1.0 m rectangular loop with a sliding connector is in uniform magnetic field 2t perpendicular to plane of loop. Resistance is 2 ohms. Determine force.

Now, as per the question, the external force needed to keep connector moving with constant velocity equals 2ms−1. With the given data, we have to determine force.

Accoding to the question, the following can be said:

Resistance of Connector = 2Ω
Given Magnetic Field = 2t
Other Two Resistances = 6Ω and 3Ω (velocity of moving connector is 2ms⁻¹)

Now, in order to estimate the induced emf generated in the circuit, E = vBl

⇒ E = 2 × 2 × 1

⇒ E = 4V

Thus, after assuming the two resistances 6Ω and 3Ω because they’re parallelly connected, then the resultant resistance should be 2Ω.

Therefore, the value of I (current) that flows via the circuit is, I = 4/2 + 2, giving the value of 1 Ampere (flowing in a clockwise direction). Now, in order to estimate the magnetic force on the connector by using the formula:

F = ilB

After replacing the values, we get,

F = 1 × 1 × 2

⇒ F = 2N, (Thus, the direction of force is towards left).

Thus, it can be said that if we want to move our connector with a constant velocity, a force of 2N is needed to be applied.

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1.0 m rectangular loop with a sliding connector is in uniform magnetic field 2t perpendicular to plane of loop. Resistance is 2 ohms. Two resistances, 6 ohms and 3 ohms, are connected.

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1.
A tank is filled with a liquid to a height of \( 12.5 \, \text{m} \). The apparent depth of a needle lying at the bottom of the tank is measured to be \( 9.0 \, \text{m} \). Calculate the speed of light in the liquid.

2.
Write the expression for the magnetic field due to a current element in vector form. Consider a 1 cm segment of a wire, centered at the origin, carrying a current of 10 A in positive x-direction. Calculate the magnetic field \( \mathbf{B} \) at a point \( (1 \, \text{m}, 1 \, \text{m}, 0) \).

5.
Photoemission of electrons occurs from a metal (\( \phi_0 = 1.96 \, \text{eV} \)) when light of frequency \( 6.4 \times 10^{14} \, \text{Hz} \) is incident on it. Calculate: Energy of a photon in the incident light, The maximum kinetic energy of the emitted electrons, and The stopping potential.

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1.0 m rectangular loop with a sliding connector is in uniform magnetic field 2t perpendicular to plane of loop. Resistance is 2 ohms. Two resistances, 6 ohms and 3 ohms, are connected.

Related Questions

CBSE CLASS XII Related Questions

1.A tank is filled with a liquid to a height of \( 12.5 \, \text{m} \). The apparent depth of a needle lying at the bottom of the tank is measured to be \( 9.0 \, \text{m} \). Calculate the speed of light in the liquid.

2.Write the expression for the magnetic field due to a current element in vector form. Consider a 1 cm segment of a wire, centered at the origin, carrying a current of 10 A in positive x-direction. Calculate the magnetic field \( \mathbf{B} \) at a point \( (1 \, \text{m}, 1 \, \text{m}, 0) \).

5.Photoemission of electrons occurs from a metal (\( \phi_0 = 1.96 \, \text{eV} \)) when light of frequency \( 6.4 \times 10^{14} \, \text{Hz} \) is incident on it. Calculate: Energy of a photon in the incident light, The maximum kinetic energy of the emitted electrons, and The stopping potential.

6. If Bohr’s quantization postulate (angular momentum \( = \frac{nh}{2\pi} \)) is a basic law of nature, it should be equally valid for the case of planetary motion also. Why, then, do we never speak of quantization of orbits of planets around the Sun? Explain.

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Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
A tank is filled with a liquid to a height of \( 12.5 \, \text{m} \). The apparent depth of a needle lying at the bottom of the tank is measured to be \( 9.0 \, \text{m} \). Calculate the speed of light in the liquid.

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Photoemission of electrons occurs from a metal (\( \phi_0 = 1.96 \, \text{eV} \)) when light of frequency \( 6.4 \times 10^{14} \, \text{Hz} \) is incident on it. Calculate: Energy of a photon in the incident light, The maximum kinetic energy of the emitted electrons, and The stopping potential.

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If Bohr’s quantization postulate (angular momentum \( = \frac{nh}{2\pi} \)) is a basic law of nature, it should be equally valid for the case of planetary motion also. Why, then, do we never speak of quantization of orbits of planets around the Sun? Explain.