A 6 ohm resistance wire has been doubled via folding. Determine new resistance.

Resistance can be expressed as the ratio between the applied voltage to the current flowing through a circuit. The S.I. unit of resistance is Ohms (Ω).

Step 1: Read The Given Data

Initial resistance on wire, R_i = 6 Ω

Assume the initial length of wire as = L_i

If final length of the wire is, L_f= \( {{L_i} \over 2}\)

Assume the initial area = A_i

If the final area of the wire, A_f= 2A_i

Let the resistivity and final resistance of the wire be ρ and R_f respectively.

Step 2: Use of Formula

Resistance can be expressed as, \(R = \rho{{L} \over A}\)

Thus, \(\rho ={{RA} \over L}\)

Step 3: New Resistance Calculation

Since the resistivity of the wire remains the same in both, we can mention:

\(\rho = {{R_i A_i} \over L_i} = {{R_fA_f} \over L_f}\)

Upon value substitution, we can get,

\({{6A_i} \over Li} = {{4A_iR_f} \over L_i}\)

⇒ R_f= 1.5 \(\Omega\)

Thus, the new resistance is 1.5 \(\Omega\).

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A 6 ohm resistance wire has been doubled via folding. Determine new resistance.

Step 1: Read The Given Data

Step 2: Use of Formula

Step 3: New Resistance Calculation

Related Questions

CBSE CLASS XII Related Questions

1.
Draw the number of scattered particles versus the scattering angle graph for scattering of alpha particles by a thin foil. Write two important conclusions that can be drawn from this plot.

2.
Assertion (A) : The mass of a nucleus is less than the sum of the masses of the constituent nucleons. Reason (R) : Energy is absorbed when the nucleons are bound together to form a nucleus.

3.
A square loop of side 0.50 m is placed in a uniform magnetic field of 0.4 T perpendicular to the plane of the loop. The loop is rotated through an angle of 60° in 0.2 s. The value of emf induced in the loop will be:

4.
The figure shows three point charges kept at the vertices of triangle ABC. The net electric field, due to this system of charges, at the midpoint M of base BC will be:

5.
Two small identical metallic balls having charges \( q \) and \( -2q \) are kept far at a separation \( r \). They are brought in contact and then separated at distance \( \frac{r}{2} \). Compared to the initial force \( F \), they will now:

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If both the number of protons and the neutrons are conserved in each nuclear reaction, in what way is mass converted into energy (or vice versa) in a nuclear reaction? Explain.

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Comments

SUBSCRIBE TO OUR NEWS LETTER

A 6 ohm resistance wire has been doubled via folding. Determine new resistance.

Step 1: Read The Given Data

Step 2: Use of Formula

Step 3: New Resistance Calculation

Related Questions

CBSE CLASS XII Related Questions

1. Draw the number of scattered particles versus the scattering angle graph for scattering of alpha particles by a thin foil. Write two important conclusions that can be drawn from this plot.

2.Assertion (A) : The mass of a nucleus is less than the sum of the masses of the constituent nucleons. Reason (R) : Energy is absorbed when the nucleons are bound together to form a nucleus.

3.A square loop of side 0.50 m is placed in a uniform magnetic field of 0.4 T perpendicular to the plane of the loop. The loop is rotated through an angle of 60° in 0.2 s. The value of emf induced in the loop will be:

4.The figure shows three point charges kept at the vertices of triangle ABC. The net electric field, due to this system of charges, at the midpoint M of base BC will be:

5.Two small identical metallic balls having charges \( q \) and \( -2q \) are kept far at a separation \( r \). They are brought in contact and then separated at distance \( \frac{r}{2} \). Compared to the initial force \( F \), they will now:

6. If both the number of protons and the neutrons are conserved in each nuclear reaction, in what way is mass converted into energy (or vice versa) in a nuclear reaction? Explain.

Similar Physics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
Draw the number of scattered particles versus the scattering angle graph for scattering of alpha particles by a thin foil. Write two important conclusions that can be drawn from this plot.

2.
Assertion (A) : The mass of a nucleus is less than the sum of the masses of the constituent nucleons. Reason (R) : Energy is absorbed when the nucleons are bound together to form a nucleus.

3.
A square loop of side 0.50 m is placed in a uniform magnetic field of 0.4 T perpendicular to the plane of the loop. The loop is rotated through an angle of 60° in 0.2 s. The value of emf induced in the loop will be:

4.
The figure shows three point charges kept at the vertices of triangle ABC. The net electric field, due to this system of charges, at the midpoint M of base BC will be:

5.
Two small identical metallic balls having charges \( q \) and \( -2q \) are kept far at a separation \( r \). They are brought in contact and then separated at distance \( \frac{r}{2} \). Compared to the initial force \( F \), they will now:

6.
If both the number of protons and the neutrons are conserved in each nuclear reaction, in what way is mass converted into energy (or vice versa) in a nuclear reaction? Explain.