Half Wave Rectifier: Working, Formula and Applications

Jasmine Grover logo

Jasmine Grover

Education Journalist | Study Abroad Lead

Half wave rectifiers are used to convert AC voltage into DC voltage. It does so by passing only a single half of the alternating current voltage waveform while blocking the other half. Generally, a rectifier is a device that helps in the conversion of AC (alternating currents) to DC (direct current). A half wave rectifier circuit uses just one diode for this AC to DC voltage conversion process. A half-wave rectifier allows only a single-way flow of the current. Only passing half of the AC current leads to irregularities, therefore a capacitor is usually used to smooth out the rectified signal before it can be used. Half-wave rectifiers are less efficient compared to full-wave rectifiers. 

Key Terms: Half Wave Rectifier, Rectifier, Diode, Alternating Current, Direct Current, Waveform, Voltage


Half Wave Rectifier

[Click Here for Sample Questions]

A half-wave rectifier is the simplest form of rectifier that make use of only one diode. The half wave rectifiers use just one diode to transform AC voltage to DC Voltage.  

  • The current can pass through a diode only when it is forward-biased.
  • On applying an alternating voltage across a diode, the current only flows in one part of the cycle.
  • This property of diodes is used to rectify alternating voltages and a rectifier that allows only one-half cycle of an AC voltage waveform to pass while blocking the other half cycle are called half wave rectifiers

Circuit of Half Wave Rectifier

A half rectifier circuit consists of three main components

  1. A diode
  2. A transformer
  3. A resistive load 

Half Wave Rectifier Circuit

Half Wave Rectifier Circuit

Also Read:


Working of Half Wave Rectifier

[Click Here for Previous Year Questions]

The working of the half-wave rectifier is as follows: 

  1. Half wave rectifier works as a step-down transformer, the left side is the primary side and the right side is the secondary side.
  2. AC voltage is connected to the primary side and the secondary side is equipped with the diode and the load. 
  3. A high AC voltage is applied to the primary side of the transformer. The secondary low voltage that is acquired is then applied to the diode
  4. The diode works in two ways, it is forward biased during the positive half cycle and reverse biased during the negative half cycle.
  5. When the diode is forward biased, it acts as a closed switch while in reverse biased it acts as an open switch.
  6. As a result, no current can flow to the load and the output voltage is equal to zero. 

Circuit Diagram - Half Wave Rectifier

Half Wave Rectifier


Half Wave Rectifier Capacitor Filter 

[Click Here for Sample Questions]

In a half-wave rectifier, a capacitor or an inductor can be used as a filter. The output waveform of the half wave rectifier is a pulsating DC waveform.

  • The main function of filters is to transform the pulsating waveform into a constant DC waveform.
  • The filter is an electronic device used to perform signal processing. There are three different types of filters:
  1. Low Pass Filter
  2. Band Pass Filter
  3. High Pass Filter

Half Wave Rectifier Waveform

Half-Wave Rectifier Waveform


Half Wave Rectifier Formula

[Click Here for Previous Year Questions]

The different half wave rectifier formula are given as – 

Ripple Factor of half wave rectifier

Ripple factor determines how well the given rectifier can convert AC voltage into DC voltage. The ripple factor of a halfwave rectifier is 1.21.

The ripple factor can be calculated using the following formula –  \(\gamma =\sqrt{(\frac{\nu_{rms}}{\nu_{dc}}})^2 -1\)

Efficiency of half wave rectifier

The efficiency of a half wave rectifier is given as the ratio of output DC power to the input AC power.

