A closed coil has 500 turns across rectangular frame of area 4.0 cm2 with resistance of 500 ohms.

As per the given parameters, the following can be understood:

The number of turns, n = 500
Area, A = 4cm² = 4 × 10⁻⁴m²
Resistance of closed coil, R = 500Ω
Magnetic field, B = 0.2wb/m²

Thus, in order to estimate the amount of charge flowing through the coil, we need to:

Magnetic flux can be expressed by the following formula,

ϕ = nBAcosθ

Where,

n = Number of turns
B = Magnetic field
A = Area
θ = Angle between Area vector and Magnetic Field

Assuming estimate the change in magnetic flux when it is turned over (with rotation of 180 degrees). Thus,

⇒ △ϕ = nBAcos0 − (nBAcos180)

Let us simplify the expression.

△ϕ = nBA + nBA = 2nBA

= 2 × 500 × 0.2 × 4 × 10⁻⁴

⇒ △ϕ = 8×10⁻²

Therefore, the charge that flows through the area can be expressed by the following formula.

△Q = △ϕ/resistance = 8×10⁻²/500

=1.6 × 10⁻⁴C

=0.16 × 10⁻³C

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A closed coil has 500 turns across rectangular frame of area 4.0 cm2 with resistance of 500 ohms. The coil is plane perpendicular to a uniform magnetic field of 0.2wb/m2. Find amount of charge through coil if turned over. (180 degrees rotation)

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Draw the number of scattered particles versus the scattering angle graph for scattering of alpha particles by a thin foil. Write two important conclusions that can be drawn from this plot.

2.
Two heaters rated as \((P_1,V)\) and \((P_2,V)\) are connected in series across a dc source of \(V/2\) volt. The power consumed by the combination will be –

3.
Draw a circuit diagram of a full-wave rectifier using p-n junction diodes. Explain its working and show the input-output waveforms.

4.
Assertion (A) : All atoms have a net magnetic moment. Reason (R) : A current loop does not always behave as a magnetic dipole.

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A closed coil has 500 turns across rectangular frame of area 4.0 cm2 with resistance of 500 ohms. The coil is plane perpendicular to a uniform magnetic field of 0.2wb/m2. Find amount of charge through coil if turned over. (180 degrees rotation)

Related Questions

CBSE CLASS XII Related Questions

1. Draw the number of scattered particles versus the scattering angle graph for scattering of alpha particles by a thin foil. Write two important conclusions that can be drawn from this plot.

2.Two heaters rated as \((P_1,V)\) and \((P_2,V)\) are connected in series across a dc source of \(V/2\) volt. The power consumed by the combination will be –

3.Draw a circuit diagram of a full-wave rectifier using p-n junction diodes. Explain its working and show the input-output waveforms.

4.Assertion (A) : All atoms have a net magnetic moment. Reason (R) : A current loop does not always behave as a magnetic dipole.

5. If Bohr’s quantization postulate (angular momentum \( = \frac{nh}{2\pi} \)) is a basic law of nature, it should be equally valid for the case of planetary motion also. Why, then, do we never speak of quantization of orbits of planets around the Sun? Explain.

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Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
Draw the number of scattered particles versus the scattering angle graph for scattering of alpha particles by a thin foil. Write two important conclusions that can be drawn from this plot.

2.
Two heaters rated as \((P_1,V)\) and \((P_2,V)\) are connected in series across a dc source of \(V/2\) volt. The power consumed by the combination will be –

3.
Draw a circuit diagram of a full-wave rectifier using p-n junction diodes. Explain its working and show the input-output waveforms.

4.
Assertion (A) : All atoms have a net magnetic moment. Reason (R) : A current loop does not always behave as a magnetic dipole.

5.
If Bohr’s quantization postulate (angular momentum \( = \frac{nh}{2\pi} \)) is a basic law of nature, it should be equally valid for the case of planetary motion also. Why, then, do we never speak of quantization of orbits of planets around the Sun? Explain.