In a graph between current i and voltage v, find the portion corresponding to negative resistance.

Considering that the temperature and physical conditions are constant, Ohm’s law claims that the flowing current via any conductor is directly proportional to the potential difference across the ends. Ohm’s law can be described mathematically as:

V = IR

Here,

  • V = Voltage
  • I = Current
  • R = Resistance

Solution of the Above Equation

Thus, Negative resistance = – (V/I) = [V/(– I)]

Therefore, the part is CD where resistance is negative.


Related Questions

  1. In An Arrangement Of Resistances, Find Effective Resistance Between Points A and B.
  2. What Is Effective Resistance?
  3. X and Y, which are two resistors, with resistances of 2 Ω and 3 Ω respectively are first connected in parallel and then in series. In both cases, the voltage that is supplied is 5 V. (i) Illustrate a circuit diagram to show the combination of resistors. (ii) Calculate the amount of voltage across 3 Ω resistor in the series combination of resistors.
  4. Find The Highest And Lowest Total Resistance Of A Combination Of Four Coils With Resistances 4 Ohms, 8 Ohms, 12 Ohms, 24 Ohms.
  5. What is Null Voltage?
  6. If R, C And L Are Fundamental Quantities In A Circuit Like Resistance, Capacitance And Inductance In W, Then Find Dimensional Formula For Resistance And Capacitance.
  7. Draw An Electric Circuit With A Cell, Key, Ammeter, A Resistor (Series) Of 2 Ohm With a Combination Of Two Resistors (4 Ohm Each) In Parallel And A Voltmeter Across Parallel Combination.

Do Check:

CBSE CLASS XII Related Questions

  • 1.
    Assertion (A) : All atoms have a net magnetic moment. Reason (R) : A current loop does not always behave as a magnetic dipole.

      • Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
      • Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
      • Assertion (A) is true, but Reason (R) is false.
      • Both Assertion (A) and Reason (R) are false.

    • 2.
      A square loop of side 0.50 m is placed in a uniform magnetic field of 0.4 T perpendicular to the plane of the loop. The loop is rotated through an angle of 60° in 0.2 s. The value of emf induced in the loop will be:

        • 5 V
        • 3.5 V
        • 2.5 V
        • Zero V

      • 3.
        Four independent waves are expressed as \[ (i)\; y_1=A_1\sin\omega t, \] \[ (ii)\; y_2=A_2\sin 2\omega t, \] \[ (iii)\; y_3=A_3\cos\omega t, \] \[ (iv)\; y_4=A_4\sin\left(\omega t+\frac{\pi}{3}\right) \] The interference between two of these waves is possible in

          • (i) and (iii) only
          • (iii) and (iv) only
          • (i), (iii) and (iv) only
          • All of them

        • 4.
          Two heaters rated as \((P_1,V)\) and \((P_2,V)\) are connected in series across a dc source of \(V/2\) volt. The power consumed by the combination will be –

            • \((P_1+P_2)\)
            • \(\dfrac{P_1+P_2}{2}\)
            • \(\dfrac{P_1P_2}{2(P_1+P_2)}\)
            • \(\dfrac{P_1P_2}{4(P_1+P_2)}\)

          • 5.
            If both the number of protons and the neutrons are conserved in each nuclear reaction, in what way is mass converted into energy (or vice versa) in a nuclear reaction? Explain.


              • 6.
                If Bohr’s quantization postulate (angular momentum \( = \frac{nh}{2\pi} \)) is a basic law of nature, it should be equally valid for the case of planetary motion also. Why, then, do we never speak of quantization of orbits of planets around the Sun? Explain.

                  CBSE CLASS XII Previous Year Papers

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