An Electric Bulb Connected to a 220 V Power Supply Draws Current of 0 .5 A. Calculate the Power of the Bulb.

Electric power can be expressed as the rate at which work is done or energy is converted into an electric circuit. In simple words, it is the measurement of energy that is used in an interval of time.

Step 1: Formula Used

The formula of Electric Power can be expressed as,

P = VI

Here,

P = Power
V = Potential Difference
I = Electric Current

Power is also denoted as:

⇒ P = I²R
⇒ P = V²/R
The expressions above are acquired with the help of Ohm’s law, where voltage, current, and resistance are interrelated by:

V = IR

Where,

R = Resistance
V = Potential Difference
I = Electric Current

Step 2: Solution

As is given,

V = 220V
I = 0.5A

Thus, in order to find the solution, we need to determine the bulb’s power

Hence, P = VI

⇒ P = 220 x 0.5 A
⇒ P = 110 watt

Thus, the bulb’s power is 110 watts.

Related Questions:

Check Out:

Ohm’s Law: Important Topics
Types of Current	Electrical Formula	Cells, emf, Internal Resistance
Combination of Resistors	Derivation of Drift Velocity	Difference Between Primary Cell and Secondary Cell
Permittivity And Permeability	Uses of Resistor	Relation between power and resistance
Current Density	Power transformers	Internal resistance formula
Ampere	Potentiometer	Differences Between Acceleration and Velocity
Wheatstone Bridge	Resistance Formula	Difference between RTD and thermocouple
Circuit Diagram	Resistor Colour Codes	Power Of Alternating Current
Static Electricity	Electromotive Force	Current density formula
Unit of Current	Carbon Resistor	Difference between air conditioning and refrigeration
Types of Resistors	Difference between AC and DC	Relation between kva and kw
Voltage divider formula	Drift Velocity	Difference between earth and neutral
Unit of Specific Resistance	Cells in Series and in Parallel	Resistivity Temperature Dependence
Current Electricity	Meter Bridge	Relation between resistance and length
Kirchhoff’s Rules	Electric Dipole	Difference between emf and voltage
Difference between kva and kw	Resistivity formula	NCERT Solutions Current Electricity

CBSE CLASS XII Related Questions

1.
Photoemission of electrons occurs from a metal (\( \phi_0 = 1.96 \, \text{eV} \)) when light of frequency \( 6.4 \times 10^{14} \, \text{Hz} \) is incident on it. Calculate: Energy of a photon in the incident light, The maximum kinetic energy of the emitted electrons, and The stopping potential.

View Solution

2.
If Bohr’s quantization postulate (angular momentum \( = \frac{nh}{2\pi} \)) is a basic law of nature, it should be equally valid for the case of planetary motion also. Why, then, do we never speak of quantization of orbits of planets around the Sun? Explain.

View Solution

3.
If both the number of protons and the neutrons are conserved in each nuclear reaction, in what way is mass converted into energy (or vice versa) in a nuclear reaction? Explain.

View Solution

4.
Draw a circuit diagram of a full-wave rectifier using p-n junction diodes. Explain its working and show the input-output waveforms.

View Solution

5.
The figure shows three point charges kept at the vertices of triangle ABC. The net electric field, due to this system of charges, at the midpoint M of base BC will be:

\( \frac{q}{4 \pi \epsilon_0 l^2} \) pointing along MA
\( \frac{q}{\pi \epsilon_0 l^2} \) pointing along AM
\( \frac{q}{2 \pi \epsilon_0 l^2} \) pointing along AM
Zero

View Solution

6.
A square loop of side 0.50 m is placed in a uniform magnetic field of 0.4 T perpendicular to the plane of the loop. The loop is rotated through an angle of 60° in 0.2 s. The value of emf induced in the loop will be:

5 V
3.5 V
2.5 V
Zero V

View Solution

An Electric Bulb Connected to a 220 V Power Supply Draws Current of 0 .5 A. Calculate the Power of the Bulb.

Step 1: Formula Used

Step 2: Solution

CBSE CLASS XII Related Questions

1.
Photoemission of electrons occurs from a metal (\( \phi_0 = 1.96 \, \text{eV} \)) when light of frequency \( 6.4 \times 10^{14} \, \text{Hz} \) is incident on it. Calculate: Energy of a photon in the incident light, The maximum kinetic energy of the emitted electrons, and The stopping potential.

2.
If Bohr’s quantization postulate (angular momentum \( = \frac{nh}{2\pi} \)) is a basic law of nature, it should be equally valid for the case of planetary motion also. Why, then, do we never speak of quantization of orbits of planets around the Sun? Explain.

3.
If both the number of protons and the neutrons are conserved in each nuclear reaction, in what way is mass converted into energy (or vice versa) in a nuclear reaction? Explain.

4.
Draw a circuit diagram of a full-wave rectifier using p-n junction diodes. Explain its working and show the input-output waveforms.

5.
The figure shows three point charges kept at the vertices of triangle ABC. The net electric field, due to this system of charges, at the midpoint M of base BC will be:

6.
A square loop of side 0.50 m is placed in a uniform magnetic field of 0.4 T perpendicular to the plane of the loop. The loop is rotated through an angle of 60° in 0.2 s. The value of emf induced in the loop will be:

Similar Physics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

An Electric Bulb Connected to a 220 V Power Supply Draws Current of 0 .5 A. Calculate the Power of the Bulb.

Step 1: Formula Used

Step 2: Solution

CBSE CLASS XII Related Questions

1.Photoemission of electrons occurs from a metal (\( \phi_0 = 1.96 \, \text{eV} \)) when light of frequency \( 6.4 \times 10^{14} \, \text{Hz} \) is incident on it. Calculate: Energy of a photon in the incident light, The maximum kinetic energy of the emitted electrons, and The stopping potential.

2. If Bohr’s quantization postulate (angular momentum \( = \frac{nh}{2\pi} \)) is a basic law of nature, it should be equally valid for the case of planetary motion also. Why, then, do we never speak of quantization of orbits of planets around the Sun? Explain.

3. If both the number of protons and the neutrons are conserved in each nuclear reaction, in what way is mass converted into energy (or vice versa) in a nuclear reaction? Explain.

4.Draw a circuit diagram of a full-wave rectifier using p-n junction diodes. Explain its working and show the input-output waveforms.

5.The figure shows three point charges kept at the vertices of triangle ABC. The net electric field, due to this system of charges, at the midpoint M of base BC will be:

6.A square loop of side 0.50 m is placed in a uniform magnetic field of 0.4 T perpendicular to the plane of the loop. The loop is rotated through an angle of 60° in 0.2 s. The value of emf induced in the loop will be:

Similar Physics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
Photoemission of electrons occurs from a metal (\( \phi_0 = 1.96 \, \text{eV} \)) when light of frequency \( 6.4 \times 10^{14} \, \text{Hz} \) is incident on it. Calculate: Energy of a photon in the incident light, The maximum kinetic energy of the emitted electrons, and The stopping potential.

2.
If Bohr’s quantization postulate (angular momentum \( = \frac{nh}{2\pi} \)) is a basic law of nature, it should be equally valid for the case of planetary motion also. Why, then, do we never speak of quantization of orbits of planets around the Sun? Explain.

3.
If both the number of protons and the neutrons are conserved in each nuclear reaction, in what way is mass converted into energy (or vice versa) in a nuclear reaction? Explain.

4.
Draw a circuit diagram of a full-wave rectifier using p-n junction diodes. Explain its working and show the input-output waveforms.

5.
The figure shows three point charges kept at the vertices of triangle ABC. The net electric field, due to this system of charges, at the midpoint M of base BC will be:

6.
A square loop of side 0.50 m is placed in a uniform magnetic field of 0.4 T perpendicular to the plane of the loop. The loop is rotated through an angle of 60° in 0.2 s. The value of emf induced in the loop will be: