A 6 ohm resistance wire has been doubled via folding. Determine new resistance.

Resistance can be expressed as the ratio between the applied voltage to the current flowing through a circuit. The S.I. unit of resistance is Ohms (Ω).

Step 1: Read The Given Data

Initial resistance on wire, R_i = 6 Ω

Assume the initial length of wire as = L_i

If final length of the wire is, L_f= $ {{L_i} \over 2}$

Assume the initial area = A_i

If the final area of the wire, A_f= 2A_i

Let the resistivity and final resistance of the wire be ρ and R_f respectively.

Step 2: Use of Formula

Resistance can be expressed as, $R = \rho{{L} \over A}$

Thus, $\rho ={{RA} \over L}$

Step 3: New Resistance Calculation

Since the resistivity of the wire remains the same in both, we can mention:

$\rho = {{R_i A_i} \over L_i} = {{R_fA_f} \over L_f}$

Upon value substitution, we can get,

${{6A_i} \over Li} = {{4A_iR_f} \over L_i}$

⇒ R_f= 1.5 $\Omega$

Thus, the new resistance is 1.5 $\Omega$.

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A 6 ohm resistance wire has been doubled via folding. Determine new resistance.

Step 1: Read The Given Data

Step 2: Use of Formula

Step 3: New Resistance Calculation

Related Questions

CBSE CLASS XII Related Questions

1.
Find the ratio $\dfrac{\lambda_\alpha}{\lambda_p}$ of the de Broglie wavelength $\lambda_\alpha$ associated with an alpha particle to the de Broglie wavelength $\lambda_p$ associated with a proton if both are moving with the same velocity.

3.
A current of \(4.0\,\text{A}\) flows through a wire of length \(1\,\text{m}\) and cross-sectional area \(1.0\,\text{mm}^2\), when a potential difference of \(2\,\text{V}\) is applied across its ends. Calculate the resistivity of the material of the wire.

4.
A square loop of side 0.50 m is placed in a uniform magnetic field of 0.4 T perpendicular to the plane of the loop. The loop is rotated through an angle of $60^\circ$ in 0.2 s. The value of emf induced in the loop will be:

5.
Two point charges -Q and Q are located at points (d, 0) and (0, d) respectively, in x-y plane. The electric field E at the origin will be:

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A rectangular loop of size 5 cm $\times$ 8 cm is lying in the $x$-$y$ plane in a uniform magnetic field $\vec{B} = (2.0\ \text{T})\hat{k}$. The total magnetic flux linked with the loop is:

Similar Physics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

A 6 ohm resistance wire has been doubled via folding. Determine new resistance.

Step 1: Read The Given Data

Step 2: Use of Formula

Step 3: New Resistance Calculation

Related Questions

CBSE CLASS XII Related Questions

1.Find the ratio $\dfrac{\lambda_\alpha}{\lambda_p}$ of the de Broglie wavelength $\lambda_\alpha$ associated with an alpha particle to the de Broglie wavelength $\lambda_p$ associated with a proton if both are moving with the same velocity.

3.A current of \(4.0\,\text{A}\) flows through a wire of length \(1\,\text{m}\) and cross-sectional area \(1.0\,\text{mm}^2\), when a potential difference of \(2\,\text{V}\) is applied across its ends. Calculate the resistivity of the material of the wire.

4.A square loop of side 0.50 m is placed in a uniform magnetic field of 0.4 T perpendicular to the plane of the loop. The loop is rotated through an angle of $60^\circ$ in 0.2 s. The value of emf induced in the loop will be:

5.Two point charges -Q and Q are located at points (d, 0) and (0, d) respectively, in x-y plane. The electric field E at the origin will be:

6.A rectangular loop of size 5 cm $\times$ 8 cm is lying in the $x$-$y$ plane in a uniform magnetic field $\vec{B} = (2.0\ \text{T})\hat{k}$. The total magnetic flux linked with the loop is:

Similar Physics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
Find the ratio $\dfrac{\lambda_\alpha}{\lambda_p}$ of the de Broglie wavelength $\lambda_\alpha$ associated with an alpha particle to the de Broglie wavelength $\lambda_p$ associated with a proton if both are moving with the same velocity.

3.
A current of \(4.0\,\text{A}\) flows through a wire of length \(1\,\text{m}\) and cross-sectional area \(1.0\,\text{mm}^2\), when a potential difference of \(2\,\text{V}\) is applied across its ends. Calculate the resistivity of the material of the wire.

4.
A square loop of side 0.50 m is placed in a uniform magnetic field of 0.4 T perpendicular to the plane of the loop. The loop is rotated through an angle of $60^\circ$ in 0.2 s. The value of emf induced in the loop will be:

5.
Two point charges -Q and Q are located at points (d, 0) and (0, d) respectively, in x-y plane. The electric field E at the origin will be:

6.
A rectangular loop of size 5 cm $\times$ 8 cm is lying in the $x$-$y$ plane in a uniform magnetic field $\vec{B} = (2.0\ \text{T})\hat{k}$. The total magnetic flux linked with the loop is: