One electric bulb is attached to a 220 V generator (current = 0.50A). Find the power of the bulb.

Electric power can be expressed as the rate at which work is done or energy is transmitted in an electric circuit.  A given value of power can be generated by a value combination of current and voltage. In order to determine power of the bulb, we have to:

Step 1: Data Given

The following data is already mentioned:

  • Voltage, V = 220 V
  • Current, I = 0.05 A

Step 2: Finding Solution

Since the voltage and current of a bulb are already mentioned, power can be estimated via the derived formula of Power, which is:

Power = Voltage × Current

Thus,

⇒ p = 220 x 0.05p 

= 22 x 0.5p 

= 11 W

Therefore, the power which is required equals 11 W.


Related Questions

  1. In An Arrangement Of Resistances, Find Effective Resistance Between Points A and B.
  2. What Is Effective Resistance?
  3. Find The Highest And Lowest Total Resistance Of A Combination Of Four Coils With Resistances 4 Ohms, 8 Ohms, 12 Ohms, 24 Ohms.
  4. What is Null Voltage?
  5. Three Incandescent Bulbs (Each 100 W) Are Attached In Series. In Another Circuit, Three More Bulbs Of Same Wattage Are Attached Parallelly To An Equal Source.
  6. Two Identical Resistors With Resistances 15 Ohm Are Connected In Series And Parallel To A Battery Of 6 V. Calculate Ratio Of Power Consumed.
  7. For The Resistor Combination, Find The Equivalent Resistance Between M and N.
  8. A Circuit Consists Of A Battery Of 3 Cells (2 V Each), A Combination Of Three Resistors, 10 Ohm, 20 Ohm And 30 Ohm, Attached Parallelly, With Plug Key And Ammeter (In Series).
  9. X and Y, which are two resistors, with resistances of 2 Ω and 3 Ω respectively are first connected in parallel and then in series. In both cases, the voltage that is supplied is 5 V. (i) Illustrate a circuit diagram to show the combination of resistors. (ii) Calculate the amount of voltage across 3 Ω resistor in the series combination of resistors.
  10. Draw An Electric Circuit With A Cell, Key, Ammeter, A Resistor (Series) Of 2 Ohm With a Combination Of Two Resistors (4 Ohm Each) In Parallel And A Voltmeter Across Parallel Combination.

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CBSE CLASS XII Related Questions

  • 1.
    Two air-filled capacitors of capacitances $C_1$ and $C_2$ are connected in parallel with a dc battery. After the capacitors are fully charged, a slab of dielectric constant K is inserted between the plates of each capacitor. How will the (i) charge on each capacitor and (ii) energy stored in the capacitor affected after the slab is introduced.


      • 2.
        An electric field $\vec{E}$ is established across the ends of a cylindrical conductor of length L and area of cross-section A. Discuss how electrons attain an average velocity, independent of time. Hence, obtain a relation between current in the conductor and this ‘average velocity’ of electrons.


          • 3.
            This ‘average velocity’ is found be few mm/s for currents in range of a few amperes. How then is current established almost the instant a circuit is closed ?


              • 4.
                Read the following paragraph and answer the questions that follow.
                In an experiment with convex lens of focal length f, the screen is fixed at a distance D from the object. A student slowly moves the lens away from the object towards the screen and finds that she is able to form sharp image of the object for two positions of the lens. The distance between these two positions of the lens is d.


                  • 5.
                    Two copper wires having their radii in the ratio of 3 : 2 are connected in series across a battery. Find the ratio of the drift velocities of the electrons in the wires.


                      • 6.
                        Derive an expression for the capacitance of a parallel plate capacitor of plate area A and plate separation d with air present between the plates.

                          CBSE CLASS XII Previous Year Papers

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