The efficiency is given by the formula – η = \(\frac{P_{DC}}{P_{AC}}\)

RMS value of Half wave Rectifier

The RMS value for a half-wave rectifier is given by Irms=\(\frac{Im}{2}\)

Form Factor of a half wave rectifier

The form factor refers to the ratio of the RMS value to the average value

Form Factor =\(\frac{\text{RMS value}}{\text{Average value}}\)


Applications of Half Wave Rectifier

[Click Here for Sample Questions]

The half wave rectifier is commonly used for the following applications: 

  1. Single demodulation purpose
  2. Rectification application 
  3. Signal peak application 

Disadvantages of Half Wave Rectifiers

[Click Here for Previous Year Questions]

The main disadvantages of half-wave rectifiers are as follows: 

  1. Power loss
  2. Low output Voltage
  3. A lot of ripples

Things to Remember

  • Half wave rectifiers allow only one part of the AC voltage to pass blocking the other.
  • Half wave rectifiers are used to transform Alternating current input power into Direct current output power.
  • During the first positive wave cycle, the diode in the AC voltage is forward biased.
  • When the AC voltage is having a negative wave cycle the diode is reverse biased.
  • Filters in the half wave rectifiers are used to stabilize the pulsating DC waveforms into constant DC waveforms. 

Also Check Out:


Previous Year Questions

  1. Determine the type of gate. [JIPMER 2019]
  2. Which Logic gate is represented by the truth table? [JKCET 2012]
  3. Calculate ß when the emitter current is changed. [JEE Main 2021]
  4. What is the impurity atom to be doped for p type semiconductors? [JEE Advanced 1988]
  5. What is pure silicon. [JIPMER 2018]
  6. Device that acts as a complete electronic circuit. [NEET 2010]
  7. A p-n junction diode is also used as? [NEET 1999]
  8. What is an intrinsic semiconductor. [MET 2012]
  9. Determine the semiconductor device type. [NEET 1998]
  10. When is an npn transistor used as an amplifier. [NEET 1996]
  11. The electrical network is equivalent to? [NEET 2017]
  12.  The value of photo electromotive force is proportional to? [NEET 2005]
  13. At absolute zero, Si acts as? [NEET 1988]
  14. Which have negative coefficient of resistance. [NEET 2020]
  15. Determine the logic gate? [NEET 2010]
  16. Which is p-type semiconductor? [NEET 2013]
  17. What causes increase in width of depletion region. [NEET 2020]
  18. Calculate the voltage gain and power of the amplifier. [NEET 2017]
  19. The pn junction is forward biased when? [NEET 1988]
  20. Calculate the power gain of the amplifier. [NEET 2010]

Sample Questions

Ques. What is a half wave rectifier? (3 marks)

Ans. A device that converts AC into DC, only in one direction is called a half wave rectifier. The half wave rectifiers are the simplest rectifiers which use only one diode. The half wave rectifiers are used to transform AC voltage to DC Voltage. To transform AC voltage to DC voltage they use one diode. 

The current can pass through a diode only when it is forward biased. On applying an alternating voltage across a diode, the current only flows in one part of the cycle. This property of diodes is used to rectify alternating voltages and a rectifier that allows only one-half cycle of an AC voltage waveform to pass while blocking the other half cycle are called half wave rectifiers.

Ques. Where half wave rectifiers are used? (2 marks)

Ans. The uses of a half wave rectifier are:
  • Circuits with low power are used to charge simple batteries.
  • Circuits used in pulse generation.
  • Circuits used for signal demodulation.
  • Cementing iron circuit.

Ques. What is the use of a filter in a half wave rectifier? Which diode is used in a half wave rectifier? How many diodes are used in the half wave rectifier? (3 marks)

Ans. The filter is used to smoothen the pulsating fluctuation of DC components. 

In a half wave rectifier, PN Junction is used to convert AC to DC. One diode is used in the half wave rectifier while the full wave rectifier uses two diodes. 

Ques. Why is capacitor used in half wave rectifiers? (2 marks)

Ans. In a half wave rectifier the output voltage is not constant and varies with respect to time to get a constant DC supply filter. The role of capacitor is to filter and convert pulsating DC to pure DC. 

