π/2 with respect to the voltage applied. Therefore, the element will be a capacitor.
- In case of the pure inductive circuit, the current lags in phase by Π/2 with respect to the voltage applied. Thus, the element will be an inductor.
Ques. What is capacitive reactance and write its S.I. unit. (Delhi 2015)
Ans. The resistance offered by the capacitor when connected to an electric circuit is known as the capacitive reactance.
It is represented by,

Where, ω = the angular frequency of the source and C = the capacitance of the capacitor.
The S.I. unit of capacitive reactance is ohm.
Ques. Plot a graph that shows variation of capacitive reactance with the change in the frequency of the AC source. (All India 2015C)
Ans. The graph showing variation of capacitive reactance with the change in the frequency of the AC source,

Where, XC = the capacitive reactance and v = the frequency in an ac circuit.
Ques. What will be the result if the capacitor is connected to the AC? (1 mark)
Ans. If the Capacitor is fully charged then it will not allow the flow of the current due to the electrons. Therefore the method of alternating current usage is used wherein the capacitor is not fully charged and determines the frequency of the current flow.
Ques. What are capacitors- AC or DC? (1 mark)
Ans. General Capacitors are marked- Ac is marked as AC and DC are marked as DC. The positive and the negative poles are marked as DC Circuits and the others without positive and negative poles are AC Circuits.
Ques. What is the maximum voltage of a capacitor? (1 mark)
Ans. Every capacitor has its voltage capacity limit. If the capacitor exceeds its range of capacity it will explode. The maximum voltage can be 100V. But the terminals of the capacitor will have little resistance.
Ques. A capacitor C, a variable resistor R and a bulb B are connected to a series in the circuit to the AC mains as shown in the figure below. The bulb glows with some brightness. How will that glow of bulb change if (i) a dielectric slab is introduced between the plates of the capacitor with resistance R to be the same and (ii) the resistance R is increased with the same capacitance. (Delhi 2014)

Ans. (i) As the dielectric slab is introduced between the plates of the capacitor, its capacitance will increase. Along with that, the potential drop across the capacitor will decrease, i.e., V = Q/C. Consequently, the potential drop across the bulb will increase as they are connected in series. Thus, its brightness will increase.
(ii) As the resistance R is increased, the potential drop across the resistor will increase. Consequently, the potential drop across the bulb will decrease as they are connected in series. Therefore, its brightness will decrease.
Ques. In an AC circuit, show that the current leads the voltage in phase by Π/2 containing an ideal capacitor. (Foreign 2014)
Ans. Let us assume that a capacitor C connected to an AC source as shown in the figure below,

Considering the AC voltage applied be,
V = Vm sin ωt
Thus, V = q/c
By applying Kirchhoff’s loop rule, we have

We know that, cos ωt = sin ωt + Π/2 … (ii)
In the circuit,

The phase diagram that shows the current lead the voltage in phase by 90° is given below,

Ques. An AC voltage, V = V0 sin ωt is applied across a pure capacitor C. Derive an expression for the current I in the circuit and hence obtain the
capacitive reactance of the circuit and
the phase of the current flowing with respect to the applied voltage. (All India 2010)
Ans. Given is the alternating current voltage, V = V0 sin ωt is applied across a capacitor C. The potential difference across the capacitor is equal to the applied voltage at any instant.

Where, V is the potential difference across the capacitor q/c.
q = CV
Or, q = CV0 sin ωt
Thus, dq/dt = ω C V0 cos ωt

(ii) From the equations (i) and (ii), current leads the voltage by Π/2.

Ques. A lamp is connected in series with a capacitor. Predict your observation when this combination is connected in turn across (i) ac source as well as (ii) a dc battery. If the capacitor of the capacitance is reduced, what change would you notice in each case? (Delhi 2012C)
Ans. (i) When ac source is connected, the capacitive reactance offered by the capacitor is XC = 1/ ωC. The current flows in the circuit and the lamp glows. And on reducing C, XC increases due to which the glow of the bulb reduces.
(ii) When dc is connected, the condenser is charged but no current flows in the circuit for which the lamp does not glow. Even when the capacitance of the capacitor is reduced, no change takes place.
Previous Year Questions
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