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Logistic Function is a model of the exponential growth of the population. It is a part of an exponential function that also considers the carrying capacity of the land.
- Logistic Function involves limiting the growth of the population.
- It is also known as the logistics curve.
- The function will form a S-shaped curve with respect to the equation.
- The initial curve will show geometric growth followed by a saturation point.
- Later, growth begins to slow arithmetically and stops when it reaches the saturation point.
- Neural networks and logistic regression are some common examples of logistic functions.
- Mathematically, it can be represented as:

Key Terms: Logistic function, Sigmoid function, Exponential function, Function, Differential equation, Saturation Point, Logarithm, Population, Differential Equation
What is Logistic Function?
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Logistic Function is a form of model that explains the exponential growth of population which also take into consideration the carrying capacity of land.
- It is an exponential function that considers definite areas will not have unlimited growth.
- When one population grows, the available resources decrease.
- It consist of inflection point where curve changes from up or down to sloping down or up.
- These are also known as concave upward or concave downward curve.
- One of the important feature includes it is the output of sigmoid function.
- It is used in the field of statistics, ecology, medicine and agriculture.
- The concept was introduced by Pierre Francois Verhulst.
Example of What is Logistic Function?Example 1: Logistic Function is used in the field of growth of tumors. Example 2: It is used in the field of agriculture to model crop response. Example 3: Find the logistic model with the given values. c=12, and points are (0,10) , (1,11). Ans: The above given two points provide two equations. Use these given values of points to solve for a and b. 10 = 12/1+a.b0 1+a= 12/10 a= 1.2 11= 121+(1.2).b1 1+(1.2).b= 12/11 b= 0.075 The logistic model is: f(x)= 12/10+(1.2).(0.075)x |
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Logistic Function Equation
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The logistic function can be derived in several ways and each function arrives at the same logic. Here, we will take into account parameters that include p=1, x0 = 0 and m= 1.
Thus, the logistic function reduces as below:
\(f (x) = \frac{1}{1 + e^{-x}} = \frac{e^x}{e^x + 1} = \frac{1}{2} + \frac{1}{2} tanh (\frac{x}{2})\)Logistic Function Curve
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The logistic function also known as logistic curve will form a S-shaped curve. The curve will first increase exponentially then it will reach its saturation point. After that curve begins to decrease linearly.
- The growth will stop when the curve will reach its maturation point.
- The Logistic Curve is also known as the Sigmoid curve because of its ‘S-shaped curve.
- The exponential or logistic function in the denominator determines the speed at which a function drops or grows to its limiting value.
f (x) = \(\frac{m} {1 + e^{ – p (x – x_0)}}\)
Where,
- M = The value that is maximum of the curve
- e = the natural logarithm base
- x0 = the given value of the midpoint of sigmoid
- P = The logistic growth rate or the curve’s steepness
Logistic Curve
Interpretation of Logistic Function
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The logistic function can be interpreted as follows:
- Consider, k (t) = the population as a function of time in a number
- t0 = the starting time.
- The term (t - to) is just an adjustable horizontal translation of the logistic function.
- M = criterion that influences the rate of exponential growth
- D= the asymptote in horizontal or the limit on the population size
- The functions stand as
k(t) = \(\frac{D}{ (1+e^{-m(t-t_0))}}\)
Derivative of Logistic Function
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The derivative of logistic function can be explained as follows:
Part 1
The derivation of logistic function are as follows:
f(x) = \(\frac{1}{1+e^{-x}} = \frac{e^x}{1+e^x}\)
\(\frac{d}{d_x}\)f(x) = \(\frac{ex. (1+e^x) - e^x. e^x}{(1+e^x)^2} = \frac{e^x}{(1+e^x)^2}\) = f(x) (1 – f (x) )
- The above derivation is also known as logistic distribution.
Part 2
The logistic function is also derived from the differential equation. In this derivation, the logistic model states that the growth decreases linearly when the population increases.
- The functions are as given below:
\(\frac{dm (t)}{dt}\) = m (t) k [1 – \(\frac{m(t)}{B}\)]
Where,
- K > 0,
- B is a constant that is greater than the value of m(0).
- The equation shows the saturation of the population.
- It also expresses how the growth rate is decreasing as m(t) as it approaches B.
- However, there is a solution to the above equation:
m (t) = \(\frac{B}{1+(B/m(0)-1)e^{kt}}\)
- The above function grows as an exponential function.
