Given parameters:
- Resistance of electric lamp (R1) = 100 Ω
- Resistance of toaster (R2) = 50 Ω
- Resistance of water filter (R3) = 500 Ω
- A potential difference of the source (V) = 220 V
To find:
- The flow of electric current through the electric iron.
- Resistance of an electric iron
The three resistors are connected in parallel as shown –

All 3 resistances are connected in parallel
Solution:
1) The total resistance (R) can be calculated by –
1/R = 1/R1 + 1/R2 + 1/R3
1/R = 1/100 + 1/50 + 1/500
1/R = (5 + 10 + 1)/500
1/R = 16/500
Total Resistance (R) = 500/16 = 31.25 Ω
2) According to Ohm’s law, the current through a conductor is directly proportional to the voltage across two points of a conductor.
V = IR
Where R is constant called resistance.
R = V/I
I = 220 × (16/500)
I = 7.04 A
Therefore, the resistance of the electric iron is 31.25 Ω and the current flowing through it is 7.04 A.
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