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Osmotic pressure can be explained as the pressure that is exerted to the solution side to prevent fluid movement when a semi-permeable membrane differentiates a solution from pure water. The term ‘osmose’ was introduced in 1854 by a British chemist, Thomas Graham. Jacobus Henricus van’t Hoff, a Dutch chemist showed in 1886 that if the solute is dilute then its partial vapour pressure obeys Henry’s law that is the osmotic pressure varies with the concentration and temperature nearby as it would if the solute were gas occupying the required volume. This relation led to equations for finding molecular weights of the solutes in the dilute solutions through effects of freezing point, boiling points and vapour pressure of a solvent. The process of Osmosis is quite important in biology and was thoroughly examined in 1877 by a German plant physiologist, Wilhelm Pfeffer.
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Key Takeaways: Osmosis, Osmotic Pressure, Reverse osmosis, water potential, xylem, types of osmosis, osmotic solutions, semipermeable membrane, Transpiration
What is Osmosis?
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Osmosis can be stated as a movement of a solvent through a semipermeable membrane as a living cell into a solution of higher concentration solute that tends to balance the concentrations of solute on both sides of the membrane. It is typically a binding property and is completely dependent on the concentration of solute particles in the solution.

Osmosis
Types of osmosis
There are basically two types of osmosis:
- Endosmosis
It is a process in which when a substance is placed in a hypotonic solution, its molecules in the solvent move inside the cell and the cell becomes swollen. This occurrence is called endosmosis.
- Exosmosis
It is a process in which when a substance is placed in a hypertonic solution, the molecules in the solvent move outside the cell and the cell becomes loose or undergo plasmolysis. This occurrence is called exosmosis.
Osmotic solutions
There are three types of osmotic solutions:
- Isotonic solution: It is the solution having an equal concentration of solutes both inside as well as outside of the cell.
- Hypertonic solution: In this solution, the concentration of solute is higher outside the cell membrane.
- Hypotonic solution: In this solution, the concentration of solute is higher inside the cell membrane.
Also Read:
| Related Articles | ||
|---|---|---|
| Types of solutions | Mole Fraction | Relation between Normality and Molarity |
| Melting and Boiling Point | Mass Percent Formula | Freezing Point Depression |
What Is Osmotic Pressure?
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Osmotic pressure in simple terms can be explained as the minimum pressure put on the solution to prevent the flow of solvent molecules through a semipermeable membrane. However, the flow continues till the equilibrium is achieved. This flow of solvent that wants to penetrate the membrane can be stopped if some extra pressure is applied to the solution. This very pressure that helps in preventing the flow of solvent is termed osmotic pressure.
Osmotic Pressure Equation
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The quantitative relationship between the osmotic pressure and solute concentration was first given by Dutch chemist Jacobus, expressing the following equation for osmotic pressure.
\(\pi\) = iCRT
Where,
\(\pi\)- osmotic pressure,
i - dimensionless van’t Hoff index,
C - molecular concentration of solute in the solution,
R - ideal gas constant,
T - temperature in kelvin.
Moreover, it is crucial to understand that the derived osmotic pressure equation holds only true for solutions that act the same as ideal solutions.
Note: Osmotic pressure for pure water is ‘0’ as it has ‘0’ osmotic pressure.
Understanding Osmotic Pressure
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Osmotic pressure can be explained easily with the help of the following steps given below:
- For this assume a U-tube showing an osmotic pressure diagram,

U-tube showing Osmotic Pressure.
- The left portion of the U-tube contains an aqueous solution, and right portion consists of pure water.
- Here, the pure water tries to dilute the solution by penetrating through the semipermeable membrane but the weight added by the water on the left tube caused pressure to hold osmosis.
- This goes on till the equilibrium is maintained.
- Now to attain osmotic pressure, increase the hydrostatic pressure on the solution side of the membrane. This then squeezes the solvent molecules closer, increasing the tendency to escape.
- This escaping tendency of a solution can be ascended until it becomes equal to the molecules in the pure solvent.
- And at this very point, osmosis will cease. Osmotic pressure is the pressure required to attain osmotic equilibrium.
Reverse Osmosis
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Reverse osmosis is a natural occurrence that happens in the opposite direction of the natural osmosis. This is basically used for extracting the major contaminants from water by pushing the water under pressure through a semipermeable membrane.

Reverse Osmosis
Significance of Osmosis
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Osmosis plays an important role as:
- Osmosis holds the transport of nutrients and the release of metabolic waste products.
- It plays a vital role in the absorption of water from the soil and distributing it to the upper parts of the plant via xylem.
- It maintains the equilibrium in the internal environment of the living organism by maintaining the balance between water and intercellular fluid.
- It maintains cell turgidity.
- Osmosis controls cell-to-cell diffusion.
- Osmosis prevents plants from drought injury due to high osmotic pressure.
- Osmosis also prevents the partial opening of fruits and sporangia.
- Osmosis induces cell turgor which regulates movements of plants and part of it.
- Osmosis maintains the continuous water supply to plants even though there is a loss of water due to transpiration.
Examples of Osmosis
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Osmosis plays a vital role in plants, animals, and humans.
- The assimilation of water through soil occurs due to osmosis.
- The guard cells of the plants are affected due to osmosis. When the plant cells are filled with water, the guard cells swell up and thus opening the stomata.
- If the fish from salt water or fresh water is placed in different salt concentrations, the fish dies due to the entry and exit of water in the cells of the fish.
- Humans suffering from cholera faces osmosis, as the bacteria overpopulate the intestine hence reversing the flow of absorption and thus preventing the absorption of water and leading to dehydration.
- When fingers are placed inside the water, they get wrinkled due to the flow of water inside the cell.
Things to Remember
- The semipermeable membrane is a biological membrane that helps in the movements of certain molecules or ions through it.
- Osmosis is applied for preserving foods. As in fruits are commonly kept in honey to keep them from spoiling. Honey acts as a hypertonic solution thus sucking water out and preventing bacteria to prevent microbial metabolism.
- Osmotic pressure has a colligative (binding) property which prevents the solvent from entering the solution through a membrane barrier.
- The concentration of solute and temperature are two factors affecting osmotic pressure.
- The pressure that moves water in and out of cells is known as water potential.
- The water moves from high potential to low. Pure water has high potential thus it moves inside the cell if they have water around them.
- Plant cells absorb water by osmosis until the cell wall forces back on the cell’s content with equal pressure.
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Sample Questions
Ques. Calculate the mole fraction of ethylene glycol (C2H6O2) in a solution containing 30% of C2H6O2 by mass. (3 marks)
Ans: Assume we have 100 g of solution. Solution will contain 30 g of ethylene glycol and 70 g of water.
Molar mass of C2H6O2 = 12 x 2 + 1 x 6 + 16 x 2 = 62 g mol-1.
Moles of C2H6O2 = \(30 \over 62 g mol^-1 \)= 0.4838 mol
Moles of water = \(70\over18 g mol-1\) = 3.8888 mol----- (molar mass of H2O = 1 x 2+ 16 = 18 g mol-1)
Xglycol = \(moles of C_2H_6O_2\over moles of C_2H_6O_2+moles of H_2O\) =\( 0.4838\over0.4838+3.8888\) = 0.1106
Similarly, Xwater = \(3.8888\over3.8888+0.4838\) = 0.8894.
Mole fraction of water can also be calculated as 1- 0.1106 = 0.8894.
Ques. Calculate the molarity of a solution containing 4 g of NaOH in 450 mL solution. (3 marks)
Ans: Moles of NaOH = \(4\over40\) = 0.1 mol------- (Molar mass of NaOH = 1 x 23 + 16 + 1 = 40 gmol-1 )
Volume of the solution in litres = 450 mL/1000 mLL-1
Molarity = \(moles of solute\over volume of the solution in litre \)= 0.1 x 1000450=0.2222 M
= 0.2222 mol L-1 or 0.2222 mol dm-3.
Ques. Write down the list of values of Henry’s Law Constant for some selected gases in water (3 marks)
Ans: The list of values of Henry’s Law Constant for some selected gases in water are given as:
| Gas | Temperature/K | KH/kbar | Gas | Temperature/K | KH/kbar |
|---|---|---|---|---|---|
| He | 293 | 144.97 | Argon | 298 | 40.3 |
| H2 | 293 | 69.16 | CO2 | 298 | 1.67 |
| N2 | 293 | 76.48 | Formaldehyde | 298 | 1.83 x 10-5 |
| N2 | 303 | 88.84 | Methane | 298 | 0.413 |
| O2 | 293 | 34.86 | Vinyl chloride | 298 | 0.611 |
| O2 | 303 | 46.82 |
Ques. Define: (3 marks)
(1)Osmosis
(2)Reverse osmosis
(3)Water potential
Ans: The definitions for them are as follows:
- Osmosis: It is the instant passage or diffusion of water or other solvents through a semipermeable membrane. Also, one that prevents the passing of dissolved substances – solutes.
- Reverse osmosis: It is a process used in extracting a large number of contaminants from water by pushing the water under pressure through the membrane.
- Water potential: It is the estimate of the potential energy in water as well as the difference between the potential in pure water and a given sample.
Ques. Draw a diagram showing reverse osmosis. (4 marks)
Ans: The diagram showing reverse osmosis is as given below:

Ques. The benzene’s boiling point is 353.23 K. When 1.90 g of a non-volatile solute was dissolved in 80 g of benzene, the boiling point is raised to 355 K. find the molar mass of the solute. Kbar for benzene is 2.53 K kg mol-1 (3 marks)
Ans: The elevation in the boiling point (\(\Delta\)Tb) = 355 – 353.23 = 1.77 K.
Molar mass = mass of a substance (m)no. of moles of a substance (n) = 2.53 x 1.90 x 10001.77 x 80 = 33.94 g mol-1.
Hence, the molar mass of the solute is 33.94 g mol-1.
Ques. Define: (5 marks)
(1) Mole fraction
(2) Molality
(3) Morality
(4) Mass percentage
Ans: The definitions for the terms are as given below:
- Mole Fraction: It is stated as the number of moles of a specific component to the total number of moles of all the components in the mix. It is represented as χ.
- Molality: It is the number of moles of the solute per kilogram of the solvent. It is also the ratio of the number of moles of solute to the mass of the solvent.
- Molarity: It is stated as the number of moles of solute per litre of the solution. it is the ratio of the number of moles of solute to the volume of the solvent.
- Mass Percentage: It is defined as the concentration of an element in a compound. It is calculated as the mass of a mixture divided by the total mass of the mix, multiplied by 100%.
Ques. A solution contains 30 g of urea in 600 g of water. The concentration of the solution in terms of mass percentage is? (2 marks)
(a) 3.84
(b) 4.76
(c) 95
(d) None of the above
Ans: (b) 4.76
The concentration in terms of mass percentage of solute in the solution = mass of solutemass of solution x 100
= 30630 x 100 = 4.762%.
The concentration of the solution in terms of mass percentage of the solute in the solution is 4.762 %.
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