- It then falls and converges to carrying capacity B which is the maximum sustainable population.
Integrals of the Logistic Function
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Consider the equation: 1- ex= p
- After applying integration function the equation is as follows:
f (x) = \(\frac{e^x}{1+e^x} = \frac{\hat{p}}{p}\)
\(\int \frac{e^x}{1+e^x}\) dx= \(\int \frac{1}{p}\) dp = log p = log (1 + ex)
Logistic Function vs Sigmoid Function
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The basic difference between Logistic Function vs Sigmoid Function is the expression or formula that clearly differentiates between the two.
- The sigmoid function is an expression of a mathematical function which is S-shaped known as the sigmoid curve.
- The logistic function is the standard choice added for a sigmoid function.
- The return value of a sigmoid function is increasing from 0 to 1.
- It also include possible values from -1 to 1 and depends on convention.
- The value depends upon the kingdom for all real numbers.
- The formula for Logistic function is given as:
f(x)= \(\frac{L}{1+e^{-k(x-x_0)}}\)
- The formula for Sigmoid Function is given as:
S(t)= \(\frac{1}{1+e^{-t}}\)
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| Class 12 Mathematics Related Concepts | ||
|---|---|---|
| Logarithm Formula | Applications of Integral | Differential Equations |
| Definite Integral | Integrals | Methods of Integration |
Things to Remember
- The logistic function is an exponential function which considers the carrying capacity of the land.
- It proves that when growth increases, the population tends to decrease.
- The growth rate declines linearly when the population increases.
- The Logistic Curve is also known as the Sigmoid curve because of its ‘S-shaped curve.
- The function is used at the time of the pandemic.
- It determines the cumulative number of infected cases.
Sample Questions
Ques. Below are the given values. Find out the value of the logistic model. c=7 and the given values of the points are (0, 2) and (3, 5). The given two points provide two different equations and the logistic model has two different variables. From these given points find the values for P and Q? (3 marks)
Ans. 2= 7/1+P;
1+P = 7/2
Thus, P = 2.5
5 = 7/ 1+ (2.5) . Q3
1+ (2.5) . Q3 =7/5
Q3= 0.16
Q ~ 0.54329
Hence, the estimated model is
f (x) = 7/ 1+ (2.5) . (0.54329) x
Ques. How many years will it take for a fungal population to reach 9000 if its growth is modeled by here
, t in years? (3 marks)
Ans: According to the given,

Taking logarithm on both sides,
- 0.12 (t - 20) = ln (0.111)
t = – ln (0.111) / 0.12 + 20
On simplifying,
t = 38.31 years
Ques. The school population is 1200 students. A rumor is known to be spread in the school. 4 people knew about the rumor when it all started and after 3 days, 300 people knew about the rumor. So how many people get to know about the rumor on the fourth day? (3 marks)
Ans. The population given is 1200 so it is the carrying capacity.
So, c=1200; (0,4); (3,300)
Let's use point (0,4) to find a.
12001+a.b0 = 4
12001+a= 4
12004= 1+a
a= 299
Now use point (3,300) to find b,
12001+299.b3= 300
4= 1+299.b3
3299= b3
0.2156 b
Therefore, x= 4;
f(x)= 12001+299.0.2156f(4) 729 people
Ques. Find the logistic model with the given values. c=12, and points are (0,9) , (1,11)? (3 marks)
Ans. The above given two points provide two equations. Use these given values of points to solve for a and b.
9= 12/1+a.b0
1+a= 12/9
a= 1.3
11= 12/1+(1.3).b1
1+(1.3).b= 12/11
b= 0.27 = 3.11
The logistic model is:
f(x)= 12/1+(1.3).(3.11)x
Ques. Find the logistic model with the given values. c=7, and points are (0,2) , (3,5)? (3 marks)
Ans. The above given two points provide two equations. Use these provided points to find the values for a and b.
2= 7/1+a
1+a= 7/2
a= 2.5
5= 7/1+(2.5).b3
1+(2.5).b3= 7/5
b3= 0.16
b 0.5429
The logistic model is:
f(x)= 7/1+(2.5).(0.5429)x
Ques. Biologists stocked a lake with 500 fish and estimated the carrying capacity as 10000. After the first year, the total number of fish got thrice more than it was before that.
