Resistance can be expressed as the ratio between the applied voltage to the current flowing through a circuit. The S.I. unit of resistance is Ohms (Ω).
Step 1: Read The Given Data
Initial resistance on wire, Ri = 6 Ω
Assume the initial length of wire as = Li
If final length of the wire is, Lf = \( {{L_i} \over 2}\)
Assume the initial area = Ai
If the final area of the wire, Af = 2Ai
Let the resistivity and final resistance of the wire be ρ and Rf respectively.
Step 2: Use of Formula
Resistance can be expressed as, \(R = \rho{{L} \over A}\)
Thus, \(\rho ={{RA} \over L}\)
Step 3: New Resistance Calculation
Since the resistivity of the wire remains the same in both, we can mention:
\(\rho = {{R_i A_i} \over L_i} = {{R_fA_f} \over L_f}\)
Upon value substitution, we can get,
\({{6A_i} \over Li} = {{4A_iR_f} \over L_i}\)
⇒ Rf = 1.5 \(\Omega\)
Thus, the new resistance is 1.5 \(\Omega\).
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