In order to determine the following from the electric circuit, we have to schematically represent it first.

Effective Resistance of 8-ohm Resistors Combination
There are two 8Ω resistors that are parallelly connected with one another, therefore their effective resistance equals:
⇒ 1/RP = 1/8 + 1/R
⇒ 1/RP = 1/4
⇒ RP = 4Ω
The Total Resistance in the given Circuit
As per the question, the following can be shown:
⇒ R = 4Ω + RP
⇒ R = 4Ω + 4Ω
⇒ R = 8Ω
Current Passing Via the Circuit
The current that passes through the circuit
⇒ I = V/R
⇒ I = 8/8
⇒ I = 1 A
Hence, the current that passes through a 4Ω resistor is 1A. Since 4Ω and Rp are connected in series, the same current flows through them.
Potential Difference across 4Ω resistor
⇒ V = I × R
⇒ V = 1 × 4
⇒ V = 4V
The Dissipated Power in a 4Ω Resistor
⇒ P = I2R
⇒ P = 12 × 4
⇒ P = 4 W
Difference, if any, in Ammeter Readings
Both A1 and A2 demonstrate the same reading due to the fact that current remains same in series combination.
Related Questions
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