A closed coil has 500 turns across rectangular frame of area 4.0 cm2 with resistance of 500 ohms. The coil is plane perpendicular to a uniform magnetic field of 0.2wb/m2. Find amount of charge through coil if turned over. (180 degrees rotation)

As per the given parameters, the following can be understood:

  • The number of turns, n = 500
  • Area, A = 4cm2 = 4 × 10−4m2
  • Resistance of closed coil, R = 500Ω
  • Magnetic field, B = 0.2wb/m2

Thus, in order to estimate the amount of charge flowing through the coil, we need to:

Magnetic flux can be expressed by the following formula,

ϕ = nBAcosθ

Where,

  • n = Number of turns
  • B = Magnetic field
  • A = Area
  • θ = Angle between Area vector and Magnetic Field

Assuming estimate the change in magnetic flux when it is turned over (with rotation of 180 degrees). Thus,

⇒ △ϕ = nBAcos0 − (nBAcos180)

Let us simplify the expression.

△ϕ = nBA + nBA = 2nBA

= 2 × 500 × 0.2 × 4 × 10−4

⇒ △ϕ = 8×10−2

Therefore, the charge that flows through the area can be expressed by the following formula.

△Q = △ϕ/resistance = 8×10−2/500

=1.6 × 10−4C

=0.16 × 10−3C


Related Questions

  1. In An Arrangement Of Resistances, Find Effective Resistance Between Points A and B.
  2. What Is Effective Resistance?
  3. Find The Highest And Lowest Total Resistance Of A Combination Of Four Coils With Resistances 4 Ohms, 8 Ohms, 12 Ohms, 24 Ohms.
  4. What is Null Voltage?
  5. X and Y, which are two resistors, with resistances of 2 Ω and 3 Ω respectively are first connected in parallel and then in series. In both cases, the voltage that is supplied is 5 V. (i) Illustrate a circuit diagram to show the combination of resistors. (ii) Calculate the amount of voltage across 3 Ω resistor in the series combination of resistors.
  6. Draw An Electric Circuit With A Cell, Key, Ammeter, A Resistor (Series) Of 2 Ohm With a Combination Of Two Resistors (4 Ohm Each) In Parallel And A Voltmeter Across Parallel Combination.

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                        CBSE CLASS XII Previous Year Papers

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