A closed coil has 500 turns across rectangular frame of area 4.0 cm2 with resistance of 500 ohms. The coil is plane perpendicular to a uniform magnetic field of 0.2wb/m2. Find amount of charge through coil if turned over. (180 degrees rotation)

As per the given parameters, the following can be understood:

  • The number of turns, n = 500
  • Area, A = 4cm2 = 4 × 10−4m2
  • Resistance of closed coil, R = 500Ω
  • Magnetic field, B = 0.2wb/m2

Thus, in order to estimate the amount of charge flowing through the coil, we need to:

Magnetic flux can be expressed by the following formula,

ϕ = nBAcosθ

Where,

  • n = Number of turns
  • B = Magnetic field
  • A = Area
  • θ = Angle between Area vector and Magnetic Field

Assuming estimate the change in magnetic flux when it is turned over (with rotation of 180 degrees). Thus,

⇒ △ϕ = nBAcos0 − (nBAcos180)

Let us simplify the expression.

△ϕ = nBA + nBA = 2nBA

= 2 × 500 × 0.2 × 4 × 10−4

⇒ △ϕ = 8×10−2

Therefore, the charge that flows through the area can be expressed by the following formula.

△Q = △ϕ/resistance = 8×10−2/500

=1.6 × 10−4C

=0.16 × 10−3C


Related Questions

  1. In An Arrangement Of Resistances, Find Effective Resistance Between Points A and B.
  2. What Is Effective Resistance?
  3. Find The Highest And Lowest Total Resistance Of A Combination Of Four Coils With Resistances 4 Ohms, 8 Ohms, 12 Ohms, 24 Ohms.
  4. What is Null Voltage?
  5. X and Y, which are two resistors, with resistances of 2 Ω and 3 Ω respectively are first connected in parallel and then in series. In both cases, the voltage that is supplied is 5 V. (i) Illustrate a circuit diagram to show the combination of resistors. (ii) Calculate the amount of voltage across 3 Ω resistor in the series combination of resistors.
  6. Draw An Electric Circuit With A Cell, Key, Ammeter, A Resistor (Series) Of 2 Ohm With a Combination Of Two Resistors (4 Ohm Each) In Parallel And A Voltmeter Across Parallel Combination.

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CBSE CLASS XII Related Questions

  • 1.

    A circular coil of 100 turns and radius $\left(\frac{10}{\sqrt{\pi}}\right)$ cm carrying current of $5.0\,\text{A}$ is suspended vertically in a uniform horizontal magnetic field of $2.0\,\text{T}$. The field makes an angle $30^\circ$ with the normal to the coil. Calculate:

    (I) the magnetic dipole moment of the coil, and

    (II) the magnitude of the counter torque that must be applied to prevent the coil from turning.


      • 2.
        The resistance of a metal wire at \(20^\circ\text{C}\) is \(1.05\,\Omega\) and at \(100^\circ\text{C}\) is \(1.38\,\Omega\). Determine the temperature coefficient of resistivity of this metal.


          • 3.

            A square loop of side 0.50 m is placed in a uniform magnetic field of 0.4 T perpendicular to the plane of the loop. The loop is rotated through an angle of $60^\circ$ in 0.2 s. The value of emf induced in the loop will be:

              • 5 V
              • 3.5 V
              • 2.5 V
              • Zero V

            • 4.

              Consider a cylindrical conductor of length $l$ and area of cross-section $A$. Current $I$ is maintained in the conductor and electrons drift with velocity $\vec{v}_d$ ($|\vec{v}_d| = \frac{e|\vec{E}|}{m}\tau$), (where symbols have their usual meanings). Show that the conductivity $\sigma$ of the material of the conductor is given by

              $$\sigma = \frac{ne^2}{m}\tau.$$


                • 5.
                  A current of \(4.0\,\text{A}\) flows through a wire of length \(1\,\text{m}\) and cross-sectional area \(1.0\,\text{mm}^2\), when a potential difference of \(2\,\text{V}\) is applied across its ends. Calculate the resistivity of the material of the wire.


                    • 6.
                      The resistance of a metal wire at \(20^\circ\text{C}\) is \(1.05\,\Omega\) and at \(100^\circ\text{C}\) is \(1.38\,\Omega\). Determine the temperature coefficient of resistivity of this metal.

                        CBSE CLASS XII Previous Year Papers

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