One electric bulb is attached to a 220 V generator (current = 0.50A). Find the power of the bulb.

Electric power can be expressed as the rate at which work is done or energy is transmitted in an electric circuit. A given value of power can be generated by a value combination of current and voltage. In order to determine power of the bulb, we have to:

Step 1: Data Given

The following data is already mentioned:

Voltage, V = 220 V
Current, I = 0.05 A

Step 2: Finding Solution

Since the voltage and current of a bulb are already mentioned, power can be estimated via the derived formula of Power, which is:

Power = Voltage × Current

Thus,

⇒ p = 220 x 0.05p

= 22 x 0.5p

= 11 W

Therefore, the power which is required equals 11 W.

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One electric bulb is attached to a 220 V generator (current = 0.50A). Find the power of the bulb.

Step 1: Data Given

Step 2: Finding Solution

Related Questions

CBSE CLASS XII Related Questions

3.
Write two advantages of reflecting telescope over refracting telescope.

4.
Two copper wires having their radii in the ratio of 3 : 2 are connected in series across a battery. Find the ratio of the drift velocities of the electrons in the wires.

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One electric bulb is attached to a 220 V generator (current = 0.50A). Find the power of the bulb.

Step 1: Data Given

Step 2: Finding Solution

Related Questions

CBSE CLASS XII Related Questions

3.Write two advantages of reflecting telescope over refracting telescope.

4.Two copper wires having their radii in the ratio of 3 : 2 are connected in series across a battery. Find the ratio of the drift velocities of the electrons in the wires.

Similar Physics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

3.
Write two advantages of reflecting telescope over refracting telescope.

4.
Two copper wires having their radii in the ratio of 3 : 2 are connected in series across a battery. Find the ratio of the drift velocities of the electrons in the wires.