A closed coil has 500 turns across rectangular frame of area 4.0 cm2 with resistance of 500 ohms.

As per the given parameters, the following can be understood:

The number of turns, n = 500
Area, A = 4cm² = 4 × 10⁻⁴m²
Resistance of closed coil, R = 500Ω
Magnetic field, B = 0.2wb/m²

Thus, in order to estimate the amount of charge flowing through the coil, we need to:

Magnetic flux can be expressed by the following formula,

ϕ = nBAcosθ

Where,

n = Number of turns
B = Magnetic field
A = Area
θ = Angle between Area vector and Magnetic Field

Assuming estimate the change in magnetic flux when it is turned over (with rotation of 180 degrees). Thus,

⇒ △ϕ = nBAcos0 − (nBAcos180)

Let us simplify the expression.

△ϕ = nBA + nBA = 2nBA

= 2 × 500 × 0.2 × 4 × 10⁻⁴

⇒ △ϕ = 8×10⁻²

Therefore, the charge that flows through the area can be expressed by the following formula.

△Q = △ϕ/resistance = 8×10⁻²/500

=1.6 × 10⁻⁴C

=0.16 × 10⁻³C

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A closed coil has 500 turns across rectangular frame of area 4.0 cm2 with resistance of 500 ohms. The coil is plane perpendicular to a uniform magnetic field of 0.2wb/m2. Find amount of charge through coil if turned over. (180 degrees rotation)

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Write any two features of nuclear forces.

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A light copper ring is freely suspended by a light string. A bar magnet is held horizontally with its length along the axis of the ring. The magnet is moved towards the ring with its N pole facing the loop. What will happen to the ring and its position? Explain.

3.
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Photoemission of electrons occurs from a metal (\( \phi_0 = 1.96 \, \text{eV} \)) when light of frequency \( 6.4 \times 10^{14} \, \text{Hz} \) is incident on it. Calculate: Energy of a photon in the incident light, The maximum kinetic energy of the emitted electrons, and The stopping potential.

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A closed coil has 500 turns across rectangular frame of area 4.0 cm2 with resistance of 500 ohms. The coil is plane perpendicular to a uniform magnetic field of 0.2wb/m2. Find amount of charge through coil if turned over. (180 degrees rotation)

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3.Two heaters rated as \((P_1,V)\) and \((P_2,V)\) are connected in series across a dc source of \(V/2\) volt. The power consumed by the combination will be –

4.Photoemission of electrons occurs from a metal (\( \phi_0 = 1.96 \, \text{eV} \)) when light of frequency \( 6.4 \times 10^{14} \, \text{Hz} \) is incident on it. Calculate: Energy of a photon in the incident light, The maximum kinetic energy of the emitted electrons, and The stopping potential.

5.Assertion (A) : The mass of a nucleus is less than the sum of the masses of the constituent nucleons. Reason (R) : Energy is absorbed when the nucleons are bound together to form a nucleus.

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SUBSCRIBE TO OUR NEWS LETTER

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Write any two features of nuclear forces.

2.
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4.
Photoemission of electrons occurs from a metal (\( \phi_0 = 1.96 \, \text{eV} \)) when light of frequency \( 6.4 \times 10^{14} \, \text{Hz} \) is incident on it. Calculate: Energy of a photon in the incident light, The maximum kinetic energy of the emitted electrons, and The stopping potential.

5.
Assertion (A) : The mass of a nucleus is less than the sum of the masses of the constituent nucleons. Reason (R) : Energy is absorbed when the nucleons are bound together to form a nucleus.