When current is drawn from a cell, the potential difference between a cell’s electrodes, when current is drawn is known as its Terminal Voltage. As per the given question, the following can be expressed:
- The E.M.F of battery = 10 V
- The internal resistance, r = 3 \(\Omega\)
- Current, I = 0.5A
- Resistance = R
According to Ohm’s law, we can obtain:
| \(I = {{E} \over (R + r)}\) |
Therefore, R = 17 \(\Omega\)
Terminal voltage of resistor = V
Now, as per what Ohm’s Law specifies,
V = I \(\times\) R
Hence, Voltage, V = 8.5 V
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