Determine the following from an electric circuit a) Effective resistance of 8 ohm resistors combination b) Flowing current via 4 ohm resistor

In order to determine the following from the electric circuit, we have to schematically represent it first.

Effective Resistance of 8-ohm Resistors Combination

There are two 8Ω resistors that are parallelly connected with one another, therefore their effective resistance equals:

⇒ 1/R_P = 1/8 + 1/R

⇒ 1/R_P = 1/4

⇒ R_P = 4Ω

The Total Resistance in the given Circuit

As per the question, the following can be shown:

⇒ R = 4Ω + R_P

⇒ R = 4Ω + 4Ω

⇒ R = 8Ω

Current Passing Via the Circuit

The current that passes through the circuit

⇒ I = V/R

⇒ I = 8/8

⇒ I = 1 A

Hence, the current that passes through a 4Ω resistor is 1A. Since 4Ω and R_p are connected in series, the same current flows through them.

Potential Difference across 4Ω resistor

⇒ V = I × R

⇒ V = 1 × 4

⇒ V = 4V

The Dissipated Power in a 4Ω Resistor

⇒ P = I²R

⇒ P = 1² × 4

⇒ P = 4 W

Difference, if any, in Ammeter Readings

Both A₁ and A₂ demonstrate the same reading due to the fact that current remains same in series combination.

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