Ques. What are the different types of rectifiers? (4 marks)

Ans. The different types of rectifiers are as follows: 
  1. Single phase & three phase rectifiers
  2. Half wave & full wave rectifiers 
  3. Bridge Rectifiers 
  4. Uncontrolled & Controlled Rectifiers 

Ques. What is the Ripple Factor of a half wave rectifier? Give its value. (3 marks)

Ans. The ripple factor refers to the ratio between the RMS values of the alternating current component and direct current component within the rectifier’s output. ???? is the symbol used to denote the ripple factor and it can be obtained by using the formula of RMS value of AC component/DC component.

The ripple factor of the half wave rectifier is 1.21. 

Ques. Can you convert AC to DC? What is the maximum efficiency of a half wave rectifier?  (2 marks)

Ans. Yes, with the help of a rectifier AC can be converted into DC. 

The maximum efficiency of a half wave rectifier is 41%. 

Ques. Explain with the help of a circuit diagram the working of a p-n junction diode as a half wave rectifier. [2013] (3 marks)

Ans. A half wave rectifier is a device that converts AC voltage into DC voltage allowing a single part of the current to flow and blocking the other half. The half wave rectifier consists of a diode as given in the circuit diagram.

 a circuit diagram the working of a p-n junction diode as a half wave rectifier

 a circuit diagram the working of a p-n junction diode as a half wave rectifier

The secondary transformer provides the required AC voltage throughout A and B. In the case of a positive half cycle of AC, the voltage present at A is positive in nature and the diode is forward biased conducting electricity.

Therefore we get the output throughout R while in the case of positive half cycles and the output varies but is unidirectional. 

Ques. What happens to the width of the depletion layer of a p-n junction when it is :
1) Forward biased
2) Reverse biased [Delhi 2011] (2 Marks)

Ans.

  1. When the width depletion of a p-n junction is forward biased it decreases.
  2. When the width depletion of a p-n junction is reverse biased it increases.

For Latest Updates on Upcoming Board Exams, Click Here: https://t.me/class_10_12_board_updates


Do Check Out:

CBSE CLASS XII Related Questions

  • 1.
    The figure shows three point charges kept at the vertices of triangle ABC. The net electric field, due to this system of charges, at the midpoint M of base BC will be:

      • \( \frac{q}{4 \pi \epsilon_0 l^2} \) pointing along MA
      • \( \frac{q}{\pi \epsilon_0 l^2} \) pointing along AM
      • \( \frac{q}{2 \pi \epsilon_0 l^2} \) pointing along AM
      • Zero

    • 2.
      A long solenoid of length \( L \) and radius \( r_1 \) having \( N_1 \) turns is surrounded symmetrically by a coil of radius \( r_2 \, (r_2>r_1) \) having \( N_2 \) turns (\( N_2 \ll N_1 \)) around its mid-point. Derive an expression for the mutual inductance of solenoid and coil. Is \( M_{12} = M_{21} \) valid in this case?


        • 3.
          Write the expression for the magnetic field due to a current element in vector form. Consider a 1 cm segment of a wire, centered at the origin, carrying a current of 10 A in positive x-direction. Calculate the magnetic field \( \mathbf{B} \) at a point \( (1 \, \text{m}, 1 \, \text{m}, 0) \).


            • 4.
              Two small identical metallic balls having charges \( q \) and \( -2q \) are kept far at a separation \( r \). They are brought in contact and then separated at distance \( \frac{r}{2} \). Compared to the initial force \( F \), they will now:

                • attract with a force \( \frac{F}{2} \)
                • repel with a force \( \frac{F}{2} \)
                • repel with a force \( F \)
                • attract with a force \( F \)

              • 5.
                Write any two features of nuclear forces.


                  • 6.
                    Draw a circuit diagram of a full-wave rectifier using p-n junction diodes. Explain its working and show the input-output waveforms.

                      CBSE CLASS XII Previous Year Papers

                      Comments


                      No Comments To Show