How is potential gradient measured?

The potential gradient is calculated by measuring the potential difference between the ends of the wire of the potentiometer and then dividing it by the length of the wire. The potential gradient is measured in Newtons.


Related Questions

  1. Is a potentiometer analog or digital?
  2. What is a DC Potentiometer?
  3. What is balance point in potentiometer?
  4. State the Working Principle of a Potentiometer.
  5. Why High Resistance Is Used In Potentiometer?
  6. What are the two faults in a potentiometer if the balance point is not obtained?
  7. How does a potentiometer measure EMF?
  8. Which Metal Is Used In Potentiometer?
  9. Sensitivity of potentiometer can be increased by__________.
  10. What are the advantages of a potentiometer?

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CBSE CLASS XII Related Questions

  • 1.

    A magnet held vertically, with its north pole down, is dropped along the axis of a closed solenoid placed vertically on a table. If the observer looks down from the top,

      • the induced current will flow in the anticlockwise direction.
      • the induced current will flow in the clockwise direction.
      • no induced current will flow in the solenoid.
      • the magnet will fall with a constant velocity.

    • 2.
      The resistance of a metal wire at \(20^\circ\text{C}\) is \(1.05\,\Omega\) and at \(100^\circ\text{C}\) is \(1.38\,\Omega\). Determine the temperature coefficient of resistivity of this metal.


        • 3.

          A rectangular loop of size 5 cm $\times$ 8 cm is lying in the $x$-$y$ plane in a uniform magnetic field $\vec{B} = (2.0\ \text{T})\hat{k}$. The total magnetic flux linked with the loop is:

            • 80 Wb
            • 16 Wb
            • \(8 \times 10^{-2}\) Wb
            • \(8 \times 10^{-3}\) Wb

          • 4.

            A square loop of side 0.50 m is placed in a uniform magnetic field of 0.4 T perpendicular to the plane of the loop. The loop is rotated through an angle of $60^\circ$ in 0.2 s. The value of emf induced in the loop will be:

              • 5 V
              • 3.5 V
              • 2.5 V
              • Zero V

            • 5.
              Two point charges -Q and Q are located at points (d, 0) and (0, d) respectively, in x-y plane. The electric field E at the origin will be:

                • \(\frac{1}{4\pi\epsilon_0} \frac{\sqrt{2}Q}{d^2} (\hat{i} - \hat{j})\)
                • \(\frac{1}{4\pi\epsilon_0} \frac{\sqrt{2}Q}{d^2} (-\hat{i} - \hat{j})\)
                • \(\frac{1}{4\pi\epsilon_0} \frac{Q}{d^2} (\hat{i} - \hat{j})\)
                • \(\frac{1}{4\pi\epsilon_0} \frac{Q}{d^2} (-\hat{i} - \hat{j})\)

              • 6.
                In a region, the electric potential varies as \(V = 10 - 50x\), where \(V\) is in volts and \(x\) is in meters. The electric field in the region is

                  • \(10\ \text{N/C}\) along \(+x\)
                  • \(10\ \text{N/C}\) along \(-x\)
                  • \(50\ \text{N/C}\) along \(+x\)
                  • \(50\ \text{N/C}\) along \(-x\)
                CBSE CLASS XII Previous Year Papers

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