If R, C and L are fundamental quantities in a circuit like resistance, capacitance and inductance in W, then find dimensional formula for resistance and capacitance.

Dimensional analysis can be defined as the practice of studying relations between physical quantities by recognising the dimensions of them. These dimensions are independent of numerical multiples and similar constants. The quantities present in the world can be described as a function of the fundamental dimensions.

Dimensional Formula

Dimensional formula of a quantity is the expression indicating the powers wherein the fundamental units are to be increased to obtain one unit of a derived quantity. For instance, if Q is an unit of a derived quantity which is defined by Q = MaLbTc, then MaLbTc is known as the dimensional formula with exponents a, b and, c that are called the dimensions.

Dimensional Formula for Resistance

The dimensional formula of resistance can be expressed as:

M1 L2 T-3 I-2

Here,

  • M = Mass
  • I = Current
  • L = Length
  • T = Time

Resistance (R) = Voltage × Current-1 … [1]

Now, because, Voltage (V) = Electric Field × Distance = [Force × Charge-1] × Distance

Accordingly, dimensional formula of charge = current × time = I1 T1

Dimensional formula of voltage = [Force × Charge-1] × Distance

= [M1 L1 T-2] × [I1 T1]-1 × [L1]

= [M1 L2 T-3 I-1] … [2]

On replacing equation (ii) in equation (i) we get,

Resistance (R) = Voltage × Current-1

R = [M1 L2 T-3 I-1] × [I]-1 = [M1 L2 T-3 I-2]

Hence, resistance is dimensionally depicted as M L2 T-3 I-2.

Dimensional Formula of Capacitance

The dimensional formula of Capacitance is expressed by:

M-1 L-2 T4 I2

Here,

  • M = Mass
  • I = Current
  • L = Length
  • T = Time

Derivation of Capacitance

Capacitance (C) = Charge × Voltage-1 . . . [1]

Since, Charge = Current × Time

∴ Therefore, the dimensional formula of charge can be give as = [I1 T1] . . . . [2]

And, Voltage = Electric Field × Distance . . [3]

Now, as per Electric Field,

Electric Field = [Force × Charge-1]

Hence, dimensional formula of force and charge equals [M1 L1 T-2] and [I1 T1] respectively.

∴ The dimensional formula of Electric Field = [M1 L1 T-2] × [I1 T1]-1

= [M1 L1 T-3 I-1] . . . [4]

On replacing equation [4] in equation [3] we can obtain,

The dimensional formula of Voltage = [M1 L1 T-3 I-1] × [L1]

= [M1 L2 T-3 I-1] . . . [5]

On replacing equations [5] and [2] in equation [1] we can obtain,

Hence, Capacitance = Charge × Voltage-1

Or, as can be expressed, C = [I1 T1] × [M1 L2 T-3 I-1]-1 = [M-1 L-2 T4 I2]

Thus, the Capacitance can be dimensionally expressed as [M-1 L-2 T4 I2].


Related Questions

  1. In An Arrangement Of Resistances, Find Effective Resistance Between Points A and B.
  2. What Is Effective Resistance?
  3. X and Y, which are two resistors, with resistances of 2 Ω and 3 Ω respectively are first connected in parallel and then in series. In both cases, the voltage that is supplied is 5 V. (i) Illustrate a circuit diagram to show the combination of resistors. (ii) Calculate the amount of voltage across 3 Ω resistor in the series combination of resistors.
  4. Find The Highest And Lowest Total Resistance Of A Combination Of Four Coils With Resistances 4 Ohms, 8 Ohms, 12 Ohms, 24 Ohms.
  5. What is Null Voltage?
  6. Draw An Electric Circuit With A Cell, Key, Ammeter, A Resistor (Series) Of 2 Ohm With a Combination Of Two Resistors (4 Ohm Each) In Parallel And A Voltmeter Across Parallel Combination.

Do Check Also:

CBSE CLASS XII Related Questions

  • 1.
    Read the following paragraph and answer the questions that follow.
    A p-type or n-type semiconductor can be converted into a p-n junction by doping it with suitable impurity. The motion of majority charge carriers causes diffusion current across the junction while the barrier electric field causes motion of minority carriers for drift current. In case of unbiased diode, the diffusion and drift currents are equal. This equilibrium is disturbed by the biasing batteries. Diodes, therefore, allow currents in one direction. This property of diode is used in making rectifiers.


      • 2.
        A charged particle $+q$ in an electric field $\vec{E}$ experiences a force in the direction of the electric field. As a result, its kinetic energy changes. Similarly, the charged particle also experiences a force when it moves in a magnetic field $\vec{B}$. But this magnetic force is perpendicular to both velocity $\vec{v}$ of the charged particle and the magnetic field $\vec{B}$, so it cannot change the kinetic energy of the charged particle. Consider two charged particles 1 and 2 of masses $m$ and $\frac{m}{2}$ having charges $-q$ and $+2q$ respectively. They are accelerated from rest through the same potential difference $V$ and acquire kinetic energy $K_1$ and $K_2$. Then they enter in a region of uniform magnetic field $\vec{B}$ perpendicular to their velocities.


          • 3.
            Two metal spheres of radii $r_1$ and $r_2$ ($> r_1$) having charges $q_1$ and $q_2$ respectively kept in air, are brought in contact. Which of the following statements is not correct ?

              • The total charge of the two spheres is conserved.
              • Both spheres attain the same potential.
              • The final potential of the system equals $\frac{1}{4\pi\epsilon_0} \frac{(q_1 + q_2)}{(r_1 + r_2)}$
              • The final potential of the system equals $\frac{1}{4\pi\epsilon_0} \frac{(q_1 + q_2) (r_1 + r_2)}{r_1 r_2}$

            • 4.
              Consider the nuclear reaction \( X \to Y + Z \). Let \( M_x \), \( M_y \), and \( M_z \) be the masses of the three nuclei X, Y, and Z respectively. Then which of the following relations hold true?

                • \( (M_x - M_z)<M_y \)
                • \( (M_x - M_y)<M_z \)
                • \( M_x>(M_y + M_z) \)
                • \( M_x<(M_y + M_z) \)

              • 5.
                The resistance of a metal wire at \( 20^\circ \text{C} \) is \( 1.05 \, \Omega \) and at \( 100^\circ \text{C} \) is \( 1.38 \, \Omega \). Determine the temperature coefficient of resistivity of this metal.


                  • 6.
                    Read the following paragraph and answer the questions that follow.
                    In an experiment with convex lens of focal length f, the screen is fixed at a distance D from the object. A student slowly moves the lens away from the object towards the screen and finds that she is able to form sharp image of the object for two positions of the lens. The distance between these two positions of the lens is d.

                      CBSE CLASS XII Previous Year Papers

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