Determine the following in the electric circuit given below.

As per the given question, the following can be determined:

Circuit

Effective resistance of two 8 Ω resistors in combination 

⇒ R = \(\frac{R_1 R_2}{R_1 R_2} = \frac{8\ \times \ 8}{8\ + \ 8}\) = 4 Ω

Current that flows through 4Ω resistor

 \(I = \frac{V}{R}= \frac{8}{4 + \frac{8 \times 8}{8+8}}\)

Potential difference across 4Ω resistance

⇒ V = IR = 1 × 4 = 4V

Disspated Power in 4 Ω resistor

⇒ P = I2R = 12 × 4 = 4W

Difference, if any, in ammeter readings

There is zero difference as because no current is seen to flow through the elements in a series circuit.

Check More: Class 12 Physics Notes


Related Questions

  1. In A Graph Between Current I And Voltage V, Find The Portion Corresponding To Negative Resistance.
  2. A Fixed Amplitude V0 And AC Voltage Source Of Variable Angular Frequency Are Joined In Series With Capacitance C And An Electric Bulb Of Resistance R (Inductance Zero). When Variable Angular Frequency Is Increased.
  3. A Closed Coil Has 500 Turns Across Rectangular Frame Of Area 4.0 Cm2 With Resistance Of 500 Ohms. The Coil Is Plane Perpendicular To A Uniform Magnetic Field Of 0.2wb/M2. Find Amount Of Charge Through Coil If Turned Over (180 Degrees Rotation).
  4. Two Identical Resistors With Resistances 15 Ohm Are Connected In Series And Parallel To A Battery Of 6 V. Calculate Ratio Of Power Consumed.
  5. Two Concentric Coplanar Circular Loops Of Wire (Resistance Per Unit Length 10 4 Ohms M-1) Have Diameters 0.2 M And 2 M. With Time-Varying Potential Difference Of (4+2.5t) Applied To Larger Loop, Find Current In Smaller One.
  6. 1.0 M Rectangular Loop With A Sliding Connector Is In Uniform Magnetic Field 2t Perpendicular To Plane Of Loop. Resistance Is 2 Ohms. Two Resistances, 6 Ohms And 3 Ohms, Are Connected.
  7. Resistance In Meter Bridge’s Two Arms Are 5 Ohms And R Ohms. When Resistance R Is Shunted With Equal Resistance, New Balance Point Becomes 1.6l1. Calculate R.
  8. If R, C And L Are Fundamental Quantities In A Circuit Like Resistance, Capacitance And Inductance In W, Then Find Dimensional Formula For Resistance And Capacitance.
  9. Two Copper Wires, Of 1 M And 9 M Respectively, Have Same Resistance. Find Their Diameters In Ratio.
  10. Three Incandescent Bulbs (Each 100 W) Are Attached In Series. In Another Circuit, Three More Bulbs Of Same Wattage Are Attached Parallelly To An Equal Source.
  11. A Circuit Consists Of A Battery Of 3 Cells (2 V Each), A Combination Of Three Resistors, 10 Ohm, 20 Ohm And 30 Ohm, Attached Parallelly, With Plug Key And Ammeter (In Series).
  12. For The Resistor Combination, Find The Equivalent Resistance Between M and N.

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CBSE CLASS XII Related Questions

  • 1.
    The figure shows three point charges kept at the vertices of triangle ABC. The net electric field, due to this system of charges, at the midpoint M of base BC will be:

      • \( \frac{q}{4 \pi \epsilon_0 l^2} \) pointing along MA
      • \( \frac{q}{\pi \epsilon_0 l^2} \) pointing along AM
      • \( \frac{q}{2 \pi \epsilon_0 l^2} \) pointing along AM
      • Zero

    • 2.
      Photoemission of electrons occurs from a metal (\( \phi_0 = 1.96 \, \text{eV} \)) when light of frequency \( 6.4 \times 10^{14} \, \text{Hz} \) is incident on it. Calculate: Energy of a photon in the incident light, The maximum kinetic energy of the emitted electrons, and The stopping potential.


        • 3.
          Draw the number of scattered particles versus the scattering angle graph for scattering of alpha particles by a thin foil. Write two important conclusions that can be drawn from this plot.


            • 4.
              If Bohr’s quantization postulate (angular momentum \( = \frac{nh}{2\pi} \)) is a basic law of nature, it should be equally valid for the case of planetary motion also. Why, then, do we never speak of quantization of orbits of planets around the Sun? Explain.


                • 5.
                  Two small identical metallic balls having charges \( q \) and \( -2q \) are kept far at a separation \( r \). They are brought in contact and then separated at distance \( \frac{r}{2} \). Compared to the initial force \( F \), they will now:

                    • attract with a force \( \frac{F}{2} \)
                    • repel with a force \( \frac{F}{2} \)
                    • repel with a force \( F \)
                    • attract with a force \( F \)

                  • 6.
                    Write the expression for the magnetic field due to a current element in vector form. Consider a 1 cm segment of a wire, centered at the origin, carrying a current of 10 A in positive x-direction. Calculate the magnetic field \( \mathbf{B} \) at a point \( (1 \, \text{m}, 1 \, \text{m}, 0) \).

                      CBSE CLASS XII Previous Year Papers

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