How many 176 ohm resistors (in parallel) are required to carry 5 A on a 220 V line?

Ohm's law provides a resistor’s equivalent resistance parallelly linked for x number of resistors of resistance 176 Ω as,

⇒ V = IR

Step 1: List the Given Data

Considering the equation as, \(R = {{V}\over I}\)

Here,

• Voltage, V = 220 V
• Current, I = 5A
• R = Equivalent Resistance of Combination

Step 2: Calculation of the Given Data

\({{1} \over R} = x \times {{1} \over (176)}\)

R = \({{176} \over x}\)

Now, as per Ohm’s Law, we get,

\({{V} \over I} = {{176} \over x}\)

⇒ \(x = {{176 \times 5} \over 220} = 4\)

Hence, in order to draw the required amount of current, four 176 Ω resistors will be needed.

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