Assume that the population of fish qualifies the logistic equation and find an expression about the size of fish in ‘t’ years.
How long will it take for the population to reach 4000? (4 marks)
Ans. An analytic solution is:
p(t)= k1+Ae-kt ; A= k-p0p0
p(t)= 100001+(10000-500500)e-kt
p(t)= 100001+19e-kt ; p(I)= 1500
100001+19e-k.1 = 1500
11+19e-k= 150010000
11+19e-k = 320
1+19e-k= 203
e-k= 1757
In (e-k)=In(1757)
-k= In(1757)
p(t)= 100001+19(1757)t
4000= 100001+19(1757)t
410= 11+19(1757)t
52= 1+ 19(1757)t
Multiplying both sides by 119,
119.52= 1+ 19(1757)t. 119
338= (1757)t
In338=In (1757)t
In338=t.In (1757)t
-2.538-1.209= t
Ques. Find the logistic model with the given values. c=7, and points are (0,2) , (3,5) c=6, and points are (0,5) , (2,5)? (3 marks)
Ans. The above given two points provide two equations. Use the above given points to find the values for a and b.
5= 6/1+a
1+a= 6/5
a= 0.05
5= 6/1+(0.05).b2
1+(0.05).b2= 6/5
b2= 0.16
b 0.4
The logistic model is:
f(x)= 6/1+(0.05).(0.4)x
Ques. If t = 0 there is one person in a community of 1,000 people who have the flu. There is an estimate that almost 1,000 people in the same community can have the flu. According to the researchers, logistic growth b= 0.6030 is constant. Find the estimated number of persons who can catch the flu after 10 days and predict the number of people in the community who caught this flu after a long time? (3 marks)
Ans. We substitute the given data into the logistic growth model
\(f(x)= \frac{k}{1+ae^{-bx}}\)
Since almost 1000 people have the flu, there is a chance that the entire population can catch it too. So we know the limiting value is k= 1000.
Now to find a, we can use the number of cases at a particular time t= 0.
\(\frac{k}{1+a}=1\)
So, a = 999. According to this model, the estimation of people catching flu after 10 days is-
\(f(x) = \frac{1000}{1+999e^{-0.603x}} \approx 293.8\)
Since the real number can only be a whole number( either a person can catch the flu or not) so after rounding the figure to 294. In the long run, people who will contract the flu is the limiting value, that is, k = 1000.
Ques. Show that if f : A → B and g : B → C are one-one, then gof : A → C is also one-one? (3 marks)
Ans. Suppose gof(x1 ) = gof(x2 )
⇒ g (f(x1 )) = g(f (x2 ))
⇒ f(x1 ) = f(x2 ), as g is one-one
⇒ x1 = x2 , since f is given as one-one so gif is also one-one.
Ques. Let f : N → Y be a function defined as f(x) = 4x + 3, where, Y = {y ∈ N: y = 4x + 3 for some x ∈ N}. Show that f is invertible. Find the inverse? (3 marks)
Ans. Consider an arbitrary element y of Y. As it is given in the definition of Y,
y = 4x + 3, in the domain N and for the value of x.
This shows that x= (y-3)4.
Define g : Y → N by g(y)= (y-3)4.
Now, gof(x) = g (f(x)) = g (4x + 3) = (4x+3-3)4= x.
and fog (y) = f(g (y)) = f ((y-3)4)= 4(y-3)4+3 = y – 3 + 3 = y.
Hence this proves that gof= IN and the value of fog= IY, which in turn states that f is invertible and the value of g is inverse of f.
Ques. Find the logistic model with the given values. c=10, and points are (0,8) , (1,11)? (3 marks)
Ans. The above given two points provide two equations. Use these given values of points to solve for a and b.
8= 10/1+a.b0
1+a= 10/8
a= 1.25
11= 12/1+(1.3).b1
1+(1.25).b= 12/11
b= 1.15
The logistic model is:
f(x)= 12/1+(1.25).(1.15)x
Ques. Find the logistic model with the given values. c=6, and points are (0,2) , (3,4) (3 marks)
Ans. The above given two points provide two equations. Use these provided points to find the values for a and b.
2= 6/1+a
1+a= 6/2
a= 3
4= 7/1+(2.5).b3
1+(3).b3= 7/4
b3= 0.25
b = 0.629
The logistic model is:
f(x)= 6/1+(3).(0.629)x
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