A uniform magnetic field B is in a cylindrical region (radius 10cm). A 80cm uniform wire with resistance 4.0 ohms is bent into a square frame and placed on one side along a diameter of the cylindrical region.

Assuming Magnetic field increases at a constant rate 0.010T/s, what is the current induced in the frame?

Centripetal force can be expressed as the net force that acts on an object in order to maintain its movement in a circular motion. As per Newton’s first law of motion, until and unless an external force is applied to an object, it is till then going to continue to move along a straight path. This is the case of centripetal force. Centripetal force can be defined as the force which maintains an object unchanged while it is travelling in a circular way, although it is not a basic force.

  • Electromagnetic force (EMF) can be defined as the force that exists in the universe.
  • The electromagnetic force (EMF) can be expressed as the physical interaction occuring when electrically charged particles contact with each other.
  • Electromagnetic force (EMF) is usually a composite of every magnetic and electrical force acting between charged particles.
  • The electromagnetic force can both attract and repel.

Current

Thus, as per the question, the following can be deduced:

  • r = 10cm
  • R = 4Ω
  • dB/ dt = 0.010T

Hence,

dϕ/dt = dB/ dt A

E = dϕ/dt = dB/dt A

= 0.01(πr2/2) = 0.01×3.15×0.01/2 = 1.57×10−4

Therefore, i = E/R = 1.57×10-4/4 = 0.39×10−4 

3.9×10−4A


Related Questions

  1. A Closed Coil Has 500 Turns Across Rectangular Frame Of Area 4.0 Cm2 With Resistance Of 500 Ohms. The Coil Is Plane Perpendicular To A Uniform Magnetic Field Of 0.2wb/M2. Find Amount Of Charge Through Coil If Turned Over (180 Degrees Rotation).
  2. If R, C And L Are Fundamental Quantities In A Circuit Like Resistance, Capacitance And Inductance In W, Then Find Dimensional Formula For Resistance And Capacitance.
  3. In A Graph Between Current I And Voltage V, Find The Portion Corresponding To Negative Resistance.
  4. 1.0 M Rectangular Loop With A Sliding Connector Is In Uniform Magnetic Field 2t Perpendicular To Plane Of Loop. Resistance Is 2 Ohms. Two Resistances, 6 Ohms And 3 Ohms, Are Connected.
  5. Two Concentric Coplanar Circular Loops Of Wire (Resistance Per Unit Length 10 4 Ohms M-1) Have Diameters 0.2 M And 2 M. With Time-Varying Potential Difference Of (4+2.5t) Applied To Larger Loop, Find Current In Smaller One.
  6. Three Incandescent Bulbs (Each 100 W) Are Attached In Series. In Another Circuit, Three More Bulbs Of Same Wattage Are Attached Parallelly To An Equal Source.
  7. Two Identical Resistors With Resistances 15 Ohm Are Connected In Series And Parallel To A Battery Of 6 V. Calculate Ratio Of Power Consumed.
  8. For The Resistor Combination, Find The Equivalent Resistance Between M and N.
  9. A Circuit Consists Of A Battery Of 3 Cells (2 V Each), A Combination Of Three Resistors, 10 Ohm, 20 Ohm And 30 Ohm, Attached Parallelly, With Plug Key And Ammeter (In Series).

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CBSE CLASS XII Related Questions

  • 1.
    An electric field $\vec{E}$ is established across the ends of a cylindrical conductor of length L and area of cross-section A. Discuss how electrons attain an average velocity, independent of time. Hence, obtain a relation between current in the conductor and this ‘average velocity’ of electrons.


      • 2.
        Two metal spheres of radii $r_1$ and $r_2$ ($> r_1$) having charges $q_1$ and $q_2$ respectively kept in air, are brought in contact. Which of the following statements is not correct ?

          • The total charge of the two spheres is conserved.
          • Both spheres attain the same potential.
          • The final potential of the system equals $\frac{1}{4\pi\epsilon_0} \frac{(q_1 + q_2)}{(r_1 + r_2)}$
          • The final potential of the system equals $\frac{1}{4\pi\epsilon_0} \frac{(q_1 + q_2) (r_1 + r_2)}{r_1 r_2}$

        • 3.
          Derive an expression for the capacitance of a parallel plate capacitor of plate area A and plate separation d with air present between the plates.


            • 4.
              Read the following paragraph and answer the questions that follow.
              In an experiment with convex lens of focal length f, the screen is fixed at a distance D from the object. A student slowly moves the lens away from the object towards the screen and finds that she is able to form sharp image of the object for two positions of the lens. The distance between these two positions of the lens is d.


                • 5.
                  A charged particle $+q$ in an electric field $\vec{E}$ experiences a force in the direction of the electric field. As a result, its kinetic energy changes. Similarly, the charged particle also experiences a force when it moves in a magnetic field $\vec{B}$. But this magnetic force is perpendicular to both velocity $\vec{v}$ of the charged particle and the magnetic field $\vec{B}$, so it cannot change the kinetic energy of the charged particle. Consider two charged particles 1 and 2 of masses $m$ and $\frac{m}{2}$ having charges $-q$ and $+2q$ respectively. They are accelerated from rest through the same potential difference $V$ and acquire kinetic energy $K_1$ and $K_2$. Then they enter in a region of uniform magnetic field $\vec{B}$ perpendicular to their velocities.


                    • 6.
                      This ‘average velocity’ is found be few mm/s for currents in range of a few amperes. How then is current established almost the instant a circuit is closed ?

                        CBSE CLASS XII Previous Year Papers

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