A current of 1 ampere flows in a series circuit containing an electric lamp and a conductor of 5 Ω when connected to a 10 V battery. Calculate the resistance of the electric lamp. Now if a resistance of 10 Ω is connected in parallel with this series combination, what change (if any) in current flowing through 5 Ω conductor and potential difference across the lamp will take place? Give reason.

Now if the resistance of 10 Ω is connected in parallel with this series combination, what change (if any) in the current flowing through the 5 Ω conductor and potential difference across the lamp will take place? Give reason.

Let R₁ be the resistance of the electric lamp and R₂ the resistance of a conductor.

In series, the total resistance R = R1 + R2 = 5 + R1

Current (I) = 1 A

Voltage (V) = 10 V

Using Ohm’s law

I = V/R

1 = 10/(5+R)

5 + R = 10

R = 5Ω

Now, a 10 Ω resistance is connected in parallel with the series combination. Therefore, the total resistance of the circuit is calculated as –

1/R_p = 1/(R1 + 5) + 1/10

Rp = 5Ω

Therefore, the current flowing in the circuit is equal to I = V/R

I = 10/5

I = 2A

Read More: Ohm’s Law and its Limitations

Related Questions

Read More:

Ohm’s Law – Important Topics
Current Electricity	Difference between air conditioning and refrigeration	Internal resistance formula
Wheatstone Bridge	Relation between kva and kw	Combination of Resistors
Potentiometer	Cells, emf, Internal Resistance	Unit of Specific Resistance
Static Electricity	Difference between AC and DC	Unit of Current
Permittivity And Permeability	Power Of Alternating Current	Ampere
Electric Dipole	Difference between kva and kw	Resistance Formula
Meter Bridge	Difference between RTD and thermocouple	Electromotive Force
Kirchhoff’s Rules	Resistivity Temperature Dependence	Current Density
Types of Current	Relation between resistance and length	Types of Resistors
Derivation of Drift Velocity	Difference Between Primary Cell and Secondary Cell	Electrical Formula
Drift Velocity	Difference between emf and voltage	Resistor Colour Codes
Resistivity formula	Relation between power and resistance	Current density formula
Carbon Resistor	Difference between earth and neutral	Uses of Resistor
Cells in Series and in Parallel	Differences Between Acceleration and Velocity	Circuit Diagram
Power transformers	NCERT Solutions Current Electricity	Voltage divider formula

CBSE CLASS XII Related Questions

1.
A charged particle $+q$ in an electric field $\vec{E}$ experiences a force in the direction of the electric field. As a result, its kinetic energy changes. Similarly, the charged particle also experiences a force when it moves in a magnetic field $\vec{B}$. But this magnetic force is perpendicular to both velocity $\vec{v}$ of the charged particle and the magnetic field $\vec{B}$, so it cannot change the kinetic energy of the charged particle. Consider two charged particles 1 and 2 of masses $m$ and $\frac{m}{2}$ having charges $-q$ and $+2q$ respectively. They are accelerated from rest through the same potential difference $V$ and acquire kinetic energy $K_1$ and $K_2$. Then they enter in a region of uniform magnetic field $\vec{B}$ perpendicular to their velocities.

2.
A student sets up the circuit as shown in the figure to find the value of unknown resistance X and records a set of readings of the voltmeter and the ammeter by using the rheostat.

3.
Write two advantages of reflecting telescope over refracting telescope.

View Solution

4.
Read the following paragraph and answer the questions that follow.
In an experiment with convex lens of focal length f, the screen is fixed at a distance D from the object. A student slowly moves the lens away from the object towards the screen and finds that she is able to form sharp image of the object for two positions of the lens. The distance between these two positions of the lens is d.

5.
With the help of a labelled diagram, explain the principle, construction and working of an a.c. generator.

View Solution

6.
Read the following paragraph and answer the questions that follow.
A p-type or n-type semiconductor can be converted into a p-n junction by doping it with suitable impurity. The motion of majority charge carriers causes diffusion current across the junction while the barrier electric field causes motion of minority carriers for drift current. In case of unbiased diode, the diffusion and drift currents are equal. This equilibrium is disturbed by the biasing batteries. Diodes, therefore, allow currents in one direction. This property of diode is used in making rectifiers.

A current of 1 ampere flows in a series circuit containing an electric lamp and a conductor of 5 Ohm when connected to a 10 V battery. Calculate the resistance of the electric lamp.

Now if the resistance of 10 Ω is connected in parallel with this series combination, what change (if any) in the current flowing through the 5 Ω conductor and potential difference across the lamp will take place? Give reason.

Related Questions

CBSE CLASS XII Related Questions

2.
A student sets up the circuit as shown in the figure to find the value of unknown resistance X and records a set of readings of the voltmeter and the ammeter by using the rheostat.

3.
Write two advantages of reflecting telescope over refracting telescope.

5.
With the help of a labelled diagram, explain the principle, construction and working of an a.c. generator.

Similar Physics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

A current of 1 ampere flows in a series circuit containing an electric lamp and a conductor of 5 Ohm when connected to a 10 V battery. Calculate the resistance of the electric lamp.

Now if the resistance of 10 Ω is connected in parallel with this series combination, what change (if any) in the current flowing through the 5 Ω conductor and potential difference across the lamp will take place? Give reason.

Related Questions

CBSE CLASS XII Related Questions

2.A student sets up the circuit as shown in the figure to find the value of unknown resistance X and records a set of readings of the voltmeter and the ammeter by using the rheostat.

3.Write two advantages of reflecting telescope over refracting telescope.

5.With the help of a labelled diagram, explain the principle, construction and working of an a.c. generator.

Similar Physics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

2.
A student sets up the circuit as shown in the figure to find the value of unknown resistance X and records a set of readings of the voltmeter and the ammeter by using the rheostat.

3.
Write two advantages of reflecting telescope over refracting telescope.

5.
With the help of a labelled diagram, explain the principle, construction and working of an a.c. generator.