In order to determine the given values,
RMS value of the voltage
\(V_{rms}\ =\ \frac{V_m}{sqrt2}\)
Replacing the values in the equation, we can obtain:
\(V_{rms}\ =\ \frac{200}{sqrt2} =\ 141.4 V\)
RMS value of the current
\(I_{rms}\ =\ {V_{rms} \over {R}}\)
Now, upon substitution,
\(I_{rms}\ =\ {141.4 \over 10} = 14.14\ A\)
Power dissipated as heat in Watt
\(P = V_{rms}I_{rms}cos{\theta}\)
On value substitution,
\(P = 141.4 {\times}14.14 = 1999.6 \ W\)
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