An inductor of inductance L= 400mH and resistors R1=2\(\Omega\) and R2=2\(\Omega\) are connected to a battery of EMF 12V . The internal resistance of the battery is negligible. The switch S is closed at t=0. The potential drop across L as a function of tim

The voltage across the inductor in a circuit is directly proportional to the rate of flow of current through the inductor.

For this firstly calculate the current flowing through the branch containing L and R2. Then differentiate current I with respect to time t.

Given: L = 400mH

R1 = 2Ω

R2 = 2Ω

E = 12V

In the branch containing L and R2, I = E/R2 1−e−R2t/L

Differentiating I with respect to t:

dI/dt = ER2e−R2t/L. R2/L

= E/Le−R2t/L

Therefore, VL = L dI/dt = Ee−R2t/L

= 12e−5tV

Then the potential drop across L as a function of time is 12e−5tV.


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CBSE CLASS XII Related Questions

  • 1.
    Consider the nuclear reaction \( X \to Y + Z \). Let \( M_x \), \( M_y \), and \( M_z \) be the masses of the three nuclei X, Y, and Z respectively. Then which of the following relations hold true?

      • \( (M_x - M_z)<M_y \)
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    • 2.
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        • 3.

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            • 4.
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                • 5.

                  (I) The real image of an object placed between $f$ and $2f$ from a convex lens can be seen on a screen placed at the image location. If the screen is removed, is the image still there? Explain.

                  (II) Plane and convex mirrors produce virtual images of objects. Can they produce real images under some circumstances? Explain.


                    • 6.

                      The number of free electrons per unit volume ($\text{m}^3$) in a wire made of copper (resistivity $1.72 \times 10^{-8}\,\Omega\,\text{m}$) is $8.5 \times 10^{28}$. Calculate the average number of collisions made by an electron in one second when an electric field is maintained in the wire.

                        CBSE CLASS XII Previous Year Papers

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