Find the highest and lowest total resistance of a combination of four coils with resistances 4 ohms, 8 ohms, 12 ohms, 24 ohms.

According to the question, there are four coils of resistances = 4 Ω, 8 Ω, 12 Ω and 24 Ω

1. Given that the coils are connected in series, then equivalent resistance will have to be highest:

⇒ 4 + 8 + 12 + 24 = 48 Ω

2. Given that the coils are connected in parallel, then equivalent resistance will have to be the lowest:

⇒ 1/R = 1/4 + 1/8 + 1/12 + 1/24

= 1/2

Therefore, R = 2 ohms can be expressed as the least value of resistance which can be obtained from the above 4 resistor combinations.

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