A closed coil has 500 turns across rectangular frame of area 4.0 cm2 with resistance of 500 ohms.

As per the given parameters, the following can be understood:

The number of turns, n = 500
Area, A = 4cm² = 4 × 10⁻⁴m²
Resistance of closed coil, R = 500Ω
Magnetic field, B = 0.2wb/m²

Thus, in order to estimate the amount of charge flowing through the coil, we need to:

Magnetic flux can be expressed by the following formula,

ϕ = nBAcosθ

Where,

n = Number of turns
B = Magnetic field
A = Area
θ = Angle between Area vector and Magnetic Field

Assuming estimate the change in magnetic flux when it is turned over (with rotation of 180 degrees). Thus,

⇒ △ϕ = nBAcos0 − (nBAcos180)

Let us simplify the expression.

△ϕ = nBA + nBA = 2nBA

= 2 × 500 × 0.2 × 4 × 10⁻⁴

⇒ △ϕ = 8×10⁻²

Therefore, the charge that flows through the area can be expressed by the following formula.

△Q = △ϕ/resistance = 8×10⁻²/500

=1.6 × 10⁻⁴C

=0.16 × 10⁻³C

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A closed coil has 500 turns across rectangular frame of area 4.0 cm2 with resistance of 500 ohms. The coil is plane perpendicular to a uniform magnetic field of 0.2wb/m2. Find amount of charge through coil if turned over. (180 degrees rotation)

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A closed coil has 500 turns across rectangular frame of area 4.0 cm2 with resistance of 500 ohms. The coil is plane perpendicular to a uniform magnetic field of 0.2wb/m2. Find amount of charge through coil if turned over. (180 degrees rotation)

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CBSE CLASS XII Related Questions

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2.Assertion (A) : All atoms have a net magnetic moment. Reason (R) : A current loop does not always behave as a magnetic dipole.

3.Photoemission of electrons occurs from a metal (\( \phi_0 = 1.96 \, \text{eV} \)) when light of frequency \( 6.4 \times 10^{14} \, \text{Hz} \) is incident on it. Calculate: Energy of a photon in the incident light, The maximum kinetic energy of the emitted electrons, and The stopping potential.

4.Draw a circuit diagram of a full-wave rectifier using p-n junction diodes. Explain its working and show the input-output waveforms.

5.The figure shows three point charges kept at the vertices of triangle ABC. The net electric field, due to this system of charges, at the midpoint M of base BC will be:

6.Assertion (A) : The mass of a nucleus is less than the sum of the masses of the constituent nucleons. Reason (R) : Energy is absorbed when the nucleons are bound together to form a nucleus.

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Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
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Assertion (A) : All atoms have a net magnetic moment. Reason (R) : A current loop does not always behave as a magnetic dipole.

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Draw a circuit diagram of a full-wave rectifier using p-n junction diodes. Explain its working and show the input-output waveforms.

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Assertion (A) : The mass of a nucleus is less than the sum of the masses of the constituent nucleons. Reason (R) : Energy is absorbed when the nucleons are bound together to form a nucleus.