Compare the power consumed in the 2 Ohm resistor in each two different circuits.

Jasmine Grover

Education Journalist | Study Abroad Lead

Ques. Compare the power used in the 2 ohms resistor in each of the following circuits:
(i) a 6 V battery in series with 1 ohm and 2 ohms resistor, and
(ii) a 4V battery in parallel with 12 ohms and 2 ohms resistors.

Solution:

In order to compare the power that is used in the two combinations, we have:

Potential difference: V1 = 6V, Resistance values, R1 = 1 Ohm, and R2 = 2 Ohm
Potential difference: V2 = 4V, Resistance values, R3 = 12 Ohm, and R4 = 2 Ohm

(i) 6V battery (series combination) with 1 Ohm and 2 Ohms Resistors

As per question, the given values are:

The potential difference of the given battery = 6 V
Resistors connected in Series = 1 Ohm and 2 Ohm

The formula for equivalent resistance in the given series combination is calculated as:

R_eq=R₁+R₂

Here, R₁= 1 Ohm, R₂= 2 Ohm

The equivalent resistance will be,

R = 1 + 2 = 3 Ohm

Now, as per Ohm’s law,

V = IR

Here, I is the current through the circuit

Thus, I = 6/3

⇒ I = 2 A

6V battery in series with 1 and 2 ohm resistors

This is the flow of current via each component of the circuit since there is no division of current in series combination circuits. Therefore, the flow of current through the 2 Ohm resistor equals 2 A.

Power can be expressed by, P= I²R

Thus, P = 2²× 2

⇒ P = 8 W

Thus, the total power consumed by the two resistors will be 8 Watts.

(ii) 4V Battery Parallelly Connected with 12 Ohm and 2 Ohm Resistors

As per question, the given values are:

The potential difference of the given battery, = 4 V
Resistors connected in Parallel = 12 Ohm and 2 Ohm

Note: The voltage across each component in a parallelly connected circuit remains the same. Therefore, the voltage across the 2 Ohm resistor is going to be 4V.
The power used in the 2-ohm resistor is expressed by: P = V²/R

⇒ P = 4²/2

⇒ P = 8 W

Thus, the power consumed by a 2 Ohm resistor in both cases is 8 W.

Related Questions

Also Check:

Important Topics of Resistors in Series
Cells, emf, Internal Resistance	Power of Alternating Current	Permittivity And Permeability
Combination of Resistors	Cells in Series and in Parallel	Ohm’s Law and its Limitations
Relation between kva and kw	Derivation of Drift Velocity	Resistivity Temperature Dependence
Types of Current	Difference between air conditioning and refrigeration	Types of Resistors
Ampere	Wheatstone Bridge	Resistivity formula
Unit of Specific Resistance	Difference between RTD and thermocouple	Electromotive Force
Resistance Formula	Difference between kva and kw	Current Electricity MCQ
Static Electricity	Relation between resistance and length	Resistor Colour Codes
Current density	Unit of Current	Conductivity
Current density formula	Difference between AC and DC	Difference between emf and voltage
Potentiometer	Difference Between Primary Cell and Secondary Cell	Internal resistance formula
Electrical Formula	Electric Dipole	Power transformers
Carbon Resistor	Differences Between Acceleration and Velocity	Relation between power and resistance
Drift Velocity	Difference between earth and neutral	Uses of Resistor

CBSE CLASS XII Related Questions

1.
If Bohr’s quantization postulate (angular momentum \( = \frac{nh}{2\pi} \)) is a basic law of nature, it should be equally valid for the case of planetary motion also. Why, then, do we never speak of quantization of orbits of planets around the Sun? Explain.

View Solution

2.
The figure shows three point charges kept at the vertices of triangle ABC. The net electric field, due to this system of charges, at the midpoint M of base BC will be:

\( \frac{q}{4 \pi \epsilon_0 l^2} \) pointing along MA
\( \frac{q}{\pi \epsilon_0 l^2} \) pointing along AM
\( \frac{q}{2 \pi \epsilon_0 l^2} \) pointing along AM
Zero

View Solution

3.
Photoemission of electrons occurs from a metal (\( \phi_0 = 1.96 \, \text{eV} \)) when light of frequency \( 6.4 \times 10^{14} \, \text{Hz} \) is incident on it. Calculate: Energy of a photon in the incident light, The maximum kinetic energy of the emitted electrons, and The stopping potential.

View Solution

4.
Assertion (A) : All atoms have a net magnetic moment. Reason (R) : A current loop does not always behave as a magnetic dipole.

Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
Assertion (A) is true, but Reason (R) is false.
Both Assertion (A) and Reason (R) are false.

View Solution

5.
A light copper ring is freely suspended by a light string. A bar magnet is held horizontally with its length along the axis of the ring. The magnet is moved towards the ring with its N pole facing the loop. What will happen to the ring and its position? Explain.

View Solution

6.
Assertion (A) : The mass of a nucleus is less than the sum of the masses of the constituent nucleons. Reason (R) : Energy is absorbed when the nucleons are bound together to form a nucleus.

Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
Assertion (A) is true, but Reason (R) is false.
Both Assertion (A) and Reason (R) are false.

View Solution

Compare the power used in the 2 Ohm resistor in each two different circuits.

Ques. Compare the power used in the 2 ohms resistor in each of the following circuits:
(i) a 6 V battery in series with 1 ohm and 2 ohms resistor, and
(ii) a 4V battery in parallel with 12 ohms and 2 ohms resistors.

Solution:

(i) 6V battery (series combination) with 1 Ohm and 2 Ohms Resistors

(ii) 4V Battery Parallelly Connected with 12 Ohm and 2 Ohm Resistors

Related Questions

CBSE CLASS XII Related Questions

1.
If Bohr’s quantization postulate (angular momentum \( = \frac{nh}{2\pi} \)) is a basic law of nature, it should be equally valid for the case of planetary motion also. Why, then, do we never speak of quantization of orbits of planets around the Sun? Explain.

2.
The figure shows three point charges kept at the vertices of triangle ABC. The net electric field, due to this system of charges, at the midpoint M of base BC will be:

3.
Photoemission of electrons occurs from a metal (\( \phi_0 = 1.96 \, \text{eV} \)) when light of frequency \( 6.4 \times 10^{14} \, \text{Hz} \) is incident on it. Calculate: Energy of a photon in the incident light, The maximum kinetic energy of the emitted electrons, and The stopping potential.

4.
Assertion (A) : All atoms have a net magnetic moment. Reason (R) : A current loop does not always behave as a magnetic dipole.

5.
A light copper ring is freely suspended by a light string. A bar magnet is held horizontally with its length along the axis of the ring. The magnet is moved towards the ring with its N pole facing the loop. What will happen to the ring and its position? Explain.

6.
Assertion (A) : The mass of a nucleus is less than the sum of the masses of the constituent nucleons. Reason (R) : Energy is absorbed when the nucleons are bound together to form a nucleus.

Similar Physics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

Compare the power used in the 2 Ohm resistor in each two different circuits.

Ques. Compare the power used in the 2 ohms resistor in each of the following circuits: (i) a 6 V battery in series with 1 ohm and 2 ohms resistor, and (ii) a 4V battery in parallel with 12 ohms and 2 ohms resistors.

Solution:

(i) 6V battery (series combination) with 1 Ohm and 2 Ohms Resistors

(ii) 4V Battery Parallelly Connected with 12 Ohm and 2 Ohm Resistors

Related Questions

CBSE CLASS XII Related Questions

1. If Bohr’s quantization postulate (angular momentum \( = \frac{nh}{2\pi} \)) is a basic law of nature, it should be equally valid for the case of planetary motion also. Why, then, do we never speak of quantization of orbits of planets around the Sun? Explain.

2.The figure shows three point charges kept at the vertices of triangle ABC. The net electric field, due to this system of charges, at the midpoint M of base BC will be:

3.Photoemission of electrons occurs from a metal (\( \phi_0 = 1.96 \, \text{eV} \)) when light of frequency \( 6.4 \times 10^{14} \, \text{Hz} \) is incident on it. Calculate: Energy of a photon in the incident light, The maximum kinetic energy of the emitted electrons, and The stopping potential.

4.Assertion (A) : All atoms have a net magnetic moment. Reason (R) : A current loop does not always behave as a magnetic dipole.

5.A light copper ring is freely suspended by a light string. A bar magnet is held horizontally with its length along the axis of the ring. The magnet is moved towards the ring with its N pole facing the loop. What will happen to the ring and its position? Explain.

6.Assertion (A) : The mass of a nucleus is less than the sum of the masses of the constituent nucleons. Reason (R) : Energy is absorbed when the nucleons are bound together to form a nucleus.

Similar Physics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

Ques. Compare the power used in the 2 ohms resistor in each of the following circuits:
(i) a 6 V battery in series with 1 ohm and 2 ohms resistor, and
(ii) a 4V battery in parallel with 12 ohms and 2 ohms resistors.

1.
If Bohr’s quantization postulate (angular momentum \( = \frac{nh}{2\pi} \)) is a basic law of nature, it should be equally valid for the case of planetary motion also. Why, then, do we never speak of quantization of orbits of planets around the Sun? Explain.

2.
The figure shows three point charges kept at the vertices of triangle ABC. The net electric field, due to this system of charges, at the midpoint M of base BC will be:

3.
Photoemission of electrons occurs from a metal (\( \phi_0 = 1.96 \, \text{eV} \)) when light of frequency \( 6.4 \times 10^{14} \, \text{Hz} \) is incident on it. Calculate: Energy of a photon in the incident light, The maximum kinetic energy of the emitted electrons, and The stopping potential.

4.
Assertion (A) : All atoms have a net magnetic moment. Reason (R) : A current loop does not always behave as a magnetic dipole.

5.
A light copper ring is freely suspended by a light string. A bar magnet is held horizontally with its length along the axis of the ring. The magnet is moved towards the ring with its N pole facing the loop. What will happen to the ring and its position? Explain.

6.
Assertion (A) : The mass of a nucleus is less than the sum of the masses of the constituent nucleons. Reason (R) : Energy is absorbed when the nucleons are bound together to form a nucleus.