How many 176 ohm resistors (in parallel) are required to carry 5 A on a 220 V line?

Ohm's law provides a resistor’s equivalent resistance parallelly linked for x number of resistors of resistance 176 Ω as,

⇒ V = IR

Step 1: List the Given Data

Considering the equation as, \(R = {{V}\over I}\)

Here,

  • Voltage, V = 220 V
  • Current, I = 5A
  • R = Equivalent Resistance of Combination

Step 2: Calculation of the Given Data

\({{1} \over R} = x \times {{1} \over (176)}\)

R = \({{176} \over x}\)

Now, as per Ohm’s Law, we get,

\({{V} \over I} = {{176} \over x}\)

⇒ \(x = {{176 \times 5} \over 220} = 4\)

Hence, in order to draw the required amount of current, four 176 Ω resistors will be needed.


Related Questions:

  1. What is the necessary condition for a conductor to obey Ohm's Law?
  2. What are the limitations of Ohm's Law?
  3. What are the applications of ohm's law used in daily life?
  4. State Ohms Law. Express It Mathematically. Define Si Unit Of Resistance.
  5. Why is the curve representing Ohm's law linear?
  6. State Ohms law. How can it be verified experimentally?
  7. How do you find the resistance in Ohm's law?
  8. What are the 3 forms of Ohm's law
  9. What is Effective Resistance?
  10. Is resistance constant in Ohm's law?
  11. Draw a circuit diagram to verify ohm’s